Tìm x, biết :
\(1\frac{8}{15}\)-\(\frac{2}{3}\)x = 0,2
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a) Ap dụng tích chất dãy tỉ số = nhau
Ta có:x/2=y/3=x+y/5+7=15/15=1
x/2=1=> x=2
y/3=1=> y=3
x + x : 0,2 = 1,35
x * 1 + x * 5 = 1,35
x * ( 1 + 5 ) = 1,35
x * 6 = 1,35
x = 1,35 : 6
x = 0,225
hok tốt nha ^_^
a.2/3 + 1/3 - x= 3/5
=> 1-x = 3/5
=> x = 1-3/5= 2/5
b. 1/8/15 - 2/3x = 0,2
=> 2/3x= 23/15 - 1/5= 4/3
=> x= 4/3 : 2/3=2
c. 2/3x -3/2x = 5/12
=> x( 2/3 - 3/2) = 5/12
=> x. -5/6 = 5/12
=> x= 5/12 : -5/6
=> x= -1/2
a) 2/3 + 1/3 - x = 3/5
=> 1 - x = 3/5
=> x = 1 - 3/5
x = 2/5
b) \(1\frac{8}{15}-\frac{2}{3}x=0,2\)
=> 23/15 - 2/3x = 0,2
=> 2/3x = 23/15 - 0,2
2/3x = 1,333333333
=>x = 1,333333333 : 2/3
x = 2
c) ???
a, \(\frac{3}{5}\left(2x-\frac{1}{3}\right)+\frac{4}{15}=\frac{12}{30}\)
\(\Leftrightarrow\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{2}{15}\)
\(\Leftrightarrow2x-\frac{1}{3}=\frac{2}{9}\)
\(\Leftrightarrow2x=\frac{5}{9}\)
\(\Leftrightarrow x=\frac{5}{18}\)
b,\(\left(-0,2\right)^x=\frac{1}{25}\)
\(\Leftrightarrow\left(\frac{-1}{5}\right)^x=\left(\frac{-1}{5}\right)^2\)
\(\Leftrightarrow x=2\)
c,\(\left|x-1\right|-\frac{3}{12}=\left(-\frac{1}{2}\right)^2\)
\(\Leftrightarrow\left|x-1\right|-\frac{3}{12}=\frac{1}{4}\)
\(\Leftrightarrow\left|x-1\right|=\frac{1}{2}\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=\frac{1}{2}\\x-1=-\frac{1}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{1}{2}\end{cases}}\)
\(a,\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{12}{30}-\frac{4}{15}\)
\(\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{2}{15}\)
\(2x-\frac{1}{3}=\frac{2}{9}\)
\(x=\frac{5}{18}\)
\(b,\left(-0,2\right)^x=\frac{1}{25}\)
\(\left(-0,2\right)^x=\left(-\frac{1}{5}\right)^2\)
\(\left(-0,2\right)^x=\left(-0,2\right)^2\)
\(x=2\)
c,/x-1/=1/2
Nếu
\(x-1\ge0\)
\(x\ge1\)
suy ra x-1=1/2
x=3/2(thỏa mãn điều kiện )
nếu \(x-1\le0\)
\(x\le1\)
suy ra x-1=-1/2
x=1/2 (thỏa mãn điều kiện )
Vậy ...
nha !!!
2/5.x:7/3.1/8=25/15
2/5.x:7/24=5/3
2/5.x=5/3.7/24
2/5.x=6/34
x=6/34:2/5
x=15/34
\(\frac{2}{5}x:\frac{7}{3}.\frac{1}{8}=\frac{25}{15}\Leftrightarrow\frac{2}{5}x:\frac{7}{3}.\frac{1}{8}=\frac{5}{3}\Leftrightarrow\frac{2}{5}x:\frac{7}{3}=\frac{5}{3}:\frac{1}{8}\Leftrightarrow\frac{2}{5}x:\frac{7}{3}=\frac{5}{3}.8\Leftrightarrow\frac{2}{5}x:\frac{7}{3}=\frac{40}{3}\)
\(\Leftrightarrow\frac{2}{5}x=\frac{40}{3}.\frac{7}{3}\Leftrightarrow\frac{2}{5}x=\frac{280}{3}\Leftrightarrow x=\frac{280}{3}:\frac{2}{5}\Leftrightarrow x=\frac{280}{3}.\frac{5}{2}\Leftrightarrow x=\frac{700}{3}\)
Vậy .........
\(x\times\frac{6}{25}=\frac{15}{-13}\)
x=\(\frac{15}{-13}\div\frac{6}{25}\)
x=\(-\frac{125}{26}\)
các câu còn lại làm tương tự nha!!!
\(1.x.\frac{6}{25}=\frac{15}{-13}\\ x=\frac{15}{-13}:\frac{6}{25}\\ x=-\frac{125}{26}\)
\(2.x:\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\\ x:\frac{4}{10}=\frac{11}{45}\\ x=\frac{11}{45}.\frac{4}{10}\\ x=\frac{22}{225}\)
\(3.\frac{3}{8}-\frac{1}{6}.x=\frac{1}{4}\\ \frac{1}{6}.x=\frac{3}{8}-\frac{1}{4}\\ \frac{1}{6}.x=\frac{1}{8}\\ x=\frac{1}{8}:\frac{1}{6}\\ x=\frac{3}{4}\)
\(4.\frac{1}{3}+\frac{1}{2}:x=-4\\ \frac{1}{2}:x=-4-\frac{1}{3}=-\frac{13}{3}\\ x=\frac{1}{2}:\left(-\frac{13}{3}\right)=-\frac{3}{26}\)
\(5.x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}=\frac{5}{6}\\ x=\frac{5}{6}-\frac{7}{12}\\ x=\frac{1}{4}\)
a)
\(\Rightarrow\left(\frac{305}{2}-\frac{1187}{8}\right):\frac{1}{5}=x:\frac{3}{10}\)
\(\Rightarrow\frac{33}{8}.5=x:\frac{3}{10}\)
\(\Rightarrow x=\frac{33}{8}.5.\frac{3}{10}\)
\(\Rightarrow x=\frac{99}{16}\)
1\(\frac{8}{15}\)-\(\frac{2}{3}\)x=0.2
\(\frac{23}{15}\)- \(\frac{2}{3}\)x=\(\frac{2}{10}\)
\(\frac{2}{3}\)x=\(\frac{23}{15}-\frac{2}{10}\)
\(\frac{2}{3}\)x=\(\frac{4}{3}\)
x=\(\frac{4}{3}:\frac{2}{3}\)
x=2
Vậy x=2