a, x - 140 : 35= 270

x - 4 = 270

x = 274

b, (x - 140) : 35= 270

x - 140 = 9450

x = 9590

Dễ mà em , hồi lớp 5 chị cũng làm đc toán lớp 6. 

a) x - 140 : 35 = 270

x - 4 = 270

x = 270 + 4

x = 274

b) ( x-140) : 35 = 270

x-140 = 270 x 35

x-140 = 9 450

x = 9 450  + 140

x = 9 590

các phần cn lại lm tương tự nha bn!
 

\(280-\left(x-140\right):35=270\)

\(\left(x-140\right):35=10\)

\(x-140=350\)

\(x=490\)

\(280-\left(x-140\right):35=270\)

\(\left(x-140\right):35=280-270\)

\(\left(x-140\right):35=10\)

\(x-140=10.35\)

\(x-140=350\)

\(x=350+140\)

\(x=490\)

a: \(280-\left(x-140\right):35=270\)

=>(x-140):35=280-270=10

=>x-140=350

=>x=350+140

=>x=490

b: \(\left(190-2x\right):35-32=16\)

=>\(\left(190-2x\right):35=32+16=48\)

=>\(190-2x=35\cdot48=1680\)

=>2x=190-1680=-1490

=>x=-745

c: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=2^3\cdot5\)

=>\(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=8\cdot5=40\)

=>41-(2x-5)=720:40=18

=>2x-5=41-18=23

=>2x=28

=>x=14

d: \(\left(x:23+45\right)\cdot37-22=2^4\cdot105\)

=>\(\left(\frac{x}{23}+45\right)\cdot37=16\cdot105+22=1702\)

=>\(\frac{x}{23}+45=46\)

=>\(\frac{x}{23}=1\)

=>x=23

e: \(\left(3x-4\right)\left(x-1\right)^3=0\)

=>\(\left[\begin{array}{l}3x-4=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac43\\ x=1\end{array}\right.\)

f: \(2^{2x-1}:4=8^3\)

=>\(2^{2x-1-2}=2^9\)

=>2x-3=9

=>2x=12

=>x=6

g: \(x^{17}=x\)

=>\(x^{17}-x=0\)

=>\(x\left(x^{16}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{16}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{16}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\\ x=-1\end{array}\right.\)

h: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-4\right)\left(x-6\right)=0\)

=>x∈{4;5;6}

i: \(\left(x+2\right)^5=2^{10}\)

=>\(\left(x+2\right)^5=\left(2^2\right)^5=4^5\)

=>x+2=4

=>x=2

k: 1+2+3+...+x=78

=>\(\frac{x\left(x+1\right)}{2}=78\)

=>x(x+1)=156

=>\(x^2+x-156=0\)

=>(x+13)(x-12)=0

=>x=-13(loại) hoặc x=12(nhận)

l: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

n: \(5^{x}:5^2=125\)

=>\(5^{x-2}=5^3\)

=>x-2=3

=>x=5

m: \(\left(x+1\right)^2=\left(x+1\right)^0\)

=>\(\left(x+1\right)^2=1\)

=>\(\left[\begin{array}{l}x+1=1\\ x+1=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=-2\end{array}\right.\)

o: Số số hạng của dãy số 2;4;..;52 là:

(52-2):2+1=50:2+1=25+1=26(số)

Tổng của dãy số 2;4;...;52 là:

\(\left(52+2\right)\cdot\frac{26}{2}=54\cdot13=702\)

(2+x)+(4+x)+...+(52+x)=780

=>26x+702=780

=>26x=78

=>x=3

p: \(70=2\cdot5\cdot7;80=2^4\cdot5\)

=>ƯCLN(70;80)=\(2\cdot5=10\)

70⋮x; 80⋮x

=>x∈ƯC(70;80)

=>x∈Ư(10)

mà x>8

nên x=10

q: \(12=2^2\cdot3;25=5^2;30=2\cdot3\cdot5\)

=>BCNN(12;25;30)=\(2^2\cdot3\cdot5^2=300\)

x⋮12; x⋮25; x⋮30

=>x∈BC(12;25;30)

=>x∈B(300)

mà 0<x<500

nên x=300

Tìm x : 

x + 1/3 = 4/5 

x = 4/5 - 1/3 

x = 12/15 - 5/15 

x = 7/15 

x - 1/2 = 2/7 

x = 2/7 + 1/2 

x = 4/14 + 7/14 

x = 11/14 

4/7 × x = 1/3 

x = 1/3 : 4/7 

x = 1/3 × 7/4 

x = 7/12 

x : 2/5 = 2/9 

x = 2/9 × 2/5 

x = 4/45 

20 × 7 : ( 5 × x - 3 × 5 ) = 4 

140 : 5  × ( x - 3 )  = 4 

5 × ( x - 3 ) = 140 : 4 

5 × ( x - 3 ) = 35 

x - 3 = 35 : 5 

x - 3 = 7 

x = 7 + 3 

x = 10 

x - 270  = 420 : 105 

x - 270 = 4 

x = 4 + 270 

x = 274 

x - 140 : 35 = 270 

x - 4 = 270 

x  = 270 + 4 

x = 274 

x + 1/3 = 4/5

x           = 4/5 - 1/3 

x           =  7/15

x - 1/2 = 2/7

x         = 2/7 + 1/2

x        = 11/14

4/7 * x  =  1/3

        x   = 1/3 : 4/7

        x    = 7/12

x : 2/5 = 2/9

x         = 2/9 * 2/5

x          4 / 45

20 * 7 : ( 5*x - 3 * 5) =4

= 140 :(5*x -3 *5) =4

5*x- 3*5 = 140 : 4

5*x - 3 * 5 = 35 

5* x           = 35 + 3 * 5

5 * x           =  50

x                = 50 : 5

x                = 10

x - 270 = 402 : 105

x - 270 = 4

x          = 270 + 4

x           =   274

x- 140 : 35 = 270 

x -  4          = 270

x                 = 270 + 4

x                  = 274

a)\(280-\left(x-140\right):35=270\)

\(\Leftrightarrow\left(x-140\right):35=10\)

\(\Leftrightarrow x-140=350\)

\(\Leftrightarrow x=490\)

b) \(\left(190-2x\right):35-32=16\)

\(\Leftrightarrow\left(190-2x\right):35=48\)

\(\Leftrightarrow190-2x=1680\)

\(\Leftrightarrow2x=-1490\Leftrightarrow x=-745\)

c) \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x-5\right)=18\)

\(\Leftrightarrow2x-5=23\)

\(\Leftrightarrow2x=28\Leftrightarrow x=14\)

280-(x-140):35=270

(x-140):35=280-270

(x-140):35=10

(x-140)=10×35

(x-140)=350

x=350-140

x=210

vậy x=210

(192-2x):35-32=16

(192-2x):35=16+32

(192-2x):35=48

(192-2x)=48×35

(192-2x)=1680

2x=192-1680

2x=-1488

x=-1488:2

x=-744

vậy x=-744

a)

\(280-\dfrac{\left(x-140\right)}{35}=270\\\dfrac{ \left(x-140\right)}{35}=10\\ x-140=\dfrac{10}{35}\\ x=\dfrac{10}{35}+140=\dfrac{982}{7}\)

b)

\(\dfrac{\left(190-2x\right)}{35}-32=16\\ \dfrac{\left(190-2x\right)}{35}=48\\ 190-2x=1680\\ -2x=1490\\ x=-745\)

c)

\(\dfrac{720}{41-2x+5}=2^3.5\\ \dfrac{720}{46-2x}=40\\ 720=1840-80x\\ 80x=1120\\ x=14\)

i) |x| - 3 = 0

|x| = 0 + 3

|x| = 3

giúp mk với