tìm X
a, 72.x-14.x=72.10-70
b,62.x-52.x=11.22-11
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c) \(\left|x\right|=3,5\Rightarrow\left[{}\begin{matrix}x=3,5\\x=-3,5\end{matrix}\right.\)
d) \(\left|x\right|=-2,7\Rightarrow x\in\varnothing\)
l) \(\left|x+\dfrac{3}{4}\right|-5=-2\Rightarrow\left|x+\dfrac{3}{4}\right|=3\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=3\\x+\dfrac{3}{4}=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3-\dfrac{3}{4}\\x=-3-\dfrac{3}{4}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=\dfrac{15}{4}\end{matrix}\right.\)
Đính chính câu l \(x=-\dfrac{15}{4}\) không phải \(x=\dfrac{15}{4}\)
1: x=7+5=12
2: =>-29-x=-10
=>x+29=10
=>x=-19
3: =>x+7=-18
=>x=-25
4: =>x+19-11=0
=>x+8=0
=>x=-8
a: \(\frac{x+1}{65}+\frac{x+2}{64}=\frac{x+3}{63}+\frac{x+4}{62}\)
=>\(\frac{x+1}{65}+1+\frac{x+2}{64}+1=\frac{x+3}{63}+1+\frac{x+4}{62}+1\)
=>\(\frac{x+66}{65}+\frac{x+66}{64}=\frac{x+66}{63}+\frac{x+66}{62}\)
=>\(\left(x+66\right)\left(\frac{1}{62}+\frac{1}{63}-\frac{1}{64}-\frac{1}{65}\right)=0\)
=>x+66=0
=>x=-66
b: \(\frac{x-12}{77}+\frac{x-11}{78}=\frac{x-74}{15}+\frac{x-72}{17}\)
=>\(\frac{x-12}{77}-1+\frac{x-11}{78}-1=\frac{x-74}{15}-1+\frac{x-72}{17}-1\)
=>\(\frac{x-89}{77}+\frac{x-89}{78}=\frac{x-89}{15}+\frac{x-89}{17}\)
=>\(\left(x-89\right)\left(\frac{1}{15}+\frac{1}{17}-\frac{1}{77}-\frac{1}{78}\right)=0\)
=>x-89=0
=>x=89
| X + 24 = 76 x = 76 - 24 x = 52 | X + 38 = 59 X = 59 – 38 X = 21 | X + 62 = 84 X = 84 – 62 X = 22 | X + 22 = 87 X = 87 – 22 X = 65 |
| X + 14 = 25 x = 25 - 14 x = 11 | X + 52 = 78 x = 78 - 52 x = 26 | X + 71 = 94 x = 94 - 71 x = 23 | X + 82 = 86 x = 86 - 82 x = 4 |