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Bài 1:
a: \(205-\left\lbrack1200-\left(4^2-2\cdot3\right)^3\right\rbrack:40\)
\(=205-\left\lbrack1200-\left(16-6\right)^3\right\rbrack:\text{40}\)
\(=205-\frac{\left\lbrack1200-10^3\right\rbrack}{40}=205-\frac{1200-1000}{40}=205-\frac{200}{40}\)
=205-5
=200
b: \(177:\left\lbrack2\cdot\left(4^2-9\right)+3^2\left(15-10\right)\right\rbrack\)
\(=177:\left\lbrack2\cdot\left(16-9\right)+9\cdot5\right\rbrack\)
\(=177:\left\lbrack2\cdot7+45\right\rbrack\)
=177:59
=3
c: \(\left\lbrack\left(25-2^2\cdot3\right)+\left(3^2\cdot4+16\right)\right\rbrack:5\)
\(=\frac{\left\lbrack25-4\cdot3+9\cdot4+16\right\rbrack}{5}=\frac{25-12+36+16}{5}=\frac{13+52}{5}\)
\(=\frac{65}{5}\)
=13
d: \(125\left(28+72\right)-25\left(3^2\cdot4+64\right)\)
\(=125\cdot100-25\cdot\left(9\cdot4+64\right)\)
\(=125\cdot100-25\cdot100\)
\(=100\cdot100=10000\)
Bài 2:
a: 135-5(x+4)=35
=>5(x+4)=135-35=100
=>x+4=20
=>x=20-4=16
b: \(25+3\left(x-8\right)=106\)
=>3(x-8)=106-25=81
=>x-8=81:3=27
=>x=27+8=35
c: \(3^2\left(x+4\right)-5^2=5\cdot2^2\)
=>9(x+4)-25=20
=>9(x+4)=45
=>x+4=5
=>x=5-4=1
Bài 3:
4; 45 + 5\(x\) = 10\(^3\): 10
45 + 5\(x\) = 100
5\(x\) = 100 - 45
5\(x\) = 55
\(x\) = 55 : 5
\(x\) = 11
Vậy \(x=11\)
5; 4\(x\) - 20 = 2\(^5\) : 2\(^2\)
4\(x\) - 20 = 2\(^3\)
4\(x\) = 8 + 20
4\(x\) = 28
\(x\) = 28 : 4
\(x=7\)
Vậy \(x=7\)
Bài 4:
1; 82 - (25 + 4\(x^{}\)) = 17
25 + 4\(x\) \(^{}\) = 82 - 17
4\(x^{}\) = 65 - 25
4\(x^{}\) = 40
\(x=40:4\)
\(x\) = 10
Vậy \(x=10\)
2; 71 - (24 + 3\(x\)) = 24
24 + 3\(x\) = 71 - 24
24 + 3\(x\) = 47
3\(x\) = 47 - 24
3\(x\) = 23
\(x\) = 23 : 3
Vậy \(x=\frac{23}{3}\)
3; 145 - (125 + \(x\)) = 12
125 + \(x\) = 145 - 12
125 + \(x\) = 133
\(x\) = 133 - 125
\(x\) = 8
Vậy \(x=8\)
Bài 5:
a: \(B=2009\cdot2011\)
\(=\left(2010-1\right)\left(2010+1\right)\)
\(=2010\cdot2010-1=A-1\)
=>B<A
b: \(B=2019\cdot2021\)
\(=\left(2020-1\right)\left(2020+1\right)\)
\(=2020\cdot2020-1\)
=A-1
=>B<A
c: \(A=234234\cdot233=234\cdot233\cdot1001\)
\(B=233233\cdot234=233\cdot234\cdot1001\)
Do đó: A=B
d: \(A=123\cdot137137=123\cdot137\cdot1001\)
\(B=137\cdot123123=137\cdot123\cdot1001\)
Do đó: A=B
Bài 4:
a: \(391-125<\overline{26x}<184+84\)
=>\(266<\overline{26x}<268\)
=>\(\overline{26x}=267\)
=>x=7
b: \(935+167<\overline{110x}<1240-135\)
=>\(1102<\overline{110x}<1105\)
=>x∈{3;4}
c: \(135\cdot12<\overline{162x}<4869:3\)
=>\(1620<\overline{162x}<1623\)
=>x∈{1;2}
d: \(11268:3<\overline{375x}<235\cdot16\)
=>\(3756<\overline{375x}<3760\)
=>x∈{7;8;9}
Bài 3:
l: x+125=492
=>x=492-125=367
m: 327-x=129
=>x=327-129=198
n: 124+(118-x)=217
=>118-x=217-124=93
=>x=118-93=25
o: 89-(73-x)=20
=>73-x=89-20=69
=>x=73-69=4
p: 198-(x+4)=120
=>x+4=198-120=78
=>x=78-4=74
q: (x+7)-25=23
=>x+7=25+23=48
=>x=48-7=41
r: 140:(x-8)=7
=>x-8=140:7=20
=>x=20+8=28
s: 4(x+41)=400
=>x+41=400:4=100
=>x=100-41=59
t: 4(3x-4)-2=18
=>4(3x-4)=2+18=20
=>3x-4=5
=>3x=9
=>x=3
u: 123-5(x+4)=38
=>5(x+4)=123-38=85
=>x+4=85:5=17
=>x=17-4=13
v: 231-(x-6)=1339:13
=>231-(x-6)=103
=>x-6=231-103=128
=>x=128+6=134
w: (x-36):18+12=14
=>(x-36):18=2
=>\(x-36=2\cdot18=36\)
=>x=36+36=72
Bài 5:
a: \(B=2009\cdot2011\)
\(=\left(2010-1\right)\left(2010+1\right)\)
\(=2010\cdot2010-1=A-1\)
=>B<A
b: \(B=2019\cdot2021\)
\(=\left(2020-1\right)\left(2020+1\right)\)
\(=2020\cdot2020-1\)
=A-1
=>B<A
c: \(A=234234\cdot233=234\cdot233\cdot1001\)
\(B=233233\cdot234=233\cdot234\cdot1001\)
Do đó: A=B
d: \(A=123\cdot137137=123\cdot137\cdot1001\)
\(B=137\cdot123123=137\cdot123\cdot1001\)
Do đó: A=B
Bài 4:
a: \(391-125<\overline{26x}<184+84\)
=>\(266<\overline{26x}<268\)
=>\(\overline{26x}=267\)
=>x=7
b: \(935+167<\overline{110x}<1240-135\)
=>\(1102<\overline{110x}<1105\)
=>x∈{3;4}
c: \(135\cdot12<\overline{162x}<4869:3\)
=>\(1620<\overline{162x}<1623\)
=>x∈{1;2}
d: \(11268:3<\overline{375x}<235\cdot16\)
=>\(3756<\overline{375x}<3760\)
=>x∈{7;8;9}
Bài 3:
l: x+125=492
=>x=492-125=367
m: 327-x=129
=>x=327-129=198
n: 124+(118-x)=217
=>118-x=217-124=93
=>x=118-93=25
o: 89-(73-x)=20
=>73-x=89-20=69
=>x=73-69=4
p: 198-(x+4)=120
=>x+4=198-120=78
=>x=78-4=74
q: (x+7)-25=23
=>x+7=25+23=48
=>x=48-7=41
r: 140:(x-8)=7
=>x-8=140:7=20
=>x=20+8=28
s: 4(x+41)=400
=>x+41=400:4=100
=>x=100-41=59
t: 4(3x-4)-2=18
=>4(3x-4)=2+18=20
=>3x-4=5
=>3x=9
=>x=3
u: 123-5(x+4)=38
=>5(x+4)=123-38=85
=>x+4=85:5=17
=>x=17-4=13
v: 231-(x-6)=1339:13
=>231-(x-6)=103
=>x-6=231-103=128
=>x=128+6=134
w: (x-36):18+12=14
=>(x-36):18=2
=>\(x-36=2\cdot18=36\)
=>x=36+36=72





nó đã cho bn bt các câu bn làm là đúng r nó chỉ thế thôi