Phân tích đa thức thành nhân tử:6ab(a+6b)+6bc(b+6c)+6ca(c+6a)+217abc
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4a2b2 + 36a2b3 + 6ab4
= 2ab2(2a + 18ab + 3b2)
4a2b3 - 6a3b2
= 2a2b2(2b - 3a)
a^3+b^3+6ab-8=(a + b - 2) (a² - a b + 2a + b² + 2b + 4)
\(9a^2b+6ab^2+b^3-6ab-2b^2\)
\(=b\left(9a^2+6ab+b^2-6a-2b\right)\)
\(=b\left[\left(3a+b\right)^2-2\left(3a+b\right)\right]\)
\(=b\left(3a+b\right)\left(3a+b-2\right)\)
\(=b\left(9a^2+6ab+b^2\right)-2b\left(3a+b\right)\)
\(=b\left(3a+b\right)^2-2b\left(3a+b\right)\)
\(=b\left(3a+b\right)\left(3a+b-2\right)\)
\(9a^2b+6ab^2+b^3-6ab-2b^2\)
\(=b\left(9a^2+6ab+b^2-6a-2b\right)\)
\(=b\left[\left(3a+b\right)^2-2\left(3a+b\right)\right]\)
\(=b\left(3a+b\right)\left(3a+b-2\right)\)
\(A=9a^2-6ab+b^2-1\)
\(A=\left(3a-b\right)^2-1\)
\(A=\left(3a-b-1\right)\left(3a-b+1\right)\)
P/s haphuong
a: \(x^3-2x^2-5x+6\)
\(=x^3-x^2-x^2+x-6x+6\)
\(=\left(x-1\right)\left(x^2-x-6\right)=\left(x-1\right)\left(x-3\right)\left(x+2\right)\)
b: \(x^4+5x^2+6\)
\(=x^4+2x^2+3x^2+6\)
\(=x^2\left(x^2+2\right)+3\left(x^2+2\right)=\left(x^2+2\right)\left(x^2+3\right)\)
c: \(x^3+4x^2+5x+2\)
\(=x^3+x^2+3x^2+3x+2x+2\)
\(=\left(x+1\right)\left(x^2+3x+2\right)=\left(x+1\right)^2\cdot\left(x+2\right)\)
d: \(x^4+324\)
\(=x^4+36x^2+324-36x^2\)
\(=\left(x^2+18\right)^2-\left(6x\right)^2=\left(x^2+18+6x\right)\left(x^2+18-6x\right)\)
a) 3a2-6ab+3b2-12c2
=3.(a2-2ab+b2-4c2)
=3.[(a-b)2-4c2]
=3.(a-b-2c)(a-b+2c)