\(\frac{41\times66+34\times41}{3+7+11+...+79}\)

= \(\frac{41\times\left(66+34\right)}{[\left(79-3\right):4+1]\times\left(79+3\right):2}\)

= \(\frac{41\times100}{20\times41}\)

= \(5\)

cảm ơn bạn nha

Bài 1 :

a) 37581 - 9999 = 37581 - 10000 - 1 = 27581 - 1 = 27580

k cho mình nha bạn ! 

a)37581-9999=37581-(9999+1-1)=37581-(10000+1)=37581-10000-1=27581+1=27582

Mik sửa lại đề một chút nha :

\(\frac{44.66+34.44}{3+7+11+...+79}\)

Ta có :

\(\frac{44.66+34.44}{3+7+11+...+79}\)

\(=\frac{44\left(66+34\right)}{820}\)

\(=\frac{4400}{820}\)

\(=\frac{220}{41}\)

Vậy \(A=\frac{220}{41}\)

Đặt B = 44 x 66 + 34 x 44

        C = 3 + 7 + 11 + ... + 79

Ta có:

B = 44 x 66 + 34 x 44

    = 44 x ( 66 + 34 )

    = 44 x 100

    = 4400

C = 3 + 7 + 11 + ... + 79

C = 79 + 75 + 71 + ... + 3

C = ( 3 + 79 ) + ( 7 + 75 ) + ( 11 + 71 ) + ... + ( 79 + 3 ) ( 10 cặp số )

C = 82 + 82 + 82 + ... + 82 ( 10 số 82 )

C = 10 x 82

C = 820

\(\Rightarrow A=\frac{4400}{820}=\frac{220}{41}\)

Mk có sửa đề chút nhé

a) 2/9 - (1/20 + 2/9)

= 2/9 - 1/20 - 2/9

= (2/9 - 2/9) - 1/20

= 0 - 1/20

= -1/20

b) -3/14 + 2/13 + (-25/14) + (-15/13)

= (-3/14 - 25/14) + (2/13 - 15/13)

= -2 - 1

= -3

c) -3/11 + 11/8 - 3/8 + (-8/11)

= (-3/11 - 8/11) + (11/8 - 3/8)

= -1 + 1

= 0

d) 3/8 + (-1/4) - (7/12 - 1/6)

= 1/8 - 5/12

= -7/24

e) (1/3 + 12/67 + 13/41) - (79/67 - 28/41)

= 1/3 + 12/67 + 13/41 - 79/67 + 28/41

= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)

= 1/3 - 1 + 1

= 1/3

\(a\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)

\(=\frac{31}{23}-\frac{7}{23}-\frac{8}{23}\)

\(=\frac{16}{23}\)

Hot

tốt

!

a)\(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)=\frac{31}{23}-\frac{8}{23}+\frac{7}{23}=1+\frac{7}{23}=1\frac{7}{23}\)

b)\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)=\left(\frac{13}{41}+\frac{28}{41}\right)+\left(\frac{79}{67}-\frac{12}{67}\right)-\frac{1}{3}=1+1-\frac{1}{3}\)

\(=2-\frac{1}{3}=\frac{5}{3}\)