2u(1+u-v) - v(1-2u+v)

= 2u + 2u^2 - 2uv - v + 2uv - v^2

= 2u + 2u^2 - v - v^2

= 2u(1+u) - v(1+v)

a) 4x^2(5x^3 - 2x + 3)

= 20x^5 - 8x^3 + 12x^2

b) 2u(1 + u - v) - v(1 - 2u + v)

= 2u + 2u^2 - v - v^2

\(B=\dfrac{2u+\sqrt{uv}-3v}{2u-5\sqrt{uv}+3v}\)

\(=\dfrac{2u+3\sqrt{uv}-2\sqrt{uv}-3v}{2u-2\sqrt{uv}-3\sqrt{uv}+3v}\)

\(=\dfrac{\sqrt{u}.\left(2\sqrt{u}+3\sqrt{v}\right)-\sqrt{v}.\left(2\sqrt{u}+3\sqrt{v}\right)}{2\sqrt{u}.\left(\sqrt{u}-\sqrt{v}\right)-3\sqrt{v}.\left(\sqrt{u}-\sqrt{v}\right)}\)

\(=\dfrac{\left(2\sqrt{u}+3\sqrt{v}\right)\left(\sqrt{u}-\sqrt{v}\right)}{\left(\sqrt{u}-\sqrt{v}\right)\left(2\sqrt{u}-3\sqrt{v}\right)}\)

\(=\dfrac{2\sqrt{u}+3\sqrt{v}}{2\sqrt{u}-3\sqrt{v}}\\ =\dfrac{4u+12\sqrt{uv}+9v}{4u-9v}\)

a) 3 u 2 − 8 u + 3 ( u 2 + 1 ) ( u − 1 )                  b) 1 − 4 u 4 ( 4 u + 1 )

vecto a=-2*vecto u+vecto v

=>xa=-2*2+3=-1 và ya=-2*3+(-2)=-8

a, \(x^2+2x\left(y+1\right)+y^2+2y+1=\left(x^2+2xy+y^2\right)+\left(2x+2y\right)+1\)

\(=\left(x+y\right)^2+2\left(x+y\right)+1=\left(x+y+1\right)^2\)

b, \(u^2+v^2+2u+2v+2\left(u+1\right)\left(v+1\right)+2\)

\(=u^2+v^2+2u+2v+2uv+2u+2v+2+2\)

\(=\left(u^2+2uv+v^2\right)+\left(4u+4v\right)+4\)

\(=\left(u+v\right)^2+4\left(u+v\right)+2^2=\left(u+v+2\right)^2\)

1.

a) \(A=x^2+2x\left(y+1\right)+y^2+2y+1\)

\(A=x^2+2x\left(y+1\right)+\left(y+1\right)^2\)

\(A=\left(x+y+1\right)^2\)

b) \(B=u^2+v^2+2u+2v+2\left(u+1\right)\left(v+1\right)+2\)\(B=u^2+v^2+2u+2v+2\left(u+1\right)\left(v+1\right)+1+1\)\(B=\left(u^2+2u+1\right)+2\left(u+1\right)\left(v+1\right)+\left(v^2+2v+1\right)\)\(B=\left(u+1\right)^2+2\left(u+1\right)\left(v+1\right)+\left(v+1\right)^2\)\(B=\left(u+1+v+1\right)^2=\left(u+v+2\right)^2\)

tik mik nha !!!

a.) \(A=x^2+y^2+1+2xy+2x+2y=\left(x+y+1\right)^2.\)

b.) \(B=u^2+v^2+2u+2v+2\left(u+1\right)\left(v+1\right)+2=u^2+2u+1+2\left(u+1\right)\left(v+1\right)+v^2+2v+1\)

\(B=\left(u+1\right)^2+2\left(u+1\right)\left(v+1\right)+\left(v+1\right)^2=\left(u+1+v+1\right)^2=\left(u+v+2\right)^2\)

Giả sử số tự nhiên a chia cho 7 dư 3. CMR a chia cho 7 dư 2

lô

xem lại đề bạn ơi. nếu( u+2v+1)+(2u-2v+2)=3u+3 và chưa chắc cái này đã lẻ

a)

\(1.2x-6=0\\ \Leftrightarrow x=\frac{6}{1.2}=5\)

b)

\(7y-1\cdot\frac{1}{6}=9\\ \Leftrightarrow7y-\frac{1}{6}=9\\ \Leftrightarrow7y=9+\frac{1}{6}=\frac{55}{6}\\ \Rightarrow y=\frac{\frac{55}{6}}{7}=\frac{55}{42}\)

c)

\(-\frac{1}{2u}+3\cdot\frac{1}{2u}+12=2020\\ \Leftrightarrow-\frac{1}{2u}+\frac{3}{2u}+12-2020=0\\ \Leftrightarrow\frac{2}{2u}-2008=0\\ \Leftrightarrow\frac{1}{u}-2008=0\\ \Leftrightarrow\frac{1}{u}=2008\\ \Rightarrow u=\frac{1}{2008}\)

d)

\(1990-0.5v=v\\ \Leftrightarrow1990-0.5v-v=0\\ \Leftrightarrow1990-1.5v=0\\ \Leftrightarrow1.5v=1990\\ \Rightarrow v=\frac{3980}{3}\)

Bạn gõ latex để đề nhìn rõ hơn nhé !...