bài 1:Tính hợp lí
a, (247.514.1813.4517 ):(18030)
b,46.95+69.120phần 84.312-611
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b: \(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
\(=\frac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\frac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}=\frac23\cdot\frac65=\frac{12}{15}=\frac45\)
c: \(\frac{7\cdot28^8+2^4\cdot14^{10}}{4^4\cdot14^9-70\cdot16^3\cdot49^4}\)
\(=\frac{7\cdot7^8\cdot2^{16}+2^4\cdot2^{10}\cdot7^{10}}{2^8\cdot2^9\cdot7^9-2\cdot5\cdot7\cdot2^{12}\cdot7^8}=\frac{7^9\cdot2^{14}\left(2^2+7\right)}{2^{13}\cdot7^8\left(2^4-5\cdot7\right)}=\frac{7\cdot2\cdot\left(4+7\right)}{16-35}=\frac{14\cdot11}{-19}=\frac{-154}{19}\)
a) \(\left(29,42+20,58\right)-\left(34,23+25,77\right)\)
\(=50-60=-10\)
b) \(-\left(212,49+87,51\right)+99,9\)
\(=-300+99,9=-200,1\)
A)29.42+20.58−34.23+(−25.77)29.42+20.58−34.23+(−25.77)
=29.42+20.58−34.23−25.77
=29.42+20.58−34.23−25.77
=(29.42+20.58)−(34.23+25.77)
=(29.42+20.58)−(34.23+25.77)
=50−60=50−60
=−10=−10
B).(−212.49)−(87.51−99.9)(−212.49)−(87.51−99.9)
=−212.49−87.51+99.9
=−212.49−87.51+99.9
=−(212.49+87.51)+99.9
=−(212.49+87.51)+99.9
=−300+99.9=−300+99.9
=−(300−99.9)=−(300−99.9)
=−200.1
a) 80-(4x5^2-3x2^3)
= 80-(4x25-3x8)
= 80-(100-24)
= 80-76
= 4
b) 125-2x[56-48:(15-7)]
= 125-2x[56-48:8]
= 125-2x[56-6]
=125-2x50
=125-100
=25.