\(6^2:43+2.5^2\)

\(=36:43+2.25\)

\(=\frac{36}{43}+50\)

\(=\frac{36}{43}+\frac{2150}{43}\)

\(=\frac{2186}{43}\)

\(6^2:43+2.5^2\)

\(=36:43+2.25\)

\(=\frac{36}{43}+50\)

\(=\frac{36}{43}+\frac{2150}{43}\)

\(=\frac{2186}{43}\)

chúc bạn học tốt

Giúp Mik ik mai nộp oy

\(\frac27\times5\frac14-\frac27\times3\frac14\)

=\(\frac27\times\left(5\frac14-3\frac14\right)\)

=\(\frac27\times\left(\left(5-3\right)+\left(\frac14-\frac15\right)\right)\)

=\(\frac27\times\left(2+0\right)\)

=\(\frac27\times2\)

=\(\frac47\)

dài quá mk lười lắm

em chưa học đâu!5a mà

  5 + (-2) + (18 - 23) + 2

= [(-2) + 2] + [5 + (18 - 23)]

= 0 + [5 + (-5)]

= 0 + 0 = 0

Câu kia đợi mai nha

a, \(5^3-12.\left(x-17\right)=80\)

\(\Rightarrow\) \(125-12.\left(x-17\right)=80\)

\(\Rightarrow\) \(12.\left(x-17\right)=45\)

\(\Rightarrow\) \(x-17=\frac{15}{4}\)

\(\Rightarrow\) \(x=\frac{83}{4}\)

Mà  \(x\in N\) \(\Rightarrow\) Không có giá trị x thỏa mãn.

b, \(\left(10^2+2.6^2\right):\left(43.x\right)=2\)

\(\Rightarrow\) \(\left(100+2.36\right):\left(43.x\right)=2\)

\(\Rightarrow\) \(172:\left(43.x\right)=2\)

\(\Rightarrow\) \(43.x=86\)

\(\Rightarrow\) \(x=2\)

\(M=1+6+6^2+6^3+...+6^{2012}\)

\(M=\left(1+6\right)+6^2.\left(6+1\right)+...+6^{2011}.\left(6+1\right)\)

\(M=43.\left(1+6^2+...+6^{2011}\right)\Rightarrow M\) luôn chia hết cho 43

\(M=1+6+6^2+6^3+....+6^{2012}\)

\(M=\left(1+6+6^2\right)+.....+\left(6^{2010}+6^{2011}+6^{2012}\right)\)

\(M=\left(6^0.1+6^0.6+6^0.6^2\right)+.....+\left(6^{2010}.1+6^{2010}.6+6^{2010}.6^2\right)\)

\(M=1.\left(1+6+6^2\right)+.....+6^{2010}.\left(1+6+6^2\right)\)

\(M=1.43+.....+6^{2010}.43\)

\(M=43.\left(1+....+2^{2010}\right)⋮43\left(đpcm\right)\)

\(\Leftrightarrow-\dfrac{43}{5}\cdot\dfrac{90}{43}< =x< =\dfrac{-13}{5}:\dfrac{7}{5}\)

=>-18<=x<=-13/7

mà x là số nguyên

nên \(x\in\left\{-18;-17;...;-2\right\}\)

\(\frac{6^2}{43}=\frac{36}{43}\)

\(2.5^2=2.25=50\)

Vậy biểu thức có kết quả là:\(\frac{36}{43}+50\)