64 . 4^x = 16^8

=> 4^3 . 4^x = (4^2) ^8

=> 4^3 . 4^x = 4^16

=>       4^x    = 4^16 : 4^ 3

=>         4^x   = 4^ 13

=>             x    =  13

      9^x = 27^4

=> ( 3^2) ^ x = ( 3^3 ) 4

=>3^2.x    = 3^ 12

=>   2.x    = 12

=>     x     = 12 : 2

=>     x      =  6

Câu 1 = 4^13

Câu 2 = 9^6

Câu cuối mik không làm được ;)

k mik nhé

a) \(3^x=81\)

\(3^x=3^4\)

\(\Rightarrow x=4\)

b) \(2^x.16=128\)

\(2^x=128:16\)

\(2^x=8\)

\(2^x=2^3\)

\(\Rightarrow x=3\)

c) \(3^x:9=27\)

\(3^x=27.9\)

\(3^x=243\)

\(3^x=3^5\)

\(\Rightarrow x=5\)

d) \(x^4=x\)

\(\Rightarrow x=0\)hoac \(\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

e) \(\left(2x+1\right)^3=27\)

\(\left(2x+1\right)^3=3^3\)

\(\Rightarrow2x+1=3\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

f) \(\left(x-2\right)^2=\left(x-2\right)^4\)

\(\left(x-2\right)^2-\left(x-2\right)^4=0\)

\(\left(x-2\right)^2-\left(x-2\right)^2.\left(x-2\right)^2=0\)

\(\left(x-2\right)^2\left[1-\left(x-2\right)^2\right]=0\)

\(\left(x-2\right)^2\left(1-x+2\right)\left(1+x-2\right)=0\)

\(\Rightarrow\left(x-2\right)^2=0\)hoac \(\orbr{\begin{cases}3-x=0\\x-1=0\end{cases}}\)

\(\Rightarrow x-2=0\)hoac \(\orbr{\begin{cases}x=3\\x=1\end{cases}}\)

\(\Rightarrow x=2\)hoac \(\orbr{\begin{cases}x=3\\x=1\end{cases}}\)

a) \(3^x=81\Leftrightarrow3^x=3^4\Rightarrow x=4\)

b)\(2^x\times16=128\Leftrightarrow2^x=8\Leftrightarrow2^x=2^3\Rightarrow x=3\)

c) \(3^x\div9=27\Leftrightarrow3^x\div3^2=3^3\Rightarrow x=5\)

d) \(x^4=x\Leftrightarrow x=1\)

e) \(\left(2x+1\right)^3=27\Leftrightarrow\left(2x+1\right)^3=3^3\Rightarrow2x+1=3 \)

\(\Rightarrow2x=3+1\Leftrightarrow2x=4\Rightarrow x=2\)

F) 

#)Giải :

\(\frac{1}{9}.3^4.3^n=3^7\)

\(\frac{1}{9}.81.3^n=3^7\)

\(9.3^n=3^7\)

\(3^2.3^n=3^7\)

\(\Rightarrow2+n=7\)

\(\Rightarrow n=5\)

       #~Will~be~Pens~#

#)Giải :

\(\frac{1}{9}.27^n=3^n\)

\(\Leftrightarrow\frac{1}{9}=\frac{3^n}{27^n}\)

\(\Leftrightarrow\frac{1}{9}=\left(\frac{1}{9}\right)^n\)

\(\Leftrightarrow n=1\)

         #~Will~be~Pens~#

a> =>x+1=3

=>x=2

 vậy x=2

b> =>3^2x-1=3³

=>2x-1=3

=>2x=4

=>x=2

  vậy x=2

C> =>2^2+x=2⁷

=>2+x=7

=>x=5

 vậy x=5

D> =>3^3x-2=3⁴

=>3x-2=4

=>3x=6

=>x=2

 vậy x=2

a) 6^x+1 = 6³ <=> x + 1 = 3 <=> x = 2

b) 3^2x-1 = 27 <=> 3^2x-1 = 3³ <=> 2x-1 = 3 <=> 2x = 4 <=> x = 2

c)4 . 2^x = 128 <=> 2^x = 128 : 4 <=> 2^x = 32 <=> 2^x = 2⁵ <=> x = 5

d) 3^3x-2 = 81 <=> 3^3x-2 = 3⁴ <=> 3x - 2 = 4 <=> 3x = 6 <=> x = 2

\(a )\)

\(\left[\left(\dfrac{1}{9}:\dfrac{8}{27}\right):\dfrac{-1}{3}\right]:\dfrac{81}{128}\)

\(=\left[\left(\dfrac{3}{27}:\dfrac{8}{27}\right):\dfrac{-1}{3}\right]:\dfrac{81}{128}\)

\(=\left(\dfrac{3}{8}:\dfrac{-1}{3}\right):\dfrac{81}{128}\)

\(=\dfrac{9}{-8}:\dfrac{81}{128}=\dfrac{9}{-8}.\dfrac{128}{91}=\dfrac{16}{-9}\)

\(b) \)

\(\left(\dfrac{-7}{15}\right).\dfrac{5}{8}.\left(\dfrac{15}{-7}\right).\left(-32\right)\)

\(=\dfrac{-7.5.15}{15.8.-7}.\left(-32\right)\)

\(=\dfrac{5}{8}.\left(-32\right)\)

\(=-20\)

help me

-27.(-28) + (-27).128

= -27.(-28 + 128)

= -27.100

=-2700

thác ai dịch được

The nutrition chat included in the monument
1 coverage of nutrition chat when you are covered
- listen to the song
Do not soak the salmon meat when cutting the meat because the stock and good birth goats are lost
Through picture 3.17em, the potential of the fish meat ingredients should be covered and recorded

8.6.2^7=2^3.2.3.2^7=2^11.3

21.9.49=3.7.3^2.7^2=3^3.3^7

81.3^5.27=3^4.3^5.3^3=3^12

225.3125=3^2.5^2.5^5=3^2.5^7

512.128=2^9.2^7=2^16

30.25.9.4=2.3.5.5^2.3^2.2^2=2^3.3^3.5^3=30^3

81.40.250=3^4.2^3.2.5^3=2^4.3^4.5^4=30^4

Câu a) : 8 . 6 . 2⁷ = 2³. 2 . 3 . 2⁷ = 2^(3+1+7) . 3 = 2¹¹ . 3.

Câu b) : 21 . 9 . 49 = 3.7.3.3.7.7 = (3.3.3) . (7.7.7) = 3³ . 7⁷.

Câu c) : 81 . 3⁵. 27 = 3⁴ . 3⁵ . 3³ = 3¹².

(-27).(-28) + (-27).128

= (-27).(-28 + 128)

= (-27).100

= - 2700

Chúc bạn học tốt 

(- 27) . (- 28) + - (27) . 128

= (- 27) . (- 28 + 128) 

 = (- 27) . 100

= -2700

~Study well~

#KSJ