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Lên chat gpt là xong

Bài 1:

\(\frac{7}{12}+\frac{-8}{15}=\frac{7}{12}-\frac{8}{15}=\frac{35}{60}-\frac{32}{60}=\frac{3}{60}=\frac{1}{20}\)

\(\frac{5}{12}+\frac{-8}{15}=\frac{5}{12}-\frac{8}{15}=\frac{25}{60}-\frac{32}{60}=\frac{-7}{60}\)

Bài 2:

\(a,x-23=-56\)

\(x=-56+23\)

\(x=-33\)

\(b,2x-36=24\)

\(2x=60\)

\(x=30\)

\(c,x-\frac{4}{5}=\frac{3}{2}\)

\(x=\frac{3}{2}+\frac{4}{5}=\frac{23}{10}\)

\(d,x-46=123\)

\(x=123+46=169\)

\(e,2x-25=-45\)

\(2x=-20\)

\(x=-10\)

\(f,x-\frac{2}{3}=-\frac{7}{5}\)

\(x=-\frac{7}{5}+\frac{2}{3}=-\frac{11}{15}\)

=.= hk tốt!!

cảm ơn bạn

1) x-7=-5 => x=-5+7 = 2

2) |x|=3 => x =3 hoặc x = -3

3) |x|+5=8 => |x| = 8-5=3

               => x = 3 hoặc x = -3

4) 8-x = 12 => x = 8-12 = -4

5) 6x-39=5628:28

=> 6x-39=201

=> 6x     = 201+39

=> 6x     = 240

=> x       = 40

6) 8²+(200-x) = 123

=> 200-x  = 123 - 64

=> 200-x  = 59

=> x         = 200-59

=> x          = 141

7) x+10 = -14

=> x     = -14 - 10

=> x     = -24

8) 5x-12 = 48

=> 5x     = 48+12

=> 5x     = 60

=> x       = 12

1) x = 2

2) x = 3 hoặc x = -3

3) x = 3 hoặc x = -3

4) x = -4

5) x = 40

6) x = 141

7) x = -24

8) x = 12 

45 + ( x - 6 ) . 3 = 60 

x-6 = (60-45):3 = 5

x = 5+6 = 11

392 + ( 12 + 3 . x ) . 6 = 404

12+3.x = (404-392):6 =2

3x = 2-12 = -10

x = -10/3

17 . x + x - 4x = 70

x.( 17+1-4) = 70

x .14 = 70

x = 70:14 =5

( 2 . x + 4² ) . 9³ = 2 . 9⁴

2.x +16 . = 2.9⁴ :9³ = 2 .9 = 18

2x = 18-16 = 2

x = 2:2 =1

49 - 5 . ( 7 - x ) = 29 

7-x = (49-29) :5 = 4

x = 7-4 =3

12 . x + 19 . x - 123 = 280

x . ( 12+19) = 280-123 =157

x . 31 = 157

x = 157:31 = 157/31

Bài 1 :

a, Ta có : \(\left(-123\right)+\left|-13\right|+\left(-7\right)\)

= \(\left(-123\right)+13+\left(-7\right)=\left(-117\right)\)

b, Ta có : \(\left|-10\right|+\left|45\right|+\left(-\left|-455\right|\right)+\left|-750\right|\)

= \(10+45-455+750=350\)

c, Ta có : \(-\left|-33\right|+\left(-15\right)+20-\left|45-40\right|-57\)

= \(\left(-33\right)+\left(-15\right)+20-5-57=-90\)

Lời giải:
$A=[(-1)+5]+[(-9)+13]+....+[(-41)+45]$

$=4+4+4+....+4$
Số lần xuất hiện của 4 là: $[(45-1):4+1]:2=6$

$A=4\times 6=24$

-------------------------

$B=(1-2-3+4)+(5-6-7+8)+....+(997-998-999+1000)$
$=0+0+.....+0=0$

sao nó .....

phải ns ntn nhỉ dễ dã man

dễ thì bạn làm đi

49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\))

= 49\(\frac{8}{23}\) - 5\(\frac{7}{32}\) - 14\(\frac{8}{23}\)

= (49\(\frac{8}{23}\) - 14\(\frac{8}{23}\)) - 5\(\frac{7}{32}\)

= 35 - 5 - \(\frac{7}{32}\)

= 30 - \(\frac{7}{32}\)

= \(\frac{960}{32}\) - \(\frac{7}{32}\)

= 953/32

Câu b:

71\(\frac{38}{45}\) - (43\(\frac{8}{45}\) - 1\(\frac{17}{57}\))

= 71\(\frac{38}{45}\) - 43\(\frac{8}{45}\) - 1\(\frac{17}{57}\)

= 28\(\frac{30}{45}\) - 1\(\frac{17}{57}\)

= 28\(\frac23\) - 1\(\frac{17}{57}\)

= \(\frac{86}{3}\) - \(\frac{74}{57}\)

= \(\frac{1634}{57}\) - \(\frac{74}{57}\)

= \(\frac{1560}{57}\)

= \(\frac{520}{19}\)