B= ( 13-4√3)(7+4√3)-8√20+2√43+24√3
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\(B=\left(13-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{43+24\sqrt{3}}}\)
\(=\left(2\sqrt{3}-1\right)^2\left(2+\sqrt{3}\right)^2-8\sqrt{20+2\sqrt{\left(4+3\sqrt{3}\right)^2}}\)
\(=\left(3\sqrt{3}+4\right)^2-8\sqrt{20+2\left(4+3\sqrt{3}\right)}\)
\(=\left(3\sqrt{3}+4\right)^2-8\sqrt{28+6\sqrt{3}}\)
\(=\left(3\sqrt{3}+4\right)^2-8\sqrt{\left(3\sqrt{3}+1\right)^2}\)
\(=43+24\sqrt{3}-8\left(3\sqrt{3}+1\right)=35\)
\(D=\left(13-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{43+24\sqrt{3}}}\)
\(=\left(2\sqrt{3}-1\right)^2\left(\sqrt{3}+2\right)^2-8\sqrt{20+2\left(3\sqrt{3}+4\right)}\)
\(=\left(4+3\sqrt{3}\right)^2-8\sqrt{28+6\sqrt{3}}\)\(=\left(4+3\sqrt{3}\right)^2-8\left(3\sqrt{3}+1\right)\)
\(=43+24\sqrt{3}-24\sqrt{3}-8=35\)
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
Câu a:
- |- 5 + 3 - 7| - |- 5 + 7|
= -|- 2 - 7| - |2|
= - |-9| - 2
= - 9 - 2
= -11
Câu b:
24 - (72 - 13 + 24) - (72 - 13)
= 24 - 72 + 13 - 24 - 72 + 13
= (24 - 24) - (72 + 72) + (13 + 13)
= 0 - 144 + 26
= - 118
Câu c:
|4 - 9 - 5| - (4 - 9 - 5) - 15 + 9
=|- 5 - 5| - (- 5 - 5) - 15 + 9
= |-10| - (-10) - 15 + 9
= 10 + 10 - 15 + 9
= 20 - 15+ 9
= 5 +9
= 14
Câu d:
- 20 - (25 - 11 + 8) +(25 - 8 + 20)
= - 20 - 25 + 11 - 8 + 25 - 8 + 20
= (-20 + 20) + (25 - 25) + (11 - 8- 8)
= 0 + 0+ 3 - 8
= -5
\(A=43+24\sqrt{3}-8\sqrt{20+2\sqrt{\left(3\sqrt{3}+4\right)^2}}\)
\(=43+24\sqrt{3}-8\sqrt{20+2\left(3\sqrt{3}+4\right)}\)
\(=43+24\sqrt{3}-8\sqrt{28+6\sqrt{3}}\)
\(=43+24\sqrt{3}-8\sqrt{\left(3\sqrt{3}+1\right)^2}\)
\(=43+24\sqrt{3}-8\left(3\sqrt{3}+1\right)\)
\(=43-8=35\)
\(A=\left(13-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{43+24\sqrt{3}}}\) \(A=\left(6+7-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{\left(16+2.4.3\sqrt{3}+27\right)}}\)
\(A=6\left(7+4\sqrt{3}\right)+\left(7-4\sqrt{3}\right)\left(7+4\sqrt{3}\right)-8\sqrt{20+2\sqrt{\left(4+3\sqrt{3}\right)^2}}\)Trong căn là hằng đẳng thức (a+b)^2
\(A=42+24\sqrt{3}+7^2-\left(4\sqrt{3}\right)^2-8\sqrt{20+2\left(4+3\sqrt{3}\right)}\) sử dụng hằng đẳng thức a^2 -b^2\(A=43+24\sqrt{3}-8\sqrt{20+8+2.3\sqrt{3}}\)
\(A=43+24\sqrt{3}-8\sqrt{1+2.3\sqrt{3}+27}\)trong căn tiếp tục là hằng đẳng thức (a+b)^2\(A=43+24\sqrt{3}-8\sqrt{\left(1+3\sqrt{3}\right)^2}\)
\(A=43+24\sqrt{3}-8\left(1+3\sqrt{3}\right)\)
\(A=35\)
chúc bạn thành công nhé
Câu 6: Khôg có cau nào đúng
Câu 7: C
Câu 8: B
Câu 9: B
Câu 10: D