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12(52+1)(54+1)(58+1)(516+1)
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CG
1
28 tháng 12 2017
Ta có: \(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(\Rightarrow P=\dfrac{24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)
\(\Rightarrow P=\dfrac{\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)
\(\Rightarrow P=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)
\(\Rightarrow P=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)
\(\Rightarrow P=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)
\(\Rightarrow P=\dfrac{5^{32}-1}{2}\)
CM
8 tháng 11 2018
Ta có:
( 5 2 - 1).P = ( 5 2 – 1).12.( 5 2 + 1)( 5 4 + 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 2 – 1).( 5 2 + 1)( 5 4 + 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 4 - 1)( 5 4 + 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 8 - 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 16 - 1)( 5 16 + 1)
= 12.( 5 32 - 1)
31 tháng 8 2021
\(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\left(5^{128}-1\right)=2.5^{128}-2\)
NL
Nguyễn Lê Phước Thịnh
CTVHS
31 tháng 8 2021
c: Ta có: \(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^2-1\right)\left(5^2+1\right)\cdot\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{16}-1\right)\cdot\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{32}-1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{64}-1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{128}-1\right)\)
\(=2\cdot5^{128}-2\)
LC
6
25 tháng 8 2019
\(\frac{-1}{-16}-\frac{1}{15}\)
\(=\frac{1}{16}-\frac{1}{15}\)
\(=\frac{15-16}{16\times15}\)
\(=\frac{-1}{240}\)
25 tháng 8 2019
\(-\frac{1}{16}-\frac{1}{15}\)
\(=-\left(\frac{1}{16}+\frac{1}{15}\right)\)
\(=-\frac{16+15}{16\times15}\)
\(=-\frac{31}{240}\)
NL
Nguyễn Lê Phước Thịnh
CTVHS
23 tháng 3
b: 200:[117-(23-6)]
=200:[117-17]
=200:100
=2
c: \(2020-\left\lbrack45-\left(6-1\right)^2\right\rbrack+2019^0\)
\(=2020-\left\lbrack45-5^2\right\rbrack+1\)
=2021-(45-25)
=2021-20
=2001
d: \(476-\left\lbrace5\cdot\left\lbrack409-\left(8\cdot3-21\right)^2\right\rbrack-1724\right\rbrace\)
=476-{5*[409-(24-21)^2]-1724}
=\(476-\left\lbrace5\cdot\left\lbrack409-9\right\rbrack-1724\right\rbrace\)
\(=476-\left(5\cdot400-1724\right)=476-\left(2000-1724\right)\)
=476-276
=200
Tham khảo tại :
Câu hỏi của Cô gái đến từ tương lai - Toán lớp 8 | Học trực tuyến
_Minh ngụy_
12.( 52 + 1 ).( 54 + 1 ).( 58 + 1 ).( 516 + 1 )
= \(\frac{1}{2}.2\). 12.( 52 + 1 ).( 54 + 1 ).( 58 + 1 ).( 516 + 1 )
= \(\frac{1}{2}\).( 52 - 1 ).(52+1).( 54 + 1 ).( 58 + 1 ).( 516 + 1 )
= \(\frac{1}{2}\).( 54 - 1 ).( 54 + 1 ).( 58 + 1 ).( 516 + 1 )
=\(\frac{1}{2}\).( 58 - 1 ).( 58 + 1 ).( 516 + 1 )
=\(\frac{1}{2}\).( 516 - 1 ).( 516 + 1 )
=\(\frac{1}{2}\).( 532 - 1 )
=\(\frac{5^{32}-1}{2}\)