g, PT \(\Leftrightarrow\dfrac{x+24}{1996}+1+\dfrac{x+25}{1995}+1+\dfrac{x+26}{1994}+1+\dfrac{x+27}{1993}+1+\dfrac{x+2036}{4}-4=0\)

\(\Leftrightarrow\left(x+2020\right)\left(\dfrac{1}{1996}+\dfrac{1}{1995}+\dfrac{1}{1994}+\dfrac{1}{1993}+\dfrac{1}{4}\right)=0\)

\(\Leftrightarrow x+2020=0\)

\(\Leftrightarrow x=-2020\)

Vậy ...

12. In spite of feeling tired, the man tried to finish the work.   

13.She swims very well.

have played

Were - was

enjoys collecting - has had

goes - has been

is said to be

Chi tiết thì giúp e vs ạ

Bài 2:

a: \(P=\frac{x^2-\sqrt{x}}{x+\sqrt{x}+1}-\frac{2x+\sqrt{x}}{\sqrt{x}}+\frac{2\left(x-1\right)}{\sqrt{x}-1}\)

\(=\frac{\sqrt{x}\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}{x+\sqrt{x}+1}-\frac{\sqrt{x}\left(2\sqrt{x}+1\right)}{\sqrt{x}}+\frac{2\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{\sqrt{x}-1}\)

\(=x-\sqrt{x}-2\sqrt{x}-1+2\left(\sqrt{x}+1\right)=x-3\sqrt{x}-1+2\sqrt{x}+2=x-\sqrt{x}+1\)

Bài 1:

a: \(P=\frac{2\sqrt{x}-4}{3\sqrt{x}-4}-\frac{2\sqrt{x}+4}{\sqrt{x}-2}+\frac{x+13\sqrt{x}-20}{\left(3\sqrt{x}-4\right)\left(\sqrt{x}-2\right)}\)

\(=\frac{\left(2\sqrt{x}-4\right)\left(\sqrt{x}-2\right)-\left(2\sqrt{x}+4\right)\left(3\sqrt{x}-4\right)+x+13\sqrt{x}-20}{\left(3\sqrt{x}-4\right)\left(\sqrt{x}-2\right)}\)

\(=\frac{2x-8\sqrt{x}+8-6x+8\sqrt{x}-12\sqrt{x}+16+x+13\sqrt{x}-20}{\left(3\sqrt{x}-4\right)\left(\sqrt{x}-2\right)}\)

\(=\frac{-3x+\sqrt{x}+4}{\left(3\sqrt{x}-4\right)\left(\sqrt{x}-2\right)}=\frac{-3x+4\sqrt{x}-3\sqrt{x}+4}{\left(3\sqrt{x}-4\right)\left(\sqrt{x}-2\right)}\)

\(=\frac{\left(3\sqrt{x}-4\right)\left(-\sqrt{x}-1\right)}{\left(3\sqrt{x}-4\right)\left(\sqrt{x}-2\right)}=\frac{-\sqrt{x}-1}{\sqrt{x}-2}\)

b: P>=-3/4

=>\(P+\frac34\ge0\)

=>\(\frac{-\sqrt{x}-1}{\sqrt{x}-2}+\frac34\ge0\)

=>\(\frac{-4\sqrt{x}-4+3\sqrt{x}-6}{4\left(\sqrt{x}-2\right)}\ge0\)

=>\(\frac{-\sqrt{x}-10}{4\left(\sqrt{x}-2\right)}\ge0\)

=>\(\sqrt{x}-2<0\)

=>\(\sqrt{x}<2\)

=>0<=x<4

Kết hợp ĐKXĐ, ta được: 0<=x<4 và x<>16/9

17. coming 18. iron___ doing 19. wakes 20. buying

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