a: =>2^4x<2^28

=>4x<28

=>x<7

b: =>5^3x+3<5

=>3x+3<1

=>3x<-2

=>x<-2/3

a) \(16^x< 128^4\)

= (24)^x < (27)⁴

= 2^4x < 2²⁸

= 4x < 28

= x < 7 

Vậy \(x=\left\{0;1;2;3;4;5;6;\right\}\)

\(#Tuyết\)

Ta có: \(5^{x}\cdot5^{x+1}\cdot5^{x+2}=10\ldots0:2^{18}\) (18 chữ số 0)

=>\(5^{x+x+1+x+2}=10^{18}:2^{18}=5^{18}\)

=>\(5^{3x+3}=5^{18}\)

=>3x+3=18

=>3x=15

=>x=5

a) \(\left(2x-18\right):\left(-10\right)-34=2\)

\(\Rightarrow\left(2x-18\right):\left(-10\right)=2+34\)

\(\Rightarrow\left(2x-18\right):\left(-10\right)=36\)

\(\Rightarrow2x-18=36\cdot\left(-10\right)\)

\(\Rightarrow2x-18=-360\)

\(\Rightarrow2x=-360+18\)

\(\Rightarrow2x=-342\)

\(\Rightarrow x=-342:2\)

\(\Rightarrow x=-171\) 

b) \(120:\left(5x+20\right)-45=75\)

\(\Rightarrow120:\left(5x+20\right)=75+45\)

\(\Rightarrow120:\left(5x+20\right)=120\)

\(\Rightarrow5x+20=120:120\)

\(\Rightarrow5x+20=1\)

\(\Rightarrow5x=1-20\)

\(\Rightarrow5x=-19\)

\(\Rightarrow x=-\dfrac{19}{5}\)

giúp mik dzới

a: \(\left(5x-10\right):\left(100x^2+18\right)=0\)

=>5x-10=0

=>5x=10

=>x=2

b: (-300):20+5(3x-1)=25

=>-15+5(3x-1)=25

=>5(3x-1)=25+15=40

=>3x-1=8

=>3x=9

=>x=3

c: \(\left(2021x+12\right)^2\left(x+4\right)>0\)

mà \(\left(2021x+12\right)^2>0\forall x\) nguyên

nên x+4>0

=>x>-4

mà x nguyên

nên x∈{-3;-2;-1;...}

<=> \(\frac{5x+1}{9}=\frac{5}{36}+\frac{1}{18}=\frac{7}{36}\)

<=> \(5x+1=\frac{7}{4}\) <=> \(x=\frac{\frac{7}{4}-1}{5}=\frac{3}{20}\)

Vậy x=3/20

1. 

a) ta có :

\(x\cdot2=9\cdot18\)

\(x\cdot2=162\)

\(x=162:2\)

\(x=81\)

b) 5x - x = 10

( 5 - 1 ) x = 10

4x = 10

x = 10 : 4

x = 2.5 

2. 

Ta có :

7y - 2y = 0

( 7 - 2 ) y = 0

5y = 0

y = 0

Vậy y = 0 là nghiệm của đa thức 7y - 2y

sao bạn biết rồi mà còn đang lên