A=1/2²+1/3²+...+1/9²

Ta có:1/2²>1/2.3,1/3²>1/3.4,...,1/9²>1/9.10

⇒A>1/2.3+1/3.4+...+1/9.10

A>1/2-1/3+1/3-1/4+...+1/9-1/10

A>1/2-1/10

A>2/5(đpcm)

Ta có: A = 1/4 + 1/9 + 1/16 + 1/25 +1/36 + 1/49 + 1/64 + 1/81

Vì 1/2²>1/2.3,1/3²>1/3.4,...,1/9²>1/9.10

=>A>1/2.3+1/3.4+...+1/9.10

=>A>1/2-1/3+1/3-1/4+...+1/9-1/10

=>A>1/2-1/10

=>A>2/5

a: \(A=\left(1-\frac49\right)\left(1-\frac{4}{25}\right)\left(1-\frac{4}{49}\right)\cdot\ldots\cdot\left(1-\frac{4}{\left(2n+1\right)^2}\right)\)

\(=\left(1-\frac23\right)\cdot\left(1-\frac25\right)\cdot\ldots\cdot\left(1-\frac{2}{2n+1}\right)\left(1+\frac23\right)\left(1+\frac25\right)\cdot\ldots\cdot\left(1+\frac{2}{2n+1}\right)\)

\(=\frac13\cdot\frac35\cdot\ldots\cdot\frac{2n-1}{2n+1}\cdot\frac53\cdot\frac75\cdot\ldots\cdot\frac{2n+3}{2n+1}\)

\(=\frac{1}{2n+1}\cdot\frac{2n+3}{3}=\frac{2n+3}{3\left(2n+1\right)}\)

b: Ta có công thức tổng quát:

\(1+\frac{1}{n^2-1}\)

\(=\frac{n^2-1+1}{n^2-1}=\frac{n^2}{n^2-1}=\frac{n\cdot n}{\left(n-1\right)\left(n+1\right)}\)

\(B=\left(1+\frac13\right)\left(1+\frac18\right)\cdot\ldots\left(1+\frac{1}{n^2-1}\right)\)

\(=\left(1+\frac{1}{2^2-1}\right)\left(1+\frac{1}{3^2-1}\right)\cdot\ldots\cdot\left(1+\frac{1}{n^2-1}\right)\)

\(=\frac{2\cdot2}{\left(2-1\right)\left(2+1\right)}\cdot\frac{3\cdot3}{\left(3-1\right)\left(3+1\right)}\cdot\ldots\cdot\frac{n\cdot n}{\left(n-1\right)\left(n+1\right)}\)

\(=\frac{2\cdot3\cdot\ldots\cdot n}{1\cdot2\cdot\ldots\cdot\left(n-1\right)}\cdot\frac{2\cdot3\cdot\ldots\cdot n}{3\cdot4\cdot\ldots\cdot\left(n+1\right)}=\frac{n}{1}\cdot\frac{2}{n+1}=\frac{2n}{n+1}\)

c: Ta có công thức tổng quát:

\(1-\frac{1}{1+2+\cdots+n}\)

\(=1-\frac{1}{\frac{n\left(n+1\right)}{2}}\)

\(=1-\frac{2}{n\left(n+1\right)}=\frac{n\left(n+1\right)-2}{n\left(n+1\right)}=\frac{n^2+n-2}{n\left(n+1\right)}=\frac{\left(n+2\right)\left(n-1\right)}{n\left(n+1\right)}\)

\(C=\left(1-\frac{1}{1+2}\right)\left(1-\frac{1}{1+2+3}\right)\cdot\ldots\cdot\left(1-\frac{1}{1+2+\cdots+n}\right)\)

\(=\frac{\left(2+2\right)\left(2-1\right)}{2\left(2+1\right)}\cdot\frac{\left(3+2\right)\left(3-1\right)}{3\left(3+1\right)}\cdot\ldots\cdot\frac{\left(n+2\right)\left(n-1\right)}{n\left(n+1\right)}\)

\(=\frac{4\cdot5\cdot\ldots\cdot\left(n+2\right)}{3\cdot4\cdot\ldots\cdot\left(n+1\right)}\cdot\frac{1\cdot2\cdot\ldots\cdot\left(n-1\right)}{2\cdot3\cdot\ldots\cdot n}=\frac{n+2}{3}\cdot\frac{1}{n}=\frac{n+2}{3n}\)

S=1/4+1/9+1/16+1/25+1/36+1/49+1/64+1/81=1-1/81=1/81

80/81 là đúng

a; \(\dfrac{1}{4}\) + \(\dfrac{2}{5}\) + \(\dfrac{6}{8}\) + \(\dfrac{9}{15}\) + \(\dfrac{8}{1}\)

= (\(\dfrac{1}{4}\) + \(\dfrac{6}{8}\)) + (\(\dfrac{2}{5}\) + \(\dfrac{9}{15}\)) + \(\dfrac{8}{1}\)

= (\(\dfrac{1}{4}\) + \(\dfrac{3}{4}\)) + (\(\dfrac{2}{5}\) + \(\dfrac{3}{5}\)) + 8

=  1 + 1 + 8

=  2 + 8

= 10

b; \(\dfrac{1}{2}\) + \(\dfrac{2}{4}\) + \(\dfrac{3}{6}\) + \(\dfrac{4}{8}\) + \(\dfrac{5}{10}\) + \(\dfrac{6}{12}\) + \(\dfrac{7}{14}\) + \(\dfrac{8}{16}\) + \(\dfrac{10}{20}\)

=  \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) x (\(\dfrac{2}{2}\) + \(\dfrac{3}{3}\) + \(\dfrac{4}{4}\) + \(\dfrac{5}{5}\)+ \(\dfrac{6}{6}+\dfrac{7}{7}+\dfrac{8}{8}\) + \(\dfrac{10}{10}\))

= \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) x (1 + 1 +1 + 1+ 1+ 1+ 1 +1)

= \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) x 1 x 8

= \(\dfrac{1}{2}\) + \(\)\(\dfrac{1}{2}\) x 8

= \(\dfrac{1}{2}\) + 4

= \(\dfrac{9}{2}\) 

a; \(\dfrac{1}{4}\) + \(\dfrac{2}{5}\) + \(\dfrac{6}{8}\) + \(\dfrac{9}{15}\) + \(\dfrac{8}{1}\)

  = (\(\dfrac{1}{4}\) + \(\dfrac{6}{8}\)) + (\(\dfrac{2}{5}\) + \(\dfrac{9}{15}\)) + 8

= (\(\dfrac{1}{4}\) + \(\dfrac{3}{4}\)) + (\(\dfrac{2}{5}\) + \(\dfrac{3}{5}\)) + 8

= 1 + 1 + 8

= 2 + 8

= 10

b; \(\dfrac{1}{2}\) + \(\dfrac{2}{4}\) + \(\dfrac{3}{6}\) + \(\dfrac{4}{8}\) + \(\dfrac{5}{10}\) + \(\dfrac{6}{12}\) + \(\dfrac{7}{14}\) + \(\dfrac{8}{16}\) + \(\dfrac{9}{18}\) + \(\dfrac{10}{20}\)

= \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\)

= \(\dfrac{1}{2}\) x 10

= 5

bấm máy tính đi bạn, nhanh hơn

ĐÂY LÀ TÍNH NHANH

a: =5*1,4-4*1,5+3*1,3

=7-6+3,9=4,9

b: =1/3*7+3/4*18-2/3*20

=7/3+54/4-40/3

=-11+54/4

=2,5

c: =5/6*17-1/2*16+2/5*15

=85/6-8+6

=85/6-2

=73/6

d: =15*4/5+12*3/4-18*4/9

=12+9-8

=12+1=13

cảm ơn ạ