18-2x²=16

2x²=18-16

2x²=2

x²=2:2

x²=1

x²=1²=(-1)²

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

(x-2)²=16

(x-2)²=4²=(-4)²

\(\Rightarrow\orbr{\begin{cases}x-2=4\\x-2=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=6\\x=-2\end{cases}}}\)

a. 2x - 16 = 40 + x

=> 2x - x = 40 + 16

=> x = 56

b. 16 - 2x = 40 - 3x

=> -2x + 3x = 40 - 16

=> x = 24

a)

(2x+2).(2x+2)=x+18

=> 4x²+4x+4x+4=x+18

=> 4x²+8x+4=x+18

=> 4x²+8x-x=18-4

=> 4x²-7x=14

=> x(4x-7)=14

Th1

x=14 => x=14

Th2

x-7=14 => x=21

Vậy x=14 hay 21

b)

(2x+8)(2x+8)+4x=16

=> (4x²+16x+16x+64)+4x=16

=> 4x²+32x+64+4x=16

=> 4x²+38x=16-64

=> x(4x+38)=-48

Th1

X=-48 => x=-48

Th2

4x+38=-48 => 4x=10 => x=2,5

Vậy..... 

\(x^2-0,25=0\)

\(\Leftrightarrow x^2-0,5^2=0\)

\(\Leftrightarrow x-0,5=0\)

\(\Leftrightarrow x=0+0,5\)

\(\Leftrightarrow x=0,5\)

b.

\(\dfrac{8}{2x}=2\Leftrightarrow2x=\dfrac{8}{2}\Rightarrow x=4:2=2\)

c.

\(\left(2x-1\right)^3=8\)

\(\Rightarrow\left(2x-1\right)^3=2^3\)

\(\Rightarrow2x-1=2\)

\(\Rightarrow2x=2+1\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\dfrac{3}{2}\)

d.

\(\left(x-2\right)^2=16\)
\(\Rightarrow\left(x-2\right)^2=4^2\)

\(\Rightarrow x-2=4\)

\(\Rightarrow x=4+2\)

\(\Rightarrow x=6\)

Chúc bạn học tốt!!!!

\(x^2-0,25=0\)

\(\Rightarrow x^2=0,25\)

\(\Rightarrow x=0,5\)

b. \(\dfrac{8}{2x}=2\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

c. \(\left(2x-1\right)^3=8\)

\(\left(2x-1\right)^3=2^3\)

\(\Rightarrow2x-1=2\)

\(\Rightarrow x=\dfrac{3}{2}\)

d. \(\left(x-2\right)^2=16\)

\(\left(x-2\right)^2=\pm4^2\)

\(\Rightarrow\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)

1/

=>23+x=0

=>x=-23

2/

=>2x=50

=>x=25

1/ -16 + 23 + x = - 16

<=>-16+23+x+16=0

<=>23+x=0

<=>x=-23

Vậy x=-23

2/ 2x – 35 = 15

<=>2x=50

<=>x=25

Vậy x=25

a) \(2^{4x+1}-8^{x+2}=0\)\(\Leftrightarrow2^{4x+1}-2^{3\left(x+2\right)}=0\)

\(\Leftrightarrow2^{4x+1}-2^{3x+6}=0\)\(\Leftrightarrow2^{4x+1}=2^{3x+6}\)

\(\Leftrightarrow4x+1=3x+6\)\(\Leftrightarrow4x-3x=6-1\)\(\Leftrightarrow x=5\)

Vậy \(x=5\)

b) \(3^2.9^{2x}=27^{x+3}\)\(\Leftrightarrow3^2.3^{2.2x}=3^{3\left(x+3\right)}\)\(\Leftrightarrow3^2.3^{4x}=3^{3x+9}\)

\(\Leftrightarrow3^{2+4x}=3^{3x+9}\)\(\Leftrightarrow2+4x=3x+9\)\(\Leftrightarrow4x-3x=9-2\)\(\Leftrightarrow x=7\)

Vậy \(x=7\)

c) \(8^{2x}.64^2=16^{x+4}\)\(\Leftrightarrow2^{3.2x}.2^{6.2}=2^{4\left(x+4\right)}\)\(\Leftrightarrow2^{6x}.2^{12}=2^{4\left(x+4\right)}\)

\(\Leftrightarrow2^{6x+12}=2^{4x+16}\)\(\Leftrightarrow6x+12=4x+16\)\(\Leftrightarrow6x-4x=16-12\)

\(\Leftrightarrow2x=4\)\(\Leftrightarrow x=2\)

Vậy \(x=2\)

[X-1]^3=125

[x-1]^3=5^3

x-1=5

x=5+1

x=6

Vậy x=6

a) \(\left(x-1\right)^3=125\)

\(\Rightarrow x-1=5\)

\(\Rightarrow x=6\)

b) \(2^{x+2}-2^x=96\)

\(\Rightarrow2^x.2^2-2^x=96\)

\(\Rightarrow2^x.3=96\)

\(\Rightarrow2^x=32=2^5\)

\(\Rightarrow x=5\)

c) \(\left(2x+1\right)^3=343=7^3\)

\(\Rightarrow2x+1=7\)

\(\Rightarrow x=3\)

a)  \(4^{2x-6}=1\)

\(\Rightarrow4^{2x-6}=4^0\)

\(\Rightarrow2x-6=0\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

b) \(2^{x-1}=16\)

\(\Rightarrow2^{x-1}=2^4\)

\(\Rightarrow x-1=4\)

\(\Rightarrow x=5\)

c)  \(5< 5x< 125\)

\(\Rightarrow\frac{5}{5}< \frac{5x}{5}< \frac{125}{5}\)

\(\Rightarrow1< x< 25\)

\(\Rightarrow\left\{x\inℤ|1< x< 25\right\}\)

d) mk không hiểu

|2x| + |-2x| = 16

=> 2x + (-2x) = 16

và 2x + 2x = 16

=> 0 = 16 ( loại ) và 4x = 16 

=> x = 4 

TH1: \(2x-2x=16\Rightarrow0=16\)(loại).

TH2: -2x+2x=16\(\Rightarrow\)16=0   (loại).

TH3: -2x-2x=16  \(\Rightarrow\)-4x=16   \(\Rightarrow\)x=-4  (TM).

TH4: 2x+2x=16  \(\Rightarrow\)4x=16  \(\Rightarrow\)x=4 (TM).

TM là thỏa mãn