Thấy cây mà chẳng thấy rừng

Bói ra ma, quét nhà ra rác.

Thầy bói nói dối ăn tiền.

Chín người mười ý.

Cãi chày, cãi cối.

cái này  là môn văn mà bạn

bài nào?

:v

hi

spite of a lot of people around, we managed to talk seriously

the heavy bag, she managed to carry it herself

of his mother's refusion

not being very nice, the car serves its purpose

spite of not having much money, he wants to buy a car

1 plays

2 swimming

3 plays

4 painting

5 climbing

6 walking

7 because

8 take

9 favorite

10 easy

1. plays

2. swimming

3. plays

4. painting

5. climbing

6. walking

7. because

8. clothes

9. favourite

10. easy

Bài 3:

\(2x^4-7x^3+17x^2-20x+14\)

\(=2x^4-4x^3+4x^2-3x^3+6x^2-6x+7x^2-14x+14\)

\(=\left(x^2-2x+2\right)\left(2x^2-3x+7\right)\)

Bài 2:

\(x^4-2x^3+2x^2-2x+a\)

\(=x^4-2x^3+x^2+x^2-2x+1+a-1\)

\(=\left(x^2-2x+1\right)\left(x^2+1\right)+a-1\)

Để \(x^4-2x^3+2x^2-2x+a\) chia hết cho x^2-2x+1 thì a-1=0

=>a=1

=>b=0; c=1

Bài 10:

a: \(\left(x^2+4x+8\right)^2+3x^{}\left(x^2+4x+8\right)+2x^2\)

\(=\left(x^2+4x+8\right)^2+2x\left(x^2+4x+8\right)+\left(x^2+x+8\right)x+2x^2\)

\(=\left(x^2+4x+8+2x\right)\left(x^2+4x+8+x\right)\)

\(=\left(x+4\right)\left(x+2\right)\left(x^2+5x+8\right)\)

b: abc-(ab+ac+bc)+(a+b+c)-1

=abc-ab-ac-bc+a+b+c-1

=ab(c-1)-a(c-1)-b(c-1)+(c-1)

=(c-1)(ab-a-b+1)

=(c-1)(b-1)(a-1)

Bài 8:

a: \(x^4+4\)

\(=x^4+4x^2+4-4x^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2=\left(x^2+2+2x\right)\left(x^2+2-2x\right)\)

b: \(4x^8+1=4x^8+4x^4+1-4x^4\)

\(=\left(2x^4+1\right)^2-\left(2x^2\right)^2\)

\(=\left(2x^4+1-2x^2\right)\left(2x^4+1+2x^2\right)\)

c: \(81x^4+4\)

\(=81x^4+36x^2+4-36x^2\)

\(=\left(9x^2+2\right)^2-\left(6x\right)^2\)

\(=\left(9x^2+2-6x\right)\left(9x^2+2+6x\right)\)

d: \(64x^4+y^4\)

\(=64x^4+16x^2y^2+y^4-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2+y^2-4xy\right)\left(8x^2+y^2+4xy\right)\)

e: \(\left(x^2-8\right)^2+36\)

\(=x^2-16x^2+64+36\)

\(=x^2+20x^2+100-36x^2\)

\(=\left(x^2+10\right)^2-\left(6x\right)^2\)

\(=\left(x^2+10-6x\right)\left(x^2+10+6x\right)\)

f: \(\left(2x^2-4\right)_{}^2+9\)

\(=4x^4-16x^2+16+9\)

\(=4x^4-16x^2+25\)

\(=4x^4+20x^2+25-36x^2\)

\(=\left(2x^2+5\right)^2-\left(6x\right)^2=\left(2x^2+5-6x\right)\left(2x^2+5+6x\right)\)

a, 1

b, 1 hoặc 2

c, 10

4/9>3/9?

2/10<3/10

3/5=6/10

Chúc em học giỏi