tính bằng cách thuận tiện nhát6/5-2/5/(5*3/7-3*3/7)
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\(=\dfrac{2}{5}\cdot\dfrac{7}{3}\cdot\dfrac{3}{7}\cdot\dfrac{5}{2}+2020=1+2020=2021\)
a, \(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{3}{5}+\dfrac{3}{5}\right)=1+\dfrac{6}{5}=\dfrac{5+6}{5}=\dfrac{11}{5}\)
`2/5 xx 4/7 + 3/5 xx 4/7`
`= 4/7 xx (2/5 + 3/5)`
`= 4/7 xx 1`
`= 4/7`
\(a,\dfrac{47}{3}:3-\dfrac{37}{3}:3+\dfrac{5}{3}=\dfrac{1}{3}\times\left(\dfrac{47}{3}-\dfrac{37}{3}\right)+\dfrac{5}{3}=\dfrac{10}{9}+\dfrac{5}{3}=\dfrac{10}{9}+\dfrac{15}{9}=\dfrac{25}{9}\)
\(b,\dfrac{3}{5}:\dfrac{7}{9}\times\dfrac{7}{9}:2=\dfrac{27}{35}\times\dfrac{7}{18}=\dfrac{3}{10}\)
\(\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{3}{8}+\dfrac{4}{8}+\dfrac{1}{8}\right)+\left(\dfrac{1}{9}+\dfrac{8}{9}\right)=1+1+1+1=4\)
\(\frac{\frac{6}{5}-\frac{2}{5}}{\frac{5x3}{7}-\frac{3x3}{7}}\)
\(=\frac{\frac{4}{5}}{\frac{5x3-3x3}{7}}\)
\(=\frac{\frac{4}{5}}{\frac{6}{7}}=\frac{4}{5}:\frac{6}{7}\)
\(=\frac{14}{15}\)
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