a,=\(\frac{1}{2}\)

b,-80000

 c,\(\frac{1}{16}\)

d,\(1,271734748x10^{29}\)

kết quả bằng 0

\(-\frac{3}{10}-0,125+\frac{-7}{10}+1,125\)

\(=\left(-\frac{3}{10}-\frac{7}{10}\right)+1,125-0,125\)

\(=-\frac{10}{10}+1=-1+1=0\)

a ) \(\left(-\frac{40}{52}.0,32.\frac{17}{20}\right):\frac{64}{75}\)

= \(\left(-\frac{16}{65}.\frac{17}{20}\right):\frac{64}{75}\)

= \(\left(-\frac{68}{325}\right):\frac{64}{75}\)

= \(\frac{-51}{208}\)

b ) \(-\frac{10}{11}.\frac{8}{9}+\frac{7}{18}.\frac{10}{11}\)

= \(\frac{10}{11}.\left(-\frac{8}{9}+\frac{7}{18}\right)\)

= \(\frac{10}{11}.\left(-\frac{1}{2}\right)\)

= \(\frac{-5}{11}\)

c ) \(\frac{45^{10}.5^{20}}{75^{15}}\)

= \(\frac{5^{10}.3^{20}.5^{20}}{5^{30}.3^{15}}\)

= \(\frac{5^{30}.3^{20}}{5^{30}.3^{15}}\)

= 3 ⁵

= 243

d ) ( - 0,125 ) ³ . 80 ⁴

= -80000

Câu a:

(0,25)\(^3\).32

= (0,25)\(^3\).4\(^2\).2

= (0,25.4)\(^2\).(0,25.2)

= 1\(^2\).0,5

= 0,5

Câu b:

(-0,125)\(^3\).(80)\(^4\)

= (-0,125.80)\(^3\) .(80)

= -10\(^3\).80

= -80000

Ta có: \(A=\frac{\frac{3}{11}+1-\frac{3}{7}}{3+\frac{9}{11}-\frac{9}{7}}-\frac{\frac{1}{3}+0,25-\frac{1}{5}+0,125}{\frac{7}{6}+\frac{7}{8}-0,7+\frac{7}{16}}\)

               \(=\frac{3\left(\frac{1}{11}+\frac{1}{3}-\frac{1}{7}\right)}{9\left(\frac{1}{3}+\frac{1}{11}-\frac{1}{7}\right)}-\frac{2\left(\frac{1}{6}+\frac{1}{8}-\frac{1}{10}+\frac{1}{16}\right)}{7\left(\frac{1}{6}+\frac{1}{8}-\frac{1}{10}+\frac{1}{16}\right)}\)

                 \(=\frac{3}{9}-\frac{2}{7}=\frac{1}{3}-\frac{2}{7}=\frac{7}{21}-\frac{6}{21}=\frac{1}{21}\)

Vậy \(A=\frac{1}{21}\)

\(15\times\frac{1}{4}\times\frac{-5}{7}-25\times\frac{1}{4}\times\frac{-5}{7}\)

\(=\frac{1}{4}\times\frac{-5}{7}\left(15-25\right)\)

\(=\frac{1}{4}\times\frac{-5}{7}\times\left(-10\right)\)

\(=\frac{25}{14}\)

\(15\times\frac{1}{4}\times\frac{-5}{7}-25\times\frac{1}{4}\times\frac{-5}{7}=\frac{1}{4}\times\frac{-5}{7}\left(15-25\right)=\frac{1}{4}\times\frac{-5}{7}\times\left(-10\right)=\frac{25}{14}\)

-(0,125)³.80³.80=-(0,125.80)³.80=-10³.80=-1000.80=-80000