\(\frac{1}{15}\)chứ ko phải \(\frac{1}{5}\)nha các bạn

\(\frac{1}{5}+\frac{9}{10}+\frac{14}{15}-\frac{1}{9}-\frac{20}{10}+\frac{1}{157}\)

\(=\frac{3}{15}+\frac{9}{10}+\frac{14}{15}-\frac{1}{9}-\frac{20}{10}+\frac{1}{157}\)

\(=\left(\frac{3}{15}+\frac{14}{15}\right)+\left(\frac{9}{10}-\frac{20}{10}\right)-\frac{1}{9}+\frac{1}{157}\)

\(=\frac{17}{15}+\frac{-11}{10}-\frac{1}{9}+\frac{1}{157}\)

\(=\left(\frac{51}{45}-\frac{5}{45}\right)+\frac{-11}{10}+\frac{1}{157}\)

\(=\frac{46}{45}+\frac{-11}{10}+\frac{1}{157}\)

\(=\left(\frac{92}{90}+\frac{-99}{90}\right)+\frac{1}{157}\)

\(=\frac{-1099}{14130}+\frac{90}{14130}\)

\(=\frac{-1099}{14130}\)

\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)

<=>  \(-4< x< -0,3\)

p/s: do k biết điều kiện của x nên mk làm đến đó

      chúc bạn học tốt

bạn ấy làm đúng đó bạn

\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}-\frac{x+2}{14}-\frac{x+2}{15}=0\\ \Leftrightarrow\left(x+2\right)\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)=0\\ \Rightarrow x+2=0\Leftrightarrow x=-2\)

(3\(x\) - \(\frac{2}{15}\))\(^3\) = \(\frac{8}{125}\)

(3\(x\) - \(\frac{2}{15}\))\(^3\) = (\(\frac25\))\(^3\)

3\(x\) - \(\frac{2}{15}\) = \(\frac25\)

3\(x\) = \(\frac25\) + \(\frac{2}{15}\)

3\(x\) = \(\frac{6}{15}\) + \(\frac{2}{15}\)

3\(x\) = \(\frac{8}{15}\)

\(x\) = \(\frac{8}{15}\) : 3

\(x\) = \(\frac{8}{15}\) x \(\frac13\)

\(x=\frac{8}{45}\)

Vậy \(x=\frac{8}{45}\)

yutyugubhujyikiu

\(\frac{7^5}{14^2}=\frac{7^5}{7^2.2^2}=\frac{7^3}{2^2}=\frac{343}{4}\)

\(\frac{14^4}{7^3}=\frac{7^4.2^4}{7^3}=7.2^4=7.16=112\)

\(\frac{15^3}{\left(-5\right)^4}=\frac{5^3.3^3}{\left(-5\right)^4}=\frac{3^3}{-5}=\frac{27}{-5}=-\frac{27}{5}\)

 \(\frac{-11}{14}-\frac{-4}{...}=\frac{-3}{14}\)

\(\frac{-11}{14}+\frac{4}{...}=\frac{-3}{14}\)

\(\frac{4}{...}=\frac{-3}{14}-\frac{-11}{14}\)

\(\frac{4}{...}=\frac{-3}{14}+\frac{11}{14}\)

\(\frac{4}{...}=\frac{8}{14}\)

\(\frac{4}{...}=\frac{4}{7}\)

\(\frac{1}{...}-\frac{-2}{15}=\frac{7}{15}\)

\(\frac{1}{...}+\frac{2}{15}=\frac{7}{15}\)

\(\frac{1}{...}=\frac{7}{15}-\frac{2}{15}\)

\(\frac{1}{...}=\frac{5}{15}\)

\(\frac{1}{...}=\frac{1}{3}\)

Hok tốt !!!!!!!!!

2) so sánh

Ta có \(\sqrt{17}\)>\(\sqrt{16}\)=4

            \(\sqrt{26}\)>\(\sqrt{25}\)=5

=> \(\sqrt{17}+\sqrt{26}>\sqrt{16}+\sqrt{25}\)

=>\(\sqrt{17}+\sqrt{26}+1>\sqrt{16}+\sqrt{25}+1\)

=>\(\sqrt{17}+\sqrt{25}+1>5+4+1=10\)

Mà \(\sqrt{99}< \sqrt{100}=10\)

Vậy \(\sqrt{17}+\sqrt{26}+1>\sqrt{99}\)

mk giúp bạn được câu 2 thôi

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