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a: \(5\cdot\frac{5}{27}+\frac{7}{23}+0,5\cdot\frac57+\frac{16}{23}+\frac12\)
\(=5\cdot\frac{5}{27}+\left(\frac{7}{23}+\frac{16}{23}\right)+0,5\left(\frac57+1\right)\)
\(=\frac{25}{27}+1+0,5\cdot\frac{12}{7}=\frac{25}{27}+1+\frac67=\frac{25}{27}+\frac{13}{7}=\frac{526}{27\cdot7}=\frac{526}{189}\)
b: \(25\frac16:\frac{-4}{5}-45\frac16:\frac{-4}{5}\)
\(=\left(25+\frac16-45-\frac16\right):\frac{-4}{5}\)
\(=-20\cdot\frac{-5}{4}=25\)
c: \(25\cdot\left(-\frac15\right)^3+\frac15-2\cdot\left(-\frac12\right)^2-\frac12\)
\(=25\cdot\frac{-1}{125}+\frac15-2\cdot\frac14-\frac12\)
\(=-\frac15+\frac15-\frac12-\frac12=-1\)
a: \(-\left(251\cdot3+281\right)+3\cdot251-\left(1-281\right)\)
\(=-251\cdot3-281+3\cdot251-1+281\)
=-1
b: \(\left(0,75-\frac14\right):\left(-5\right)+\frac{1}{15}-\left(-\frac15\right):\left(-3\right)\)
\(=\left(0,75-0,25\right):\left(-5\right)+\frac{1}{15}-\frac{1}{15}\)
=0,5:(-5)
=-1
c: \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac25\)
\(=\frac29:\frac59-\frac75\)
\(=\frac25-\frac75=-\frac55=-1\)
a: \(-\left(251\cdot3+281\right)+3\cdot251-\left(1-281\right)\)
\(=-251\cdot3-281+3\cdot251-1+281\)
=-1
b: \(\left(0,75-\frac14\right):\left(-5\right)+\frac{1}{15}-\left(-\frac15\right):\left(-3\right)\)
\(=\left(0,75-0,25\right):\left(-5\right)+\frac{1}{15}-\frac{1}{15}\)
=0,5:(-5)
=-1
c: \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac25\)
\(=\frac29:\frac59-\frac75\)
\(=\frac25-\frac75=-\frac55=-1\)
a: \(5\cdot\frac{5}{27}+\frac{7}{23}+0,5\cdot\frac57+\frac{16}{23}+\frac12\)
\(=5\cdot\frac{5}{27}+\left(\frac{7}{23}+\frac{16}{23}\right)+0,5\left(\frac57+1\right)\)
\(=\frac{25}{27}+1+0,5\cdot\frac{12}{7}=\frac{25}{27}+1+\frac67=\frac{25}{27}+\frac{13}{7}=\frac{526}{27\cdot7}=\frac{526}{189}\)
b: \(25\frac16:\frac{-4}{5}-45\frac16:\frac{-4}{5}\)
\(=\left(25+\frac16-45-\frac16\right):\frac{-4}{5}\)
\(=-20\cdot\frac{-5}{4}=25\)
c: \(25\cdot\left(-\frac15\right)^3+\frac15-2\cdot\left(-\frac12\right)^2-\frac12\)
\(=25\cdot\frac{-1}{125}+\frac15-2\cdot\frac14-\frac12\)
\(=-\frac15+\frac15-\frac12-\frac12=-1\)
\(A=2019^2-\left(2019-3\right)\left(2019+3\right)\\ A=2019-2019^2-2019\cdot3+2019\cdot3+3^2\\ A=9\)
a) (-124) + 24 = -100
b) 37. 78 + 37. 22
= 37 . ( 78 + 22 )
= 37 . 100
= 3700
= (-2013).2.1007 + 1007.26
= (-4026).1007 + 1007.26
= 1007.(-4026 + 26)
= 1007.(-4000)
= -4028000
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\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}=\frac{3^{28}.5^{10}.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3^3}=\frac{3^{28}.5^{10}.2^{21}}{2^{21}.3^{27}.5^{12}}\)
\(=3.5^{-2}\)