a) Ta có: x + 15 \(⋮\)x + 8

<=> (x + 8) + 7 \(⋮\)x + 8

Do x + 8 \(⋮\)x + 8 => 7 \(⋮\)x + 8

=> x + 8 \(\in\)Ư(7) = {1; -1; 7; -7}

=> x \(\in\){-7; -9; -1; -15}

Vậy ...

b) Ta có: 2x + 14 = 2(x + 7) \(⋮\)x + 7 

=> mọi x thì 2x + 14 \(⋮\)x + 7

2^x=64

x=6

x¹⁵=x³¹<=>x={0;1} kkk tui nha

a) 4x - 15 = - 75 - x

<=> 4x + x = -75 + 15

<=> 5x = -60

<=> x = -12

b) 72 - 3x = 5x + 8

<=> -3x -5x = 8 - 72

<=> -8x = -64

<=> x = 8

d) 3 . | x - 7 | = 21

<=> | x - 7 | = 7

\(\Leftrightarrow\orbr{\begin{cases}x-7=7\\x-7=-7\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=14\\x=0\end{cases}}\)

\(-7\left|x+3\right|=-49\) 

\(\Leftrightarrow\left|x+3\right|=7\)

\(\Leftrightarrow\orbr{\begin{cases}x+3=7\\x+3=-7\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-10\end{cases}}\)

\(B=\left(1+\dfrac{1}{8}\right)\left(1+\dfrac{1}{15}\right)\left(1+\dfrac{1}{24}\right).....\left(1+\dfrac{1}{440}\right)\left(1+\dfrac{1}{483}\right)\)

\(B=\dfrac{9}{8}.\dfrac{16}{15}.\dfrac{25}{24}.....\dfrac{441}{440}.\dfrac{484}{483}\)

\(B=\dfrac{9.16.25.....441.484}{8.15.24.....440.483}\)

\(B=\dfrac{3.3.4.4.5.5.....21.21.22.22}{2.4.3.5.4.6.....20.22.21.23}\)

\(B=\dfrac{3.4.5.....21.22}{2.3.4.....20.21}.\dfrac{3.4.5.....21.22}{4.5.6.....22.23}\)

\(B=11.\dfrac{3}{23}=\dfrac{33}{23}\)

B = \(\dfrac{4}{3}.\dfrac{9}{8}.\dfrac{16}{15}.\dfrac{25}{24}...\dfrac{121}{120}.\dfrac{144}{143}\)

B = \(\dfrac{4.9.16.25...121.144}{3.8.15.24....120.143}\)

B = \(\dfrac{2.2.3.3.4.4.5.5...11.11.12.12}{1.3.2.4.3.5.4.6...10.12.11.13}\)

B = \(\dfrac{2.3.4.5...11.12}{1.2.3.4.5...10.11}.\dfrac{2.3.4.5...11.12}{3.4.5.6.7...12.13}\)

B = 12 . \(\dfrac{2}{13}\)

B = \(\dfrac{24}{13}\)

|x + 8| = 10

=> x + 8 = 10 hoặc  x + 8 = -10

=> x = 2 hoặc x = -18

vậy_

\(x+15\%x=115\)

\(\Leftrightarrow x+\frac{15}{100}x=115\)

\(\Leftrightarrow x+\frac{3}{20}x=115\)

\(\Leftrightarrow x\left(1+\frac{3}{20}\right)=115\)

\(\Leftrightarrow x\left(\frac{20}{20}+\frac{3}{20}\right)=115\)

\(\Leftrightarrow\frac{23}{20}x=115\)

\(\Leftrightarrow x=115\div\frac{23}{20}\)

\(\Leftrightarrow x=115\times\frac{20}{23}\)

\(\Leftrightarrow x=\frac{2300}{23}=100\)

\(\left|-2-x\right|=-15+\left(-37\right)-\left(37+15-8\right)\)

\(\left|-2-x\right|=\left(-52\right)-\left(52-8\right)\)

\(\left|-2-x\right|=\left(-52\right)-44\)

\(\left|-2-x\right|=-96\)

Vì \(\left|a\right|\ge0\)mà \(-96< 0\)nên \(x\in\varnothing\)

Vậy x không có giá trị thỏa mãn đề bài

|-2 - x | = - 15 + (-37) - (37 + 15 - 8)

|-2 - x | = - 15 + (-37) - (52 - 8 )

|-2 - x | = - 15 + (-37) - 46

|-2 - x | = - 98

mà |-2 - x | > hoặc = 0 vói mọi x thuộc z

vậy x thuộc rỗng

mk ko bt viết kí hiệu

\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}.\)

\(\Rightarrow x.\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)=\frac{8}{9}\)

\(\Rightarrow x.\frac{23}{52}=\frac{8}{9}\)

\(\Rightarrow x=\frac{426}{207}\)

Study well 

\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}\)

<=> x\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{x}{39}\right)=\frac{8}{9}\)

<=> x = \(\frac{8}{9}:\frac{23}{52}\)

<=> x = \(\frac{416}{207}\)

                                                 \(\frac{3}{4}x\frac{8}{9}x\frac{15}{16}x...x\frac{9999}{10000}\)

                                             \(=\frac{1.3}{2^2}.\frac{2.4}{3^2}.\frac{3.5}{4^2}.....\frac{99.101}{100^2}\)

                                              \(=\frac{1.3.2.4.3.5.....99.101}{2.2.3.3.4.4.....100.100}\)

                                                  \(=\frac{1.2.3.....99}{2.3.4.....100}.\frac{3.4.5.....101}{2.3.4.....100}\)

                                                    \(=\frac{1}{100}.\frac{101}{2}=\frac{101}{200}\)

                                              Ủng hộ mk nha,chúc bn học tốt!!!

bn ơi mjk chưa học số có mũ bn giúp mjk nốt nha

mình không biết làm

b, \(\dfrac{x-3}{4}=\dfrac{15}{20}\)

<=> \(\dfrac{x-3}{4}=\dfrac{3}{4}\)

=> x-3=3

<=> x=6

Vậy x=6

\(a,\dfrac{x}{15}=\dfrac{4}{y}=\dfrac{-2}{5}\)

* \(\dfrac{x}{15}=\dfrac{-2}{5}\)

\(\Rightarrow\dfrac{x}{15}=\dfrac{-6}{15}\)

\(\Rightarrow x=-6\)

*\(\dfrac{4}{y}=\dfrac{-2}{5}\)

\(\Rightarrow\dfrac{4}{y}=\dfrac{4}{-10}\)

\(\Rightarrow y=-10\)

Vậy x = - 6 ; y = - 10

\(b,\dfrac{x-3}{4}=\dfrac{15}{20}\)

=> ( x - 3 ) . 20 = 4. 15

=> 20x - 60 = 60

=> 20x = 60 + 60

=> 20x = 120

=> x = 120 : 20

=> x = 6

Vậy x = 6

\(c,\dfrac{-5}{9}+\dfrac{-8}{15}+\dfrac{22}{-9}+\dfrac{-7}{15}< x\le\dfrac{-1}{3}+\dfrac{-1}{4}+\dfrac{-5}{12}\)

\(\Rightarrow\dfrac{-5}{9}+\dfrac{-8}{15}+\dfrac{-22}{9}+\dfrac{-7}{15}< x\le\dfrac{-4}{12}+\dfrac{-3}{12}+\dfrac{-5}{12}\)

\(\Rightarrow\left(\dfrac{-5}{9}+\dfrac{-22}{9}\right)+\left(\dfrac{-8}{15}+\dfrac{-7}{15}\right)< x\le-1\)

\(\Rightarrow-3+\left(-1\right)< x\le-1\)

\(\Rightarrow-4< x\le-1\)

\(\Rightarrow x=-3;-2;-1\)