ai trả lời được thì tôi k đúng cho :))

thì kệ

b./ \(\Leftrightarrow\frac{x+1}{2009}+1+\frac{x+2}{2008}+1+\frac{x+3}{2007}+1=\frac{x+10}{2000}+1+\frac{x+11}{1999}+1+\frac{x+12}{1998}+1.\)

\(\Leftrightarrow\frac{x+2010}{2009}+\frac{x+2010}{2008}+\frac{x+2010}{2007}-\frac{x+2010}{2000}-\frac{x+2010}{1999}-\frac{x+2010}{1998}=0\)

\(\Leftrightarrow\left(x+2010\right)\left(\frac{1}{2009}+\frac{1}{2008}+\frac{1}{2007}-\frac{1}{2000}-\frac{1}{1999}-\frac{1}{1998}\right)=0\)(b)

Mà \(\frac{1}{2009}+\frac{1}{2008}+\frac{1}{2007}-\frac{1}{2000}-\frac{1}{1999}-\frac{1}{1998}< 0\)

(b) \(\Leftrightarrow x+2010=0\Leftrightarrow x=-2010\)

a./

\(\Leftrightarrow\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}-\frac{x+1}{5}-\frac{x+1}{6}=0.\)

\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)=0\)(a)

Mà \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}>0\)

(a) \(\Leftrightarrow x+1=0\Leftrightarrow x=-1\)

\(a,3^4:3^x=3^3\)

\(3^{4-x}=3^3\)

=> 4 -x = 3

=> x = 1

Nguyễn Tấn Tài bn làm hết nhé

Đặt là a, b nhá 

\(a)\) \(7^{x-1}-2.7^{100}=5.7^{100}\)

\(\Leftrightarrow\)\(7^{x-1}=5.7^{100}+2.7^{100}\)

\(\Leftrightarrow\)\(7^{x-1}=7^{100}\left(5+2\right)\)

\(\Leftrightarrow\)\(7^{x-1}=7^{100}.7\)

\(\Leftrightarrow\)\(7^{x-1}=7^{101}\)

\(\Leftrightarrow\)\(x-1=101\)

\(\Leftrightarrow\)\(x=101+1\)

\(\Leftrightarrow\)\(x=102\)

Vậy \(x=102\)

\(b)\) \(5^{x-4}=25\)

\(\Leftrightarrow\)\(5^{x-4}=5^2\)

\(\Leftrightarrow\)\(x-4=2\)

\(\Leftrightarrow\)\(x=2+4\)

\(\Leftrightarrow\)\(x=6\)

Vậy \(x=6\)

Chúc bạn học tốt ~ 

\(7^{x-1}-2.7^{100}=5.7^{100}\)

\(\Rightarrow7^{x-1}=5.7^{100}+2.7^{100}\)

\(\Rightarrow7^{x-1}=7.7^{100}\)

\(\Rightarrow7^{x-1}=49^{100}\)

\(\Rightarrow7^{x-1}=7^{2^{100}}\)

\(\Rightarrow7^{x-1}=7^{200}\)

\(\Rightarrow x=201\)

Vậy x = 201

\(5^{x-4}=25\)

\(\Rightarrow5^{x-4}=5^2\)

\(\Rightarrow x=6\)

Vậy x = 6

\(\left(2^{100}.5+2^{100}.3\right):2^{101}\)

\(=2^{100}.8:2^{101}\)

\(=2^{100}.2^3:2^{101}\)

\(=2^{103}:2^{101}\)

\(=2^2\)

\(=4\)

\(3^5:3^3+2^2.2^3-14\)

\(=3^2+2^6-14\)

\(=9+64-14\)

\(=59\)

A = \(\frac{2^{13}.5^2.2^6.3^4}{8.2^{18}.81.5}\)

   = \(\frac{2^{19}.5^2.3^4}{2^3.2^{18}.3^4.5}\)

   = \(\frac{2^{19}.5^2.3^4}{2^{21}.3^4.5}\) 

   = \(\frac{5}{2^2}\) = \(\frac{5}{4}\)

\(A=\frac{2^{13}.5^2.2^6.3^4}{8.2^{18}.81.5}\)

\(A=\frac{2^{19}.5^2.3^4}{2^{21}.3^4.5}=\frac{5}{2^3}=\frac{5}{8}\)

a) \(x+\left(-7\right)=-20\)

\(\Rightarrow x=-20+7\)

\(\Rightarrow x=-13\)

Vậy \(x=-13\)

b) \(8-x=-12\)

\(\Rightarrow x=8-\left(-12\right)\)

\(\Rightarrow x=20\)

Vậy \(x=20\)

c) \(|x|-7=-6\)

\(\Rightarrow|x|=-6+7\)

\(\Rightarrow|x|=1\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

Vậy \(x\in\left\{1;-1\right\}\)

d) \(5^2.2^2-7.|x|=65\)

\(\Rightarrow\left(5.2\right)^2-7.|x|=65\)

\(\Rightarrow10^2-7.|x|=65\)

\(\Rightarrow100-7.|x|=65\)

\(\Rightarrow7.|x|=35\)

\(\Rightarrow|x|=5\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)

Vậy \(x\in\left\{5;-5\right\}\)

e) \(37-3.|x|=2^3-4\)

\(\Rightarrow37-3.|x|=8-4\)

\(\Rightarrow37-3.|x|=4\)

\(\Rightarrow3.|x|=33\)

\(\Rightarrow|x|=11\)

\(\Rightarrow\orbr{\begin{cases}x=11\\x=-11\end{cases}}\)

Vậy \(x\in\left\{11;-11\right\}\)

f) \(|x|+|-5|=|-37|\)

\(\Rightarrow|x|+5=37\)

\(\Rightarrow|x|=32\)

\(\Rightarrow\orbr{\begin{cases}x=32\\x=-32\end{cases}}\)

Vậy \(x\in\left\{32;-32\right\}\)

g)\(5.|x+9|=40\)

\(\Rightarrow|x+9|=8\)

\(\Rightarrow\orbr{\begin{cases}x+9=8\\x+9=-8\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\x=-17\end{cases}}\)

Vậy \(x\in\left\{-1;-17\right\}\)

h) \(-\frac{5}{6}+\frac{8}{3}+\frac{-29}{6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)

\(\Rightarrow\frac{-5}{6}+\frac{16}{6}+\frac{-29}{6}\le x\le\frac{-1}{2}+\frac{4}{2}+\frac{5}{2}\)

\(\Rightarrow-3\le x\le4\)

Vậy \(-3\le x\le4\)

câu a

x+(-7)=-20

x=-20-(-7)

x=-13

4x-(7+5x)=15+(-29).                      b,x/11=x+4/33

4x-7-5x=-14.                                    33x=11(x+4)

4x-5x=14+7.                                     33x=11x+44

-x=21.                                               33x-11x=44

x=-21                                                22x=44

                                                         x=44:22=2

2.     a,   \(\frac{3.7.11}{33.9}\)

=         \(\frac{3.7.11}{3.11.3.3}\)

=          \(\frac{7}{9}\)

b,             \(\frac{5^3.2^4}{4.10^2.11}\)

=              \(\frac{5^3.2^4}{2^2.5^2.2^2.11}\)

=              \(\frac{5.1}{11}=\frac{5}{11}\)