Tìm số nguyên x, biết:
a)
b)
c)
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Bài 4:
a: |x-2|=0
=>x-2=0
=>x=2
b: |x+3|=1
=>\(\left[\begin{array}{l}x+3=1\\ x+3=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=1-3=-2\\ x=-1-3=-4\end{array}\right.\)
c: \(-3\left|4-x\right|=-9\)
=>|4-x|=3
=>|x-4|=3
=>\(\left[\begin{array}{l}x-4=3\\ x-4=-3\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=1\end{array}\right.\)
d: |2x+1|=-2
mà -2<0<=|2x+1|
nên x∈∅
Bài 5:
a: \(\left(x+3\right)^2=36\)
=>\(\left[\begin{array}{l}x+3=6\\ x+3=-6\end{array}\right.\Rightarrow\left[\begin{array}{l}x=6-3=3\\ x=-6-3=-9\end{array}\right.\)
b: \(\left(x+5\right)^2=100\)
=>\(\left[\begin{array}{l}x+5=10\\ x+5=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x=10-5=5\\ x=-10-5=-15\end{array}\right.\)
c: \(\left(2x-4\right)^2=0\)
=>2x-4=0
=>2x=4
=>x=2
d: \(\left(x-1\right)^3=27\)
=>x-1=3
=>x=4
a: =>x-3=9
=>x=12
b: =>10-x=-26
=>x=36
c: =>x:4-1=2
=>x:4=3
=>x=12
d: =>x^2=4
=>x=2 hoặc x=-2
e: =>(x-2)^2=100
=>x-2=10 hoặc x-2=-10
=>x=12 hoặc x=-8
b: \(\Leftrightarrow x+8\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{-7;-9;-3;-13\right\}\)
a) x - 17 = 23
x = 23 + 17
x = 40
Vậy x = 40
b) 2 ( x - 1 ) = 7 + ( - 3 )
x - 1 = 4 : 2
x = 2 + 1
x = 3
Vậy x = 3
c) 4 ( x + 3 )^3 - 7 = 101
4 ( x + 3 )^3 = ( 101 + 7 ) : 4
( x + 3 )^3 = 3^3
⇒ x + 3 = 3
⇒ x = 0
Vậy x = 0
d) 2^{ x+ 1 } . 3 + 15 = 39
2^{ x + 1 } = ( 39 - 15 ) : 3
2^{ x + 1 } = 2{ 2 + 1 }
⇒ x + 1 = 2 + 1
⇒ x = 2
Vậy x = 2
a: x/2=-5/y
=>xy=-10
=>\(\left(x,y\right)\in\left\{\left(1;-10\right);\left(-10;1\right);\left(-1;10\right);\left(10;-1\right);\left(2;-5\right);\left(-5;2\right);\left(-2;5\right);\left(5;-2\right)\right\}\)
b: =>xy=12
mà x>y>0
nên \(\left(x,y\right)\in\left\{\left(12;1\right);\left(6;2\right);\left(4;3\right)\right\}\)
c: =>(x-1)(y+1)=3
=>\(\left(x-1;y+1\right)\in\left\{\left(1;3\right);\left(3;1\right);\left(-1;-3\right);\left(-3;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(2;2\right);\left(4;0\right);\left(0;-4\right);\left(-2;-2\right)\right\}\)
d: =>y(x+2)=5
=>\(\left(x+2;y\right)\in\left\{\left(1;5\right);\left(5;1\right);\left(-1;-5\right);\left(-5;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(-1;5\right);\left(3;1\right);\left(-3;-5\right);\left(-7;-1\right)\right\}\)
a: Sửa đề: -x+20=-(-25)-8
=>-x+20=25-8
=>20-x=17
=>x=20-17
=>x=3
b: x+(-45)=-62+17
=>x-45=-45
=>x=-45+45
=>x=0
a) Ta có x 3 = 2 6 => 6.x = 3.2 => x =1
b) Ta có x 4 = 1 − 2 => -2.x = 1.4 =>x = -2
c) 3 − 9 = 3 x => x= -9