Bạn có thể làm được các nốt âm nhạc không

18 : 8 - 9

= \(\frac94\) - 9

= \(\frac94-\frac{36}{4}\)

\(=-\frac{27}{4}\)

567 : 678 = \(\frac{567}{678}\)

\(\frac{3^2}{5.14}+\frac{3^2}{7.18}+\frac{3^2}{99.22}+\frac{3^2}{11.26}+\frac{3^2}{13.30}\)

\(=\frac{9}{5.14}+\frac{9}{7.18}+\frac{9}{9.22}+\frac{9}{11.26}+\frac{9}{13.30}\)

\(=\frac{9}{2}.\left(\frac{4}{10.14}+\frac{4}{14.18}+\frac{4}{18.22}+\frac{4}{22.26}+\frac{4}{26.30}\right)\)

\(=\frac{9}{2}.\left(\frac{1}{10}-\frac{1}{14}+\frac{1}{14}-\frac{1}{18}+...+\frac{1}{26}-\frac{1}{30}\right)\)

\(=\frac{9}{2}.\left(\frac{1}{10}-\frac{1}{30}\right)\)

\(=\frac{9}{2}.\left(\frac{3}{30}-\frac{1}{30}\right)\)

\(=\frac{9}{2}.\frac{2}{30}\)

\(=\frac{9}{30}\)

\(=\frac{3}{10}\)

Chúc bạn học tốt !!! 

A =\(\frac{3^2}{5.14}+\frac{3^2}{7.18}+\frac{3^2}{9.22}+\frac{3^2}{11.26}+\frac{3^2}{13.30}\)

A =\(3^2.\left(\frac{1}{5.14}+\frac{1}{7.18}+\frac{1}{9.22}+\frac{1}{11.26}+\frac{1}{13.30}\right)\)

A =\(9.\frac{1}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.15}\right)\)

A =\(\frac{9}{4}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\right)\)

A =\(\frac{9}{4}.\left(\frac{1}{5}-\frac{1}{15}\right)\)

A =\(\frac{9}{4}.\frac{2}{15}\)

A =\(\frac{3}{10}\)

1 a/ B = 2016 . 2016 - 2014 . 2018

           =\(2016^2-\left(2016-2\right).\left(2016+2\right)\)

           = \(2016^2-2016.\left(-2+2\right)\\\)

           =\(2016^2-2016.0 \)

           = \(2016^2\)

1: Tính
a) B = 2016 x 2016 - 2014 x 2018
       = (2016 x 2016) - (2014 x 2018)
       =  4064256 - 4064252
       = 4
       b) 327 x 412 + 400 / 328 x 412 -12
          = (327 x 412 + 400) / ( 328 x 412 - 12)
           = 135124 / 135124
           = 1

c) ( 1234 x 567 - 667 ) : ( 567 + 1234 x 5)
   = (1234 x 567 - 667) : (567 + 1234 x 566) 
= [1234 x 566 + (1234 - 667)] / (1234 x 566 + 567) 
= (1234 x 566 + 567) / (1234 x 566 + 567)
= 1
để thiếu bạn ơi
 

\(A=\frac{1}{1.2.3}+\frac{1}{3.2.5}+\frac{1}{5.2.7}+\frac{1}{7.2.9}+...+\frac{1}{41.2.43}\)

\(4A=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{41.43}\)

\(4A=\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+\frac{9-7}{7.9}+...+\frac{43-41}{41.43}\)

\(4A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{41}-\frac{1}{43}=1-\frac{1}{43}\)

\(A=\frac{1}{4}-\frac{1}{172}=\frac{42}{172}=\frac{21}{86}\)

cùng 1 câu hỏi sao đang chi nhiều vậy bn???

Mình lỡ tay ấy mà

\(\dfrac{5.14^{15}.9^9-4.3^{20}.8^9}{5.2^9-7.2^{29}.27^6}\)

\(=\dfrac{5.2^{30}.3^{18}-2^2.2^{27}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\dfrac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\dfrac{2^{28}.3^{18}.2}{2^{28}.3^{18}}=2\)