Ta thấy A gấp 1²+2²+....+10² 4 lần nên Tổng A gấp 4 lần nó

=> A=385.4=1540

Đặt S = \(1^2+2^2+3^2+\cdots+\) \(10^2\)
Ta có: \(2^2=(2\cdot1)^2=\) \(4\cdot1^2\)
\(4^2=(2\cdot2)^2\) \(=4\cdot2^2\)
...
\(20^2=(2\cdot10)^2=4\cdot10^2\)
=> \(A=4\cdot1^2+4\cdot2^2+4\cdot3^2+\cdots+4\cdot10^2\)
\(A=4\cdot\left(1^2+2^2+3^2+\cdots+10^2\right)=4S\)
\(\Rightarrow4S=4\cdot385\)
\(4S=1540\)
\(\Rightarrow A=1540\)

\(A=\left(12^2+14^2+16^2+18^2+20^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\)

\(A=\left(12^2-1^2\right)+\left(14^2-3^2\right)+\left(16^2-5^2\right)+\left(18^2-7^2\right)+\left(20^2-9^2\right)\)\(A=\left(12+1\right)\left(12-1\right)+\left(14+3\right)\left(14-3\right)+\left(16-5\right)\left(16+5\right)+\left(18-7\right)\left(18+7\right)+\left(20-9\right)\left(20+9\right)\)

\(A=11.13+11.17+11.21+11.25+11.29\)

\(A=11.\left(13+17+21+25+29\right)\)

\(A=11.\left[\left(13+17\right)+\left(21+29\right)+25\right]\)

\(A=11.\left(30+50+25\right)\)

\(A=11.105=1155\)

Ta thấy : 2\(^2\)=4=4.1\(^2\)

  4\(^2\)=16=4.2\(^2\)

   6\(^2\)=36=4.3\(^2\)

     ...

  20\(^2\)=400=4.10\(^2\)

 =>S=2\(^2\)+4\(^2\)+6\(^2\)+...+20\(^2\)=4.(1\(^2\)+2\(^2\)+3\(^2\)+...+10\(^2\))

 = 4.385 

 =1540

  Vậy tổng S = 1540

1155 nhé bn nhưng mk k bt cách làm

Bn nào bt giúp mk vs

\(\left(12^2+14^2+16^2+18^2+20^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\\\Rightarrow\left[\left(2^2.6^2\right)+\left(2^2.7^2\right)....+\left(2^2.10^2\right)\right]-\left(1^2+3^2+...+9^2\right)\\ \Rightarrow2^2.\left(6^2+7^2....+.10^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\\ \Rightarrow4.330-165=1155\)