Bài 5: 

a) Ta có: A+P=Q

nên A=Q-P

\(=2x^2+5xy-3y^2-6x^2+7xy-4y^2\)

\(=-4x^2+12xy-7y^2\)

b) Ta có: B-Q=P

nên B=P+Q

\(=6x^2-7xy+4y^2+2x^2+5xy-3y^2\)

\(=8x^2-2xy+y^2\)

Bài 6: 

a) \(P\left(-\dfrac{1}{2}\right)=4\cdot\left(-\dfrac{1}{2}\right)^2-9\cdot\dfrac{-1}{2}=4\cdot\dfrac{1}{4}+\dfrac{9}{2}=1+\dfrac{9}{2}=\dfrac{11}{2}\)

\(Q\left(\dfrac{2}{3}\right)=3\cdot\dfrac{2}{3}+6=2+6=8\)

b) Đặt P(x)=0

\(\Leftrightarrow x\left(4x-9\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{9}{4}\end{matrix}\right.\)

Đặt Q(x)=0

\(\Leftrightarrow3x+6=0\)

hay x=-2

B5:

a)ta có :A+P=Q suy ra A=Q-P

  A=-4x^2+12xy-y^2

b)ta có :B-Q=P suy ra A=Q+P

B=8x^2-2xy+y^2

`63.(-25)+25.(-37)`

`=(-63).25+25.(-37)`

`=25.[(-63)+(-37)]`

`=25.(-100)`

`=-2500`

\(63\times\left(-25\right)+25\times\left(-37\right)\\ =63\times\left(-1\right)\times25+25\times\left(-37\right)\\ =25\times\left(-63-37\right)\\ =25\times\left(-100\right)\\ =-2500\)

Exercise 1:

15. What would you like to do when you grow up?

16. Where you would like to work?

17. What is your dream job, Susan?

18. She would like to look after old people

19. Teaching Maths is my dream job

20. Do you like folk tales?

21. What kinds of stories do you like?

22. How did the story end?

23. Why do you like the story?

* Bài cuối mình làm ở phần bình luận cho bạn nhé!

Bài 15:

\(P=\dfrac{x+y-1}{x\left(x+y\right)}+\dfrac{x-y}{2xy}\cdot\dfrac{xy+y^2+xy-y^2}{x\left(x-y\right)\left(x+y\right)}\)

\(=\dfrac{1}{x}\)

bài nào

mới vào lớp 4 à ?

nghe viết thì có gì khó

\(\left\{{}\begin{matrix}-5x+3y=22\\3x+2y=22\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}-15x+9y=66\\15x+10y=110\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}-y=-44\\3x+2y=22\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y=44\\3x=22-2y=22-2\cdot44=22-88=-66\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=-22\\y=44\end{matrix}\right.\)

\(a-b=2\Leftrightarrow a=b+2\)

\(P=3a^2+b^2+8\\ P=3\left(b+2\right)^2+b^2+8\\ P=3b^2+12b+12+b^2+8\\ P=4b^2+12b+20\\ P=\left(4b^2+12b+9\right)+11\\ P=\left(2b+3\right)^2+11\ge11\forall a;b\)

Dấu "=" xảy ra \(\Leftrightarrow b=\dfrac{-3}{2}\)

Pmin = 11