$\sin a.\cos a.(\tan a+\cot a)\\=\sin a.\cos a.\tan a+\sin a.\cos a.\cot a\\=\sin a.\cos a.\dfrac{\sin a}{\cos a}+\sin a.\cos a.\dfrac{\cos a}{\sin a}\\=\sin^2 a+\cos^2 a\\=1$

\(sin\left(a\right).cos\left(a\right).\left(tan\left(a\right)+cot\left(a\right)\right)\\ =sin\left(a\right).cos\left(a\right).tan\left(a\right)+sin\left(a\right).cos\left(a\right).cot\left(a\right)\\ =sin\left(a\right).cos\left(a\right).\dfrac{sin\left(a\right)}{cos\left(a\right)}+sin\left(a\right).cos\left(a\right).\dfrac{cos\left(a\right)}{sin\left(a\right)}\\ =sin^2\left(a\right)+cos^2\left(a\right)=1\)

\(A=cos\left(7\pi-x\right)+3sin\left(\dfrac{3\pi}{2}+x\right)-cos\left(\dfrac{\pi}{2}-x\right)-sinx\)

\(=cos\left(x+\pi\right)+3sin\left(-\dfrac{\pi}{2}+x\right)-cos\left(\dfrac{\pi}{2}-x\right)-sinx\)

\(=-cosx-3cosx-sinx-sinx=-4cosx-2sinx\)

Bài 1:

ΔABC vuông tại A

=>\(AB^2+AC^2=BC^2\)

=>\(AC^2=6^2-4^2=36-16=20\)

=>\(AC=2\sqrt5\) (cm)

Xét ΔABC vuông tại A có

sin B=cos C=\(\frac{AC}{BC}=\frac{2\sqrt5}{6}=\frac{\sqrt5}{3}\)

cos B=sin C=\(\frac{AB}{BC}=\frac46=\frac23\)

tan B=cot C=\(\frac{AC}{AB}=\frac{2\sqrt5}{4}=\frac{\sqrt5}{2}\)

cot B=tan C=\(\frac{AB}{AC}=\frac{4}{2\sqrt5}=\frac{4\sqrt5}{10}=\frac{2\sqrt5}{5}\)

BÀi 2:

a: \(A=cos^2x+cos^2x\cdot\cot^2x\)

\(=cos^2x\left(1+\cot^2x\right)\)

\(=\frac{cos^2x}{\sin^2x}=\cot^2x\)

b: \(\sin^2x+\sin^2x\cdot\tan^2x\)

\(=\sin^2x\left(1+\tan^2x\right)\)

\(=\sin^2x:cos^2x=\tan^2x\)

mình ko bt cách viết  phân số nên đường gạch ngang mờ mờ mà các bạn nhìn là phân số nhé

a, \(\left(1-sin^2x\right)cot^2x+1-cot^2x\)

\(=cot^2x-sin^2x.cot^2x+1-cot^2x\)

\(=1-sin^2x.\frac{\text{cos}^2x}{sin^2x}=1-\text{cos}^2x=sin^2x\)

b,\(\left(tanx+cotx\right)^2-\left(tanx-cotx\right)2\)

\(=tan^2x2.tanx.cotx+cot^2x-tan^2x+2tanx.cotx-cot^2x\)

\(=4tanxcotx=4\)

c,\(\left(xsina-y\text{cos}a\right)^2+\left(x\text{cos}a+ysina\right)^2\)

\(=x^2sin^2a=2xysina\text{cos}a+y^2\text{cos}^2a+2xysina\text{cos}a+y^2sin^2a\)

\(=x^2\left(sin^2a+\text{cos}^2a\right)+y^2\left(sin^2a+\text{cos}^2a\right)\)

\(=x^2+y^2\)