1. a) \(45x-37=53\)

\(45x=90\)

\(x=2\)

vay \(x=2\)

b) \(\frac{x}{9}+500=600\)

\(\frac{x}{9}=100\)

\(\frac{x}{9}=\frac{900}{9}\)

\(\Rightarrow x=900\)

vay \(x=900\)

c) \(576-x=139\)

\(x=576-139\)

\(x=437\)

vay \(x=437\)

d) \(\left(48+x\right)-27=79\)

\(48+x=79+27\)

\(48+x=106\)

\(x=58\)

vay \(x=58\)

2. \(2^5.2^7.2^9=2^{5+7+9}=2^{21}\)

 \(3^9.3^2.3=3^{9+2+1}=3^{12}\)

\(10^9:10^7=10^{10-7}=10^3\)

3). \(2.2.2.2.2.2=2^6\)

\(2.3.2.2.3.3.3=2^3.3^4\)

\(10.9.10.10.10.9.9=10^4.9^3\)

1 a) x= 720

b ) x=chín trăm 

c)x= 437

d)x=58

bài2   a)= 2²¹  b)3¹² c ) =10²  

bài 3 a)=2⁶ b)=2² nhân 3⁴ c )= 10³ nhân chín mũ 3 

a)  \(3\left(4-2x\right)-2\left(x+3\right)=12-7x\)

\(\Leftrightarrow\)\(12-6x-2x-6=12-7x\)

\(\Leftrightarrow\)\(6-8x=12-7x\)

\(\Leftrightarrow\)\(x=-6\)

Vậy...

b)  \(\left|16+\right|3\left(x-2\right)||-5=20\)

\(\Leftrightarrow\)\(\left|16+\right|3\left(x-2\right)||=25\)(1)

Ta thấy:  \(\left|3\left(x-2\right)\right|\ge0\)\(\Rightarrow\)\(16+\left|3\left(x-2\right)\right|>0\)

nên từ (1)   \(\Rightarrow\)  \(16+\left|3\left(x-2\right)\right|=25\)

                   \(\Leftrightarrow\)\(\left|3\left(x-2\right)\right|=9\)

                   \(\Leftrightarrow\)  \(\orbr{\begin{cases}3\left(x-2\right)=9\\3\left(x-2\right)=-9\end{cases}}\)

                  \(\Leftrightarrow\) \(\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)

Vậy....

c)   \(\left|-5-3^2\right|-||3x+5|-7.2^3|=3^9:3^7\)

\(\Leftrightarrow\)\(14-||3x+5|-56|=9\)

\(\Leftrightarrow\)\(||3x+5|-56|=5\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}\left|3x+5\right|-56=5\\\left|3x+5\right|-56=-5\end{cases}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}\left|3x+5\right|=61\\\left|3x+5\right|=51\end{cases}}\)

đến đây bn giải tiếp nhé

\(\Rightarrow36^{15}<6^x<36^{16}\Rightarrow6^{30}<6^x<6^{32}\Rightarrow30

\(4^{15}.9^{15}<2^{^x}.3^x<2^{16}.18^{16}\)

\(\Rightarrow36^{15}<6^x<36^{16}\)

\(\Rightarrow\left(6^2\right)^{15}<6^x<\left(6^2\right)^{16}\)

\(\Rightarrow6^{30}<6^x<6^{32}\)

=> 30<x<32

\(\Rightarrow x=31\)

\(|-1-\frac{-2}{3}|-\left(\frac{7}{-6}-x+\frac{1}{2}\right)=-|-\frac{7}{4}|\)

\(\frac{1}{3}+\frac{7}{6}+x-\frac{1}{2}=-\frac{7}{4}\)

\(\frac{3}{2}+x-\frac{1}{2}=-\frac{7}{4}\)

\(\frac{3}{2}+x=-\frac{5}{4}\)

\(x=-\frac{11}{4}\)

BÀI 1 dễ òi nên k giải nữa nha, chỉ cần ghép các số ( 1;2;3 ) số đầu, liên tiếp dần là đc nha bạn.

Bài 2: 

\(8^4\cdot16^5=\left(2^3\right)^4\cdot\left(2^4\right)^5=2^{12}\cdot2^{20}=2^{32}\)

\(5^{40}\cdot125^7\cdot625^3=5^{40}\cdot\left(5^3\right)^7\cdot\left(5^4\right)^3=5^{40}\cdot5^{21}\cdot5^{12}=5^{73}\)

\(27^4\cdot81^{10}=\left(3^3\right)^4\cdot\left(3^4\right)^{10}=3^{12}\cdot3^{40}=3^{52}\)

\(10^3\cdot100^5\cdot1000^4=10^3\cdot\left(10^2\right)^5\cdot\left(10^3\right)^4=10^3\cdot10^{10}\cdot10^{12}=10^{25}\)

bạn à phải trả lời tất thì mình mới k nha bạn thông cảm