\(\Leftrightarrow5x+5=4x+12\)

hay x=7

\(a,\dfrac{-1}{8}=\dfrac{3}{x}\\ \dfrac{3}{-24}=\dfrac{3}{x}\\ x=-24\\ b,\dfrac{x}{3}=\dfrac{3}{x}\\ x.x=3.3\\ x^2=9\\ x=\pm3\\ c,\dfrac{3}{4}.x=1\dfrac{1}{2}\\ \dfrac{3}{4}.x=\dfrac{3}{2}\\ x=\dfrac{3}{2}:\dfrac{3}{4}\\ x=2\\ d,x-\dfrac{3}{10}=\dfrac{7}{15}:\dfrac{3}{5}\\ x-\dfrac{3}{10}=\dfrac{7}{9}\\ x=\dfrac{7}{9}+\dfrac{3}{10}\\ x=\dfrac{97}{90}\\ e,\dfrac{-4}{7}-x=\dfrac{-8}{3}.\dfrac{3}{7}\\ \dfrac{-4}{7}-x=\dfrac{-8}{7}\\ x=\dfrac{-4}{7}+\dfrac{8}{7}\\ x=\dfrac{4}{7}\\ \)

f: =>x*4/7=1/5+2/3=3/15+10/15=13/15

=>x=91/60

g: =>1/3:3x=1/5-2/3=-7/15

=>3x=-5/7

=>x=-5/21

h: =>7/8x=-1/9

=>x=-1/9:7/8=-1/9*8/7=-8/63

j: =>(2,8x-50)=34

=>2,8x=84

=>x=30

\(2\frac{4}{5}.x-50:\frac{2}{3}=51\)

\(\frac{14}{5}.x-50:\frac{2}{3}=51\)

\(\frac{14}{51}.x=51+50:\frac{2}{3}\)

\(\frac{14}{51}.x=51+75\)

\(\frac{14}{51}.x=126\)

\(x=126:\frac{14}{51}\)

x=459

Vậy x=459

\(\frac{2}{3}.x=\frac{5}{12}=>x=\frac{5}{12}:\frac{2}{3}=\frac{5.3}{12.2}=\frac{15}{24}\)=\(\frac{3}{8}\)

vậy x=3/8

a) 60 - 3 ( x - 2 ) = 51

=> 3 (x - 2) = 60 - 51 = 9

=> x - 2 = 9 : 3 = 3

=> x = 3 = 2 = 5 

b) 4x - 20 = 2^5 : 2^2

=> 4x - 20 = 8

=> 4x = 8 + 20 = 28

=> x = 28 : 4 = 7

c) 48751 - ( 10425 + x ) = 382^8 : 12

đề có sai ko ?

d) ( 2367 - x ) - ( 2^10 - 7 ) = 15^2 - 20 

=> 2367 - x - 2^10 + 7 = 205

=> -x = 205 - 7 + 2¹⁰ - 2367 = -1145

=> x = 1145

câu D của bạn trần như sai rồi phải là 1146 mới là đáp án đúng

a) x = 1/2

b) x = 70/153

c) x = dư ( có sai đề ko bạn )

~Ủng hộ mk nha các bạn~

ừ mình nhầm câu c) là X * 306 = 36108 + 612 

x^2=16

Suy ra x^2=4^2

Vậy x^2=4^2

[1/(x+2)-1/(x+5)]+[1/(x+5)-1/(x+10)]+[1/(x+10)-1/(x+17)]=x/15.[1/(x+2)-1/(x+17)]
1/(x+2)-1/(x+17)=x/15.[1/(x+2)-1/(x+17)]
1=x/15
x=15

a) x - \(\frac{1}{8}\)= \(\frac{7}{3}\)x \(\frac{21}{4}\)

   x - \(\frac{1}{8}\)= \(\frac{49}{4}\)

             x = \(\frac{49}{4}\)+ \(\frac{1}{8}\)

             x = 98

b) x : \(\frac{3}{2}\) = \(\frac{1}{4}\)

               x = \(\frac{1}{4}\)x \(\frac{3}{2}\)

              x = \(\frac{3}{8}\)

c) \(\frac{103}{10}\) - x = \(\frac{4}{5}\)

                    x = \(\frac{103}{10}\)- \(\frac{4}{5}\)

                    x = \(\frac{19}{5}\)

d) x = 51 x \(\frac{4}{17}\)

    x = \(12\)

Vậy chị kết luận ngắn gọn là:

a)=98

b)=3/8

c)=19/5

d)=12