Ta có: \(\frac{x-2011}{12}+\frac{x-2011}{20}+\frac{x-2011}{30}+\frac{x-2011}{42}+\frac{x-2011}{56}+\frac{x-2011}{72}=\frac{16}{9}\)

=>\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)

=>\(\left(x-2011\right)\left(\frac13-\frac14+\frac14-\frac15+\frac15-\frac16+\frac16-\frac17+\frac17-\frac18+\frac18-\frac19\right)=\frac{16}{9}\)

=>\(\left(x-2011\right)\left(\frac13-\frac19\right)=\frac{16}{9}\)

=>\(\frac29\left(x-2011\right)=\frac{16}{9}\)

=>x-2011=8

=>x=8+2011

=>x=2019

\(\frac{2011.2013-2011.2012}{2012.2011+2011.2013}\)

\(=\frac{2011.\left(2013-2012\right)}{2011.\left(2012+2013\right)}\)

\(=\frac{2011.1}{2011.4025}\)

\(=\frac{1}{4025}\)

bài này là bài Tính nha mọi người giải rõ ra giúp mik nha

\(\Leftrightarrow2011.\left|x-2011\right|+\left(x-2011\right)^2=2013.\left|x-2011\right|\)

\(\Leftrightarrow\left(x-2011\right)^2=2.\left|x-2011\right|\Rightarrow\orbr{\begin{cases}x-2011=0\\2=\left|x-2011\right|\end{cases}}\Rightarrow\orbr{\begin{cases}x=2013\\x=2009\end{cases}}\text{hoặc }x=2011\)

Vậy ....

Chọn A

x . 2011 - x = 2011 . 2009 - 2011

x.(2011 - 1) = 4038088

x . 2010 = 4038088

x = 4038088: 2010

x = 2008,999005

X x 2011-X = 2011 x 2009 - 2011

X x ( 2011-1)   = 2011 x (2009- 1)

X x 2010        = 2011 x 2010

=> X=2011

X x 2011 - X = 2011 x 2009 + 2011

=> X x ( 2011-1) = 2011 x (2009+1)

=> X x 2010 = 2011 x 2010

=> X = 2011

\(2012\cdot\left|x-2011\right|+\left(x-2011\right)^2=2013\left|2011-x\right|\)

=>\(\left(x-2011\right)^2-\left|x-2011\right|=0\)

=>\(\left|x-2011\right|\left(\left|x-2011\right|-1\right)=0\)

TH1: |x-2011|=0

=>x-2011=0

=>x=2011

TH2: |x-2011|-1=0

=>x-2011=1 hoặc x-2011=-1

=>x=2012 hoặc x=2010

Ta có : 

\(A=\frac{2012.14+1997+2010.2011}{2011.5+2011.1008+1012.2011}\)

\(\Rightarrow A=\frac{\left(2011+1\right).14+1997+2010.2011}{2011.\left(5+1008+1012\right)}\)

\(\Rightarrow A=\frac{2011.14+14+1997+2010.2011}{2011.2025}\)

\(\Rightarrow A=\frac{2011.14+2011+2010.2011}{2011.2025}\)

\(\Rightarrow A=\frac{2011.\left(14+1+2011\right)}{2011.2025}\)

\(\Rightarrow A=\frac{2011.25}{2011.25}\)

\(\Rightarrow A=1\) ( tử số = mẫu số ) 

Vậy \(A=1\)

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