Tìm y:
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a: \(y\times4\frac{7}{12}=6\frac14\)
=>\(y\times\frac{55}{12}=\frac{25}{4}\)
=>\(y=\frac{25}{4}:\frac{55}{12}=\frac{25}{4}\times\frac{12}{55}=\frac{3\times5}{11}=\frac{15}{11}\)
b: \(y:3\frac78=5\frac12\)
=>\(y:\frac{31}{8}=\frac{11}{2}\)
=>\(y=\frac{11}{2}\times\frac{31}{8}=\frac{341}{16}\)
c: \(6\frac17:y=5\frac25\)
=>\(\frac{43}{7}:y=\frac{27}{5}\)
=>\(y=\frac{43}{7}:\frac{27}{5}=\frac{43}{7}\times\frac{5}{27}=\frac{215}{189}\)
a, \(y=\dfrac{7}{11}-\dfrac{5}{14}=\dfrac{98-55}{154}=\dfrac{43}{154}\)
b, \(y=\dfrac{8}{9}.\dfrac{4}{7}=\dfrac{32}{63}\)
a)3/4 × (5/6 + 7/8)
=3/4 × 41/24
=41/32
b)3/5 × y=4/7
y=4/7:3/5
y=20/21
5 x y - 7 = 8 + 2 x y
5 x y - 7 - 2 x y = 8
( 5 x y - 2 x y ) - 7 = 8
3 x y - 7 = 8
3 x y = 8 + 7
3 x y = 15
y = 15 : 3
y = 5
Vậy ...
\(5\times y-7=8+2\times y\)
\(5\times y-7-2\times y=8\)
\(\left(5\times y-2\times y\right)-7=8\)
\(3\times y-7=8\)
\(3\times y=8+7\)
\(3\times y=15\)
\(y=15\div3\)
\(y=5\)
`7/2 : y= 3/8 + 5/4`
`=> 7/2 : y= 3/8 +10/8`
`=> 7/2 : y=13/8`
`=> y= 7/2 : 13/8`
`=> y= 7/2 xx 8/13`
`=> y= 28/13`
\(\frac{4}{7}+y=\frac{5}{8}-\frac{1}{4}\)
\(\frac{4}{7}+y=\frac{3}{8}\)
\(y=\frac{3}{8}-\frac{4}{7}\)
\(y=-\frac{11}{56}\)
hình như bạn ra sai đề rồi
\(\frac{4}{7}+y=\frac{3}{8}\)
\(y=\frac{3}{8}-\frac{4}{7}=-\frac{11}{56}\)
a)
y : 5 + 27 = 4 × 8
y : 5 + 27 = 32
y : 5 = 32 – 27
y : 5 = 5
y = 5 × 5
y = 25
b)
12 – 7 < y < 12 – 4
5 < y < 8
y = 6; 7
a: Để y là số nguyên thì 4x-8⋮2x+5
=>4x+10-18⋮2x+5
=>-18⋮2x+5
mà 2x+5 lẻ
nên 2x+5∈{1;-1;3;-3;9;-9}
=>2x∈{-4;-6;-2;-8;4;-14}
=>x∈{-2;-3;-1;-4;2;-7}
\(y=\frac{4x-8}{2x+5}=\frac{4x+10-18}{2x+5}=2-\frac{18}{2x+5}\)
Khi x=-2 thì \(y=2-\frac{18}{2x+5}=2-\frac{18}{2\cdot\left(-2\right)+5}=2-\frac{18}{1}=2-18=-16\)
Khi x=-3 thì \(y=2-\frac{18}{2x+5}=2-\frac{18}{2\cdot\left(-3\right)+5}=2-\frac{18}{-1}=2+18=20\)
Khi x=-1 thì \(y=2-\frac{18}{2x+5}=2-\frac{18}{2\cdot\left(-1\right)+5}=2-\frac{18}{3}=2-6=-4\)
Khi x=-4 thì \(y=2-\frac{18}{2x+5}=2-\frac{18}{2\cdot\left(-4\right)+5}=2-\frac{18}{-3}=2+6=8\)
Khi x=2 thì \(y=2-\frac{18}{2x+5}=2-\frac{18}{2\cdot2+5}=2-\frac{18}{9}=2-2=0\)
Khi x=-7 thì \(y=2-\frac{18}{2x+5}=2-\frac{18}{2\cdot\left(-7\right)+5}=2-\frac{18}{-9}=2+2=4\)
b: xy-3x+2y=7
=>x(y-3)+2y-6=1
=>(x+2)(y-3)=1
=>(x+2;y-3)∈{(1;1);(-1;-1)}
=>(x;y)∈{(-1;4);(-3;2)}