(x- 5)^5 = (x-5)^6
tìm x nha mn help me
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x+1/3+x+14/43+x+1/19+x+26=0
4x+65470/2451=0
4x=-65470/2451
x=-32735/4902
\(\left|x-3y\right|5+\left|y+4\right|=0\)
\(\Leftrightarrow\left\{\begin{matrix}x-3y=0\\y+4=0\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}x=3y\\y=-4\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}x=-12\\y=-4\end{matrix}\right.\)
Vậy....
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\(\left|x+3y-1\right|+3\left|y+2\right|=0\)
\(\Leftrightarrow\left\{\begin{matrix}x+3y-1=0\\y+2=0\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}x=1-3y\\y=-2\end{matrix}\right.\)\(\Leftrightarrow\left\{\begin{matrix}x=7\\y=-2\end{matrix}\right.\)
Vậy .....
1,a)\(\left|x-3y\right|\)\(\ge\)0 => \(\left|x-3y\right|\).5 \(\ge\)0
\(\left|y+4\right|\)\(\ge\)0
Mà \(\left|x-3y\right|\)5+\(\left|y+4\right|\)=0
=> \(\left|y+4\right|\)=0 => y=-4
=> \(\left|x-3y\right|\)=0 => \(\left|x-3.-4\right|\)=0 => x= -12
Câu b làm tương tự.
Tick cho chụy nha!
j: (2x-1)(3x+1)-(4-3x)(3-2x)=3
=>(2x-1)(3x+1)-(3x-4)(2x-3)=3
=>\(6x^2+2x-3x-1-\left(6x^2-9x-8x+12\right)=3\)
=>\(6x^2-x-1-\left(6x^2-17x+12\right)=3\)
=>\(6x^2-x-1-6x^2+17x-12=3\)
=>16x-13=3
=>16x=16
=>x=1
k: \(\left(2x+1\right)\left(x+3\right)-\left(x-5\right)\left(2x+7\right)=8\)
=>\(2x^2+6x+x+3-\left(2x^2+7x-10x-35\right)=8\)
=>\(2x^2+7x+3-2x^2-7x+10x+35=8\)
=>10x+38=8
=>10x=-30
=>x=-3
m: 2(3x-1)(2x+5)-6(2x-1)(x+2)=-6
=>\(2\left(6x^2+15x-2x-5\right)-6\left(2x^2+4x-x-2\right)=-6\)
=>\(2\left(6x^2+13x-5\right)-6\left(2x^2+3x-2\right)=-6\)
=>\(12x^2+26x-10-12x^2-18x+12=-6\)
=>8x+2=-6
=>8x=-8
=>x=-1
k hộ mik nha alan walker ngầu lol
Ta có :\(\frac{x-5}{4}=\frac{-9}{5-x}\)
\(\Rightarrow\frac{x-5}{4}=\frac{\left(-9\right).\left(-1\right)}{\left(5-x\right).\left(-1\right)}\)
\(\Rightarrow\frac{x-5}{4}=\frac{9}{x-5}\)
=>(x-5).(x-5)=9.4
\(\Rightarrow\left(x-5\right)^2=36\)
\(\Rightarrow\orbr{\begin{cases}x-5=6\\x-5=-6\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=11\\x=-1\end{cases}}\)
Vậy \(x=\left(11;-1\right)\)
Ta có: \(5.\left|x\right|=\left|-2017\right|+\left|13\right|\)
\(5.\left|x\right|=2017+13\)
\(5.\left|x\right|=2030\)
\(\left|x\right|=406\)
\(\Rightarrow x\in\left\{-406;406\right\}\)
Sắp thi rùi, chúc bn hok "tuốt" nha^^
x + xx + 5 = 125
x + xx = 125 - 5
x + xx = 120
x + x * 11 = 120
x * ( 11 + 1 ) = 120
x * 12 = 120
x = 120 : 12
x= 10
Vậy x = 10
x + xx + 5 = 125
x + xx = 125 - 5
x + xx = 120
x + X x 2 = 120
X x 3 = 120
X = 120 : 3
X = 40
Vì 15= 16 nên x - 5 = 1
x= 1+5
x=6
\(\left(x-5\right)^5=\left(x-5\right)^6\)
\(\Rightarrow\left(x-5\right)^6-\left(x-5\right)^5=0\)
\(\Rightarrow\left(x-5\right)^5.\left(x-5-1\right)=0\)
\(\Rightarrow\left(x-5\right)^5.\left(x-6\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x-5\right)^5=0\\x-6=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)