\(\dfrac{sssss}{ssss}\)sdsdsdsdsdsd \(sssss\)
\(\dfrac{sssss}{ssss}\)
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
22 tháng 9 2023
\(\dfrac{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}\) + \(\dfrac{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}{\dfrac{\dfrac{9}{9}}{\dfrac{9}{9}}}\) = 1 + 1 = 2
NL
Nguyễn Lê Phước Thịnh
CTVHS
26 tháng 8
Ta có: \(\frac{1}{99}+\frac{2}{98}+\cdots+\frac{99}{1}\)
\(=\left(\frac{1}{99}+1\right)+\left(\frac{2}{98}+1\right)+\cdots+\left(\frac{98}{2}+1\right)+1\)
\(=\frac{100}{2}+\frac{100}{3}+\cdots+\frac{100}{100}=100\left(\frac12+\frac13+\cdots+\frac{1}{100}\right)\)
Ta có: \(A=\frac{\frac{1}{99}+\frac{2}{98}+\cdots+\frac{99}{1}}{\frac12+\frac13+\cdots+\frac{1}{100}}\)
\(=\frac{100\left(\frac12+\frac13+\cdots+\frac{1}{100}\right)}{\frac12+\frac13+\cdots+\frac{1}{100}}=100\)
Ta có: \(92-\frac19-\frac{2}{10}-\cdots-\frac{92}{100}\)
\(=\left(1-\frac19\right)+\left(1-\frac{2}{10}\right)+\cdots+\left(1-\frac{92}{100}\right)\)
\(=\frac89+\frac{8}{10}+\cdots+\frac{8}{100}=8\left(\frac19+\frac{1}{10}+\cdots+\frac{1}{100}\right)\)
Ta có: \(\frac{1}{45}+\frac{1}{50}+\cdots+\frac{1}{500}\)
\(=\frac{1}{5\cdot9}+\frac{1}{5\cdot10}+\cdots+\frac{1}{5\cdot100}\)
\(=\frac15\left(\frac19+\frac{1}{10}+\cdots+\frac{1}{100}\right)\)
Ta có: \(B=\frac{92-\frac19-\frac{2}{10}-\cdots-\frac{92}{100}}{\frac{1}{45}+\frac{1}{50}+\cdots+\frac{1}{500}}\)
\(=8:\frac15=40\)
Do đó: A/B=100/40=5/2
8 tháng 4 2023
\(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{1\dfrac{1}{6}-\dfrac{7}{8}+0,7}\\ =\dfrac{2\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}{7\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}-\dfrac{\dfrac{2}{6}-\dfrac{2}{8}+\dfrac{2}{10}}{\dfrac{7}{6}-\dfrac{7}{8}+\dfrac{7}{10}}\\ =\dfrac{2}{7}-\dfrac{2\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}{7\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{10}\right)}\\ =\dfrac{2}{7}-\dfrac{2}{7}=0\)
8 tháng 4 2023
phân số cuối là \(\dfrac{2}{7}-\dfrac{2\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}{7\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}\) nha :vv
P
23 tháng 4 2023
1) \(\dfrac{1}{2}+\dfrac{13}{19}-\dfrac{4}{9}+\dfrac{6}{19}+\dfrac{5}{18}\)
\(=\dfrac{1}{2}+\left(\dfrac{13}{19}+\dfrac{6}{19}\right)-\dfrac{4}{9}+\dfrac{5}{18}\)
\(=\dfrac{3}{2}-\dfrac{4}{9}+\dfrac{5}{18}\)
\(=\dfrac{19}{18}+\dfrac{5}{18}\)
\(=\dfrac{24}{18}\)
\(=\dfrac{4}{3}\)
2) \(\dfrac{-20}{23}+\dfrac{2}{3}-\dfrac{3}{23}+\dfrac{2}{5}+\dfrac{7}{15}\)
\(=\left(-\dfrac{20}{23}-\dfrac{3}{23}\right)+\dfrac{2}{3}+\dfrac{2}{5}+\dfrac{7}{15}\)
\(=-1+\dfrac{2}{3}+\dfrac{2}{5}+\dfrac{7}{15}\)
\(=-\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{7}{15}\)
\(=\dfrac{1}{15}+\dfrac{7}{15}\)
\(=\dfrac{8}{15}\)
3) \(\dfrac{4}{3}+\dfrac{-11}{31}+\dfrac{3}{10}-\dfrac{20}{31}-\dfrac{2}{5}\)
\(=\left(\dfrac{-11}{31}-\dfrac{20}{31}\right)+\dfrac{4}{3}+\dfrac{3}{10}-\dfrac{2}{5}\)
\(=-1+\dfrac{4}{3}+\dfrac{3}{10}-\dfrac{2}{5}\)
\(=\dfrac{1}{3}+\dfrac{3}{10}-\dfrac{2}{5}\)
\(=\dfrac{1}{3}-\dfrac{1}{10}\)
\(=\dfrac{7}{30}\)
4) \(\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)
\(=\dfrac{5}{7}.\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)\)
\(=\dfrac{5}{7}.-\dfrac{7}{11}\)
\(=-\dfrac{35}{77}\)
\(=-\dfrac{5}{11}\)