11;22;33;44;55;66;77;88;99;110

11 22 33 44 55 66 77 88 99 110 nha e

Sửa đề: \(\frac35\times\frac{7}{11}+\frac{6}{11}\times\frac35-0,6\times\frac{2}{11}\)

\(=\frac35\times\left(\frac{7}{11}+\frac{6}{11}-\frac{2}{11}\right)\)

\(=\frac35\times\frac{11}{11}=\frac35\)

= 11x2+11x6+11x11+11x9+11x2

= 11x(2+6+11+9+2)

= 11x30

= 11x3x10

= 33x10

=330

11*2+11*6+11*11+11*9+11*2=11*(2+6+11+9+2)=11*30=330

******nha

Ta có: \(2x^4+11x^3+11x^2-24x-36\)

\(=2x^4+4x^3+7x^3+14x^2-3x^2-6x-18x-36\)

\(=\left(x+2\right)\left(2x^3+7x^2-3x-18\right)\)

\(=\left(x+2\right)\left(2x^3+4x^2+3x^2+6x-9x-18\right)\)

\(=\left(x+2\right)^2\left(2x^2+3x-9\right)\)

\(=\left(x+2\right)^2\cdot\left(2x^2+6x-3x-9\right)\)

\(=\left(x+2\right)^2\cdot\left(x+3\right)\left(2x-3\right)\)

Ta có: \(x^5+7x^4+21x^3+47x^2+80x+60\)

\(=x^5+4x^4+4x^3+3x^4+12x^3+12x^2+5x^3+20x^2+20x+15x^2+60x+60\)

\(=\left(x^2+4x+4\right)\left(x^3+3x^2+5x+15\right)\)

\(=\left(x+2\right)^2\cdot\left(x+3\right)\left(x^2+5\right)\)

Ta có: \(\frac{2x^4+11x^3+11x^2-24x-36}{x^5+7x^4+21x^3+47x^2+80x+60}\)

\(=\frac{\left(x+2\right)^2\cdot\left(x+3\right)\left(2x-3\right)}{\left(x+2\right)^2\cdot\left(x+3\right)\left(x^2+5\right)}=\frac{2x-3}{x^2+5}\)

o ti k hieu

Sửa đề: Tìm GTLN, GTNN của A

ĐKXĐ: x<>1

Đặt A=K

=>\(\frac{-x^2+x-11}{x^2-2x+1}=K\)

=>\(K\left(x^2-2x+1\right)=-x^2+x-11\)

=>\(KX^2-2K\cdot x+K+x^2-x+11=0\)

=>\(x^2\left(K+1\right)+x\left(-2K-1\right)+K+11=0\) (1)

\(\Delta=\left(-2K-1\right)^2-4\left(K+1\right)\left(K+11\right)\)

\(=4K^2+4K+1-4K^2-48K-44=-44K-43\)

Để (1) có nghiệm thì Δ>=0

=>-44K-43>=0

=>-44K>=43

=>K<=-43/44

=>A<=-43/44

=>GTLN của A là -43/44 và A không có giá trị nhỏ nhất

Dấu '=' xảy ra khi \(A=-\frac{43}{44}\)

=>\(\frac{-x^2+x-11}{x^2-2x+1}=\frac{-43}{44}\)

=>\(\frac{x^2-x+11}{x^2-2x+1}=\frac{43}{44}\)

=>\(44\left(x^2-x+11\right)=43\left(x^2-2x+1\right)\)

=>\(44x^2-44x+484=43x^2-86x+43\)

=>\(x^2+42x+441=0\)

=>\(\left(x+21\right)^2=0\)

=>x+21=0

=>x=-21