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P = \(\frac{2}{3}.\frac{4}{5}.\frac{6}{7}...\frac{98}{99}\). CMR: P \(< \frac{1}{7}\)
Đề bài đây à
A, Câu này thì tớ chưa rõ lắm
B, 47 - [ ( 45 . 2^4 - 5^2 . 12 ) : 14] =
= 47 - [ ( 45. 16 - 25 . 12 ) : 14]
= 47 - [ ( 720 - 300 ) : 14]
= 47 - [ 420 : 14 ]
= 47 - 30
= 17
Chúc bạn học giỏi! :^
#Coffee
A=50-[(50-2^3.5):2+3] B=47-[(45.2^4-5^2.12):14]
=50-[(50-40):2+3] =47-[(45.16-25.12):14]
=50-(10:2+3) =47-[(720-300):14]
=50-(5+3) =47-[420:14]
=50-8=42 =47-30=17
k tcik
a)\(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
\(5^{2x-3}-2\cdot25=75\)
\(5^{2x-3}-50=75\)
\(5^{2x-3}=125\)
\(125=5^3\)
\(5^3=5^{\left(3+3\right):2}=5^3\Rightarrow x=3\)
Vậy \(x=3\)
b)\(\frac{2}{9}\cdot\left(5x+1\right):2-\frac{1}{18}=\frac{5}{36}\)
\(=\frac{2}{9}\cdot\left(5x+1\right):2=\frac{5}{36}+\frac{1}{18}\)
\(=\frac{2}{9}\cdot\left(5x+1\right)=\frac{7}{36}\cdot2\)
\(5x+1=\frac{7}{18}:\frac{2}{9}\)
\(x=\left(\frac{7}{4}-1\right):5=\frac{3}{20}\)
\(\Rightarrow x=\frac{3}{20}\)
a, \(5^{2x-3}-2.5^2=5^2.3\)
\(\Leftrightarrow5^{2x-3}-2.25=25.3\)
\(\Leftrightarrow5^{2x-3}-50=75\)
\(\Leftrightarrow5^{2x-3}=125\)
\(\Leftrightarrow5^{2x-3}=5^3\)
\(\Leftrightarrow2x-3=3\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
b, \(\frac{2}{9}.\left(5x+1\right):2-\frac{1}{18}=\frac{5}{36}\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right):2=\frac{7}{36}\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right)=\frac{7}{36}.2\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right)=\frac{7}{18}\)
\(\Leftrightarrow5x+1=\frac{7}{18}:\frac{2}{9}\)
\(\Leftrightarrow5x+1=\frac{7}{18}.\frac{9}{2}\)
\(\Leftrightarrow5x+1=\frac{7}{4}\)
\(\Leftrightarrow5x=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}:5=\frac{3}{4}.\frac{1}{5}=\frac{3}{20}\)
157*(17-7)=......
(-37)*86 - (-37)*76=(-37)*(86-76)=.......
1975*(-115+15)=....
199*[(15-17)-(-17+5)]=........
17*[-84+(-16)]=.......
= 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/37 - 1/39
= 1/3 - 1/39
= 13/39 - 1/39
= 12/39
= 4/13
cho mình xin tick !
2/3.5 + 2/5.7 + ...+ 2/37.39
= 1/3 - 1/5 + 1/5 - 1/7 + 1/37 - 1/39
= 1/3 - 1/39
= 4/13
\(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\cdots+\frac{2}{37\cdot39}\)
\(=\frac13-\frac15+\frac15-\frac17+\cdots+\frac{1}{37}-\frac{1}{39}\)
\(=\frac13-\frac{1}{39}=\frac{12}{39}=\frac{4}{13}\)