18

tick nHÉ ngỌC hÀ

\(\left[\left(46-32\right)^2-\left(54-42\right)^2\right]\times36-1872\)

\(=\left(14^2-12^2\right)\times36-1872\)

\(=\left(196-144\right)\times36-1872\)

\(=52\times36-1872\)

\(=1872-1872\)

\(=0\)

[(46-32)^2-(54-42)^2]*36-1872

=(14^2-12^2)*36-1872

=(196-144).36-1872

=52.36-1872

=1872-1872

=0

(x-7)^7=(x-7)^8

=>(x-7)^7-(x-7)^8=0

=>(x-7)^7.1-(x-7)^7.(x-7)=0

=>(x-7)^7.[1-(x-7)]=0

\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)=0\end{cases}\Rightarrow\orbr{\begin{cases}x=7;-7\\x=0\end{cases}}}\)

Vậy x={7;-7;0}

1+2^3+3^3-4^2.x=20

=>36-4^2.x=20

=>4^2.x=16=4^2

=>2.x=2

=>x=1

mk vừa làm hoi này cho bạn mà                

C=[(46-32)^2-(54-42)^2]*36-1872 

=(14^2-12^2)*36-1872

=(196-144).36-1872

=52.36-1872

=1872-1872

=0

C=[(46-32)^2-(54-42)^2]*36-1872

=(14^2-12^2)*36-1872

=(196-144).36-1872

=52.36-1872

=1872-1872

=0

\(\left[\left(46-32\right)^2-\left(54-42\right)^2\right]\cdot36-1872\)

\(=\left[\left(14\right)^2-12^2\right]\cdot36-1872\)

\(=\left(196-144\right)\cdot36-1872\)

\(=52\cdot36-1872\)

\(=1872-1872\)

\(=0\)

$\textbf{A}$

$A=[261-(36-31)^3\cdot2]-9\cdot1001$

$=[261-5^3\cdot2]-9009$

$=[261-125\cdot2]-9009$

$=(261-250)-9009$

$=11-9009$

$=-8998.$

$\textbf{B}$

$B=\{315-[(60-41)^2-361]\cdot4217\}+2885$

$=\{315-(19^2-361)\cdot4217\}+2885$

$=\{315-(361-361)\cdot4217\}+2885$

$=315-0+2885$

$=3200.$