a/ x thuộc Ư(35)

x \(\in\hept{ }\)1;5;7;35;-1;-5;-7;-35

Vì x > 0 nên x = ........

Nhớ k nhé!

a. x bằng 1,,5,7,35

b, x bằng 2, 4, 3 ,7

c, x bằng 2.

giúp mk vs

lm đc câu nào thì mk k cho

a) \(\Leftrightarrow\left[{}\begin{matrix}2x+3=0\\5x-15=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=3\end{matrix}\right.\)

b) \(\Leftrightarrow\left[{}\begin{matrix}3x+1=0\\3x-9=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=3\end{matrix}\right.\)

a. \(\left[{}\begin{matrix}2x+3=0\\5x-15=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-3}{2}\\x=3\end{matrix}\right.\)

b. \(\left[{}\begin{matrix}3x+1=0\\3x-9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1}{3}\\x=3\end{matrix}\right.\)

nhiều câu nhưng dễ sao mk làm hết nổi đây

???????????????????????????????????????????????????????????????????????????

plz no no no no no no

cứ làm đi

a,(2x+1)(y-3)=12

2x+1 và y-3 Ư(12)=

=>x=0,y=15

c) Ta có: \(36^{25}=\left(6^2\right)^{25}=6^{50}\)

\(25^{36}=\left(5^2\right)^{36}=5^{72}\)

Ta có: \(6^{50}=\left(6^5\right)^{10}=7776^{10}\)

mà \(5^{70}=\left(5^7\right)^{10}=78125^{10}\)

nên \(6^{50}< 5^{70}\)

mà \(5^{70}< 5^{72}\)

nên \(6^{50}< 5^{72}\)

hay \(36^{25}< 25^{36}\)

a: (2x+1)(y-3)=12

mà 2x+1 lẻ

nên (2x+1;y-3)∈{(1;12);(3;4)}

=>(2x;y)∈{(0;15);(2;7)}

=>(x;y)∈{(0;15);(1;7)}

b: \(2^{x}+2^{x+1}+\cdots+2^{x+2015}=2^{2019}-8\)

=>\(2^{x}\left(1+2+\cdots+2^{2015}\right)=2^3\left(2^{2016}-1\right)\)

Đặt \(A=1+2+\cdots+2^{2015}\)

=>\(2A=2+2^2+\cdots+2^{2016}\)

=>2A-A=\(2+2^2+\cdots+2^{2016}-1-2-2^2-\cdots-2^{2015}\)

=>\(A=2^{2016}-1\)

Ta có: \(2^{x}\left(1+2+\cdots+2^{2015}\right)=2^3\left(2^{2016}-1\right)\)

=>\(2^{x}=2^3\)

=>x=3