bằng 28 bn nhé

Ta có: A = \(\frac{-2}{11}+\frac{6}{7}+\frac{1}{2}+\frac{-9}{11}+\frac{1}{7}\)
A = \(\left(\frac{-2}{11}+\frac{-9}{11}\right)+\left(\frac{6}{7}+\frac{1}{7}\right)+\frac{1}{2}\)

A = \(-1+1+\frac{1}{2}\)

A = \(\frac{1}{2}\)

B = \(\left(\frac{9}{16}+\frac{8}{27}\right)+\left(1+\frac{7}{16}+\frac{-19}{27}\right)\)

B = \(\frac{9}{16}+\frac{8}{27}+1+\frac{7}{16}-\frac{19}{27}\)

B = \(\left(\frac{9}{16}+\frac{7}{16}\right)+1+\left(\frac{8}{27}-\frac{19}{27}\right)\)

B = \(1+1-\frac{11}{27}\)

B = \(\frac{43}{27}\)

Mà 1/2 < 43/27 (Vì 1/2 < 1; 43/27 > 1)

=> A < B

                       Giải

\(A=\frac{-2}{11}+\frac{6}{7}+\frac{1}{2}+\frac{-9}{11}+\frac{1}{7}\)

\(\Leftrightarrow A=\left(\frac{-2}{11}+\frac{-9}{11}\right)+\left(\frac{6}{7}+\frac{1}{7}\right)+\frac{1}{2}\)

\(\Leftrightarrow A=\frac{-11}{11}+\frac{7}{7}+\frac{1}{2}\)

\(\Leftrightarrow A=-1+1+\frac{1}{2}\)

\(\Leftrightarrow A=\frac{1}{2}< 1\left(1\right)\)

\(B=\left(\frac{9}{16}+\frac{8}{27}\right)+\left(1+\frac{7}{16}+\frac{-19}{27}\right)\)

\(\Leftrightarrow B=\left(\frac{9}{16}+\frac{7}{16}\right)+\left(\frac{8}{27}+\frac{-19}{27}\right)+1\)

\(\Leftrightarrow B=\frac{16}{16}+\frac{-11}{27}+1\)

\(\Leftrightarrow B=1+\frac{-11}{27}+1\)

\(\Leftrightarrow B=2+\frac{-11}{27}\)

\(\Leftrightarrow B=\frac{43}{27}\)\(>1\left(2\right)\)

Từ (1) và (2) suy ra A < B

a) \(3^{29}\)< \(10^{20}\)

b) \(3^{11}\)< \(17^{14}\)

c) \(27^4\): \(9^3\). \(81^4\) >  \(16^3\).\(32^4\)

a: 27^4=(3^3)^4=3^12<3^18

b: 49^4=(7^2)^4=7^8

c: 9^16=(9^2)^8=81^8>27^8

1)

-2/15 < 0 

-10/-11 > 0

nên x < y

2) 

ví dụ 1 < 2 => -1 > -2

ta có 16/29 < 16/27 < 19/27 

suy ra -16/29 > -16/27 > -19/27

a) 2^27=(2^3)^9=8^9

    3^18=(3^2)^9=9^9

    Vì 8^9 bé hơn 9^9 nên 2^27 bé hơn 3^18

Le Thi My Duyen đừng lih tih, trog câu hỏi tương tự CỐ GẮNG LÊN BẠN NHÉ lm lih tih !!

12¹⁸ = 3¹⁸ . 2³⁶

27⁶ . 16⁹ = 3¹⁸ . 3³⁶

=> 12¹⁸ = 27⁶ . 16⁹ 

so sánh 12^18 và 27^16 *16^9

=> 9\(^{10}\)=\(\left(3^2\right)^{10}\)=\(3^{20}\)(1)

\(27^{13}=\left(3^3\right)^{13}\)=\(3^{39}\)(2)

Từ (1) và (2) => \(27^{13}>9^{10}\)

9¹⁰ và 27¹³

9¹⁰ = ( 3² )¹⁰ = 3²⁰

27¹³ = ( 3³ )¹³ = 3³⁹

Vì 20 < 39 nên 9¹⁰ < 27¹³

7 = 3 + 4 = √9 + √16

Do 10 > 9 nên √10 > √9

17 > 16 nên √17 > √16

⇒ √10 + √17 > √9 + √16

Vậy √10 + √17 > 7

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(1/8)²³ = 1/(2³)²³ = 1/2⁶⁹

(1/32)¹⁶ = 1/(2⁵)¹⁶ = 1/2⁸⁰

Do 69 < 80 nên 2⁶⁹ < 2⁸⁰

⇒ 1/2⁶⁹ > 1/2⁸⁰

Vậy (1/8)²³ > (1/³²)¹⁶

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5 = √25

Do 27 > 25 nên √27 > √25

Vậy √27 > 5