Cho A= [ m; 2m-1 ] B = ( -1; 5)
tìm m để :
1.B là con của A
2.A là con của B
3. A giao B bằng rỗng
4. A \ B bằng rỗng
5. A hợp B bằng rỗng
Giúp mình với ạ
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I exercise regularly so as to improve my mental health.
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The farmer plants seeds after preparing the agricultural fields.
She completed her vocational training before starting her job.
Despite losing his job, he kept looking for work because of unemployment.
He studies hard when learning about economic principles.
We distribute food to the needy after collecting donations.
She donates money to the poor to support charity.
She learns how to recycle plastic products because of worrying about global warming.
They moved to a new area to escape overpopulation.
She attends workshops after finishing her vocational training.
\(\left\{{}\begin{matrix}V+v=18\\V-v=12\end{matrix}\right.\Leftrightarrow\left(V,v\right)=\left(15,3\right)\)
Đặt \(AB=s\left(km\right)\) thì \(t_{xuôi}=\dfrac{s}{18}\left(h\right),t_{ngược}=\dfrac{s}{12}\left(h\right)\)
Theo đề bài, ta có: \(\dfrac{s}{18}+\dfrac{s}{12}=2,5\Leftrightarrow s=18\left(km\right)\)
Nếu vận tốc dòng nước là \(v\left(km/h\right)\) và vận tốc thực của thuyền là \(V\left(km/h\right)\) thì:
\(\left\{{}\begin{matrix}V+v=18\\V-v=12\end{matrix}\right.\Leftrightarrow\left(V,v\right)=\left(15,3\right)\). Vậy \(v_{nước}=3km/h\)
Có \(t_{xuôi}=\dfrac{s}{18}=\dfrac{18}{18}=1\left(h\right)\), \(t_{ngược}=\dfrac{s}{12}=\dfrac{18}{12}=1,5\left(h\right)\)
Gọi thời gian chuyển động của vật là \(t\)
Khi đó \(s_t=v_0t+\dfrac{1}{2}at^2=0.t+\dfrac{1}{2}.2t^2=t^2\)
\(s_{t-1}=v_0\left(t-1\right)+\dfrac{1}{2}a\left(t-1\right)^2=\left(t-1\right)^2\)
Trong giây cuối vật đi được 25m
\(\Leftrightarrow t^2-\left(t-1\right)^2=25\)
\(\Leftrightarrow2t-1=25\)
\(\Leftrightarrow t=13\)
Vậy thời gian vật chuyển động là 13 giây.
Biện pháp tu từ đạo Ngự qua câu thơ nào trong bài thơ Tây Tiến của tác giả Quang Dũng
1. She had difficulty handing in the report by deadline.
-> She found.......it difficult to hand in the report by deadline.........................................................
2. The bad weather resulted in Mike's late arrival.
-> Due to...the bad weather, Mike arrived late...........................................................
3. It's possible that someone took the things we had bought when we were in the cinema.
-> The things we had bought might.......have been taken when we were in the cinema.................................................
4. Let's make one more tiktok clip now!
-> How........about making one more tiktok clip now?............................................
5. He didn't follow what I said, that was why everything went wrong.
-> I wish......he had followed what I said........................................................................................
6. Having nothing else to do, we decided to go for a walk.
-> Since.......we had nothing else to do, we decided to go for a walk.......................................................................
7. " Nothing will persuade me to apply for that kind of job." She said.
-> She flatly..refused that kind of job......................................................................................
8. The school i studied at last year was better than this one.
-> This school isn't...as good as the school I studied last year.............................................................
9. You must leave now, or you'll miss the bus.
-> You'll miss..the bus unless you leave now.................................................
a.
\(B\subset A\Rightarrow\left\{{}\begin{matrix}m< -1\\2m-1>5\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m< -1\\m>3\end{matrix}\right.\)
\(\Rightarrow\) Không tồn tại m thỏa mãn
b.
\(A\subset B\Rightarrow\left\{{}\begin{matrix}m>-1\\2m-1< 5\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m>-1\\m< 3\end{matrix}\right.\)
\(\Rightarrow-1< m< 3\)
c.
\(A\cap B=\varnothing\Rightarrow\left[{}\begin{matrix}m\ge5\\2m-1\le-1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}m\ge5\\m\le0\end{matrix}\right.\)
d.
\(A\backslash B=\varnothing\Rightarrow A\subset B\Rightarrow-1< m< 3\)
e.
\(B\ne\varnothing\) nên ko tồn tại m để \(A\cap B=\varnothing\)