4^40=[2^2]^20=2^40

vậy 2^81>4^40

25^10=[5^2]^10=5^20=5^5.5^15

105^5=21^5.5^5

vì 5^5.5^5<21^5.5^5 nên 25^10<105^5

Ta có

kết quả là:

2^81 > 4^40

105^5 > 25^5

nha bn

1/2×(2×x-3)+105/2=-137/2

1/2×(2×x-3)=-137/2-105/2

1/2×(2×x-3)=-242/2

2×x-3=-242/2:1/2

2×x-3=-242

2.x=(-242)+3

2.x=239

x=239:2

x=239/2

A,-12×25-25×75-25×13

=[(-12)-75-13].25

=(-100).25

-2500

B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5

=(-35)-(-25)+(-13)

=-23

C,-354+265-156+125

=[(-354)-156]+(265+125)

=(-510)+277

=-233

D,-74+40-50+16-35

=(-74)+40+(-50)+16+(-35)

=[(-74)+(-35)]+[40+(-50)+16]

=(-109)+26

=-83

E,-2/3×4/5+-4/5×4/3-0,125

=-2/3.4/5+4/5.(-4/3)-0,125

=4/5.[-2/3+(-4/3)]-0,125

=4/5.(-2)-0,125

=-8/5-0,125

=(-1,6)+(-0,125)

=-1,725

-2/3×4/5+ -4/5×4/3-0,125

Giúp e nốt ik ạ

a) 2018 + (– 3)  <  2018

          b) (– 105) + 5 > (– 105)

          c) (– 59) + (– 10) < (–59)

a: =-36-329-71+136-2021

=100-400-2021

=-300-2021

=-2321

vãi l

a) 58.75+58.50-58.25

=58.(75+50-25)

=58.100

=5800

b) \(20:2^2-5^9:5^8\)

\(20:4-5\)

\(5-5=0\)

c)\(\left(5^{19}:5^{17}-4\right):7\)

\(\left(5^2-4\right):7\)

\(\left(25-4\right):7\)

\(21:7\)

=\(3\)

d) \(84:4+3^9:3^7+5^0\)

\(=21+3^2+1\)

\(=21+9+1\)

\(30+1=31\)

e) \(295-\left(31-2^2.5\right)^2\)

\(295-\left(31-4.5\right)^2\)

\(295-\left(31-20\right)^2\)

\(295-\left(11\right)^2\)

\(295-121\)

\(=174\)

f) \(11^{25}:11^{23}-3^5:\left(1^{10}\right)+2^3-60\)

\(11^2-243:1+8-60\)

\(121-243+8-60\)

\(-122+8-60\)

\(-114-60\)

\(=-174\)

a) 1763 + (–2) = 1763 – 2 = 1761.

Vậy 1763 + (–2) < 1763.

b) (–105) + 5 = –(105 – 5) = –100.

So sánh –100 và –105:

|–100| = 100, |–105| = 105. Mà 100 < 105 nên (–100) > (–105).

Vậy (–105) + 5 > (–105).

c) (–29) + (–11) = – (29 + 11) = –40.

So sánh –40 và –29:

|–40| = 40; |–29| = 29. Mà 40 > 29 nên (–40) < (–29).

Vậy (–29) + (–11) < (–29).

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