Phân tích đa thức thành nhân tử
x2+4x-y+4
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\(x^2-3x-4=x^2+x-4x-4=x\left(x+1\right)-4\left(x+1\right)=\left(x-4\right)\left(x+1\right)\)
\(x^2-4-3\left(x-2\right)=\left(x-2\right)\left(x-1\right)\)
=x²-2²-3(x-2)
=(x+2)(x-2)-3(x-2)
=(x-2)[(x+2)-3]
=(x-2)(x-1)
\(x^2-2xy+y^2+3x-3y-4\)
\(=\left(x-y\right)^2-1+3x-3y-3\)
\(=\left[\left(x-y\right)^2-1^2\right]+\left(3x-3y-3\right)\)
\(=\left[\left(x-y\right)-1\right]\left[\left(x-y\right)+1\right]+3\left(x-y-1\right)\)
\(=\left(x-y-1\right)\left(x-y+1\right)+3\left(x-y-1\right)\)
\(=\left(x-y-1\right)\left[\left(x-y+1\right)+3\right]\)
\(=\left(x-y-1\right)\left(x-y+4\right)\)
\(=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x+3\right)\)
\(x^2-4y^2-2x+1=\left(x-1\right)^2-4y^2=\left(x-1-2y\right)\left(x-1+2y\right)\)
\(x^2-11x+3\\ =\left(x^2-4x+4\right)-7x-1\\ =\left(x-2\right)^2-\left(\sqrt{7x+1}\right)^2\\ =\left(x-2-\sqrt{7x+1}\right)\left(x-2+\sqrt{7x+1}\right)\)
cac cau oi gup minh giai bai toan nay voi:1:viet phan so 7/8 thanh tong cua 3 phan so toi gian co mau so khac nha
2;MOT MANH GIAY HINH CHU NHAT CO CHU VI LA 22/3 DM CHIEU DAI HON CHIEU RONG 1/2D, TINH DIEN H CUA MANH GIAY DO
X^2 + 4x - y + 4
= x^2 + 4x + 4 - y
= x^2 + 2. X . 2 + 2^2 - y
= (x+ 2) ^2 - y