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a. \(\frac{1}{5}=0,2\)
\(\Rightarrow|x|=-0,2\)
b.\(\frac{x+9}{15}=\frac{3}{5}\)
\(\frac{9}{15}=\frac{3}{5}\Rightarrow\frac{x+9}{15}=\frac{9}{5}\)
\(\Rightarrow x=0\)
c. \(|x|=0,75=\frac{3}{4}\)
\(|x|=\frac{3}{4}\)
\(|x|=-0,75\)
d.\(\frac{x}{169}=\frac{10^4}{x}\)
\(\frac{x}{169}=\frac{10000}{x}\)
\(\Rightarrow x=-1300\)
\(\frac{1}{3}x-0,5x=0,75\)
\(\Leftrightarrow-\frac{1}{6}x=0,75\)
\(\Leftrightarrow\)\(x=-\frac{9}{2}\)
1/3x -0.5x = 0.75
(1/3 - 0.5)x = 0.75
-1/6x =0.75
x =0.75 : -1/6
x =-9/2
tk mình nha .thank bạn nhiều:))
1/3 . x - 0,5 . x = 0,75
=> ( 1/3 - 0,5)x = 0,75
=> ( 1/3 -1/2)x =0,75
=> (-1/6)x = 0,75
=> x = 0,75 : (-1/6)
=> x = -9/2
Vậy x = -9/2
Bài 1:
6) 3x + 2³ = 17 + 3²
3x + 8 = 17 + 9
3x + 8 = 26
3x = 26 - 8
3x = 18
x = 18 : 3
x = 6
Vậy x = 6
Bài 2:
3) 145 - (125 + x) = 12
125 + x = 145 - 12
125 + x = 133
x = 133 - 125
x = 8
Vậy x = 8
6) 3³ - (x - 5) = 2²
27 - (x - 5) = 4
x - 5 = 27 - 4
x - 5 = 23
x = 23 + 5
x = 28
Vậy x = 28
9) (x + 7) - 15⁰ = 202 - 19
(x + 7) - 1 = 189
x + 7 = 189 + 1
x + 7 = 190
x = 190 - 7
x - 183
Vậy x = 183
\(a,70-5\times\left(x-3\right)=45\)
\(5\times\left(x-3\right)=70-45\)
\(5\times\left(x-3\right)=25\)
\(x-3=25:5\)
x - 3 = 5
x = 5 + 3 = 8
vậy x = 8
\(b,12+\left(5+x\right)=20\)
12 + 5 + x = 20
17 + x = 20
x = 20 - 17 = 3
vậy x = 3
c, 130 - (100 + x) = 25
130 - 100 - x = 25
30 - x = 25
x = 30 - 25 = 5
vậy x = 5
\(g,10+2\times x=4^5:4^3\)
\(10+2\times x=4^2\)
\(10+2\times x=16\)
\(2\times x=16-10\)
\(2\times x=6\)
x = 6 : 2 = 3
vậy x = 3
h, \(14\times x+54=82\)
\(14\times x=82-54\)
\(14\times x=28\)
\(x=28:14=2\)
vậy x = 2
\(k,15\times x-133=17\)
\(15\times x=17+133\)
\(15\times x=150\)
\(x=150:15=10\)
vậy x = 10
\(a,70-5\times\left(x-3\right)=45\)
\(5\times\left(x-3\right)=70-45\)
\(5\times\left(x-3\right)=25\)
\(x-3=25:5\)
x - 3 = 5
x = 5 + 3 = 8
vậy x = 8
\(b,12+\left(5+x\right)=20\)
12 + 5 + x = 20
17 + x = 20
x = 20 - 17 = 3
vậy x = 3
c, 130 - (100 + x) = 25
130 - 100 - x = 25
30 - x = 25
x = 30 - 25 = 5
vậy x = 5
\(g,10+2\times x=4^5:4^3\)
\(10+2\times x=4^2\)
\(10+2\times x=16\)
\(2\times x=16-10\)
\(2\times x=6\)
x = 6 : 2 = 3
vậy x = 3
h, \(14\times x+54=82\)
\(14\times x=82-54\)
\(14\times x=28\)
\(x=28:14=2\)
vậy x = 2
\(k,15\times x-133=17\)
\(15\times x=17+133\)
\(15\times x=150\)
\(x=150:15=10\)
vậy x = 10
\(a.97-7\left(x-8\right)=3\cdot2^4\)
\(97-7\left(x-8\right)=48\)
\(7\left(x-8\right)=97-48\)
\(7\left(x-8\right)=49\)
\(x-8=49:7=7\)
\(x=7+8=15\)
\(b.5x^2-74=51\)
\(5x^2=51+74=125\)
\(x^2=125:5=25\)
\(\Rightarrow x=\pm5\)
\(c.3x+2-3x=216\)
\(0x=214\)
⇒ \(x\in\) rỗng
\(5\left(3x-4\right)^3=40\)
\(\left(3x-4\right)^3=40:5=8\)
⇒ 3x - 4 = 2
⇒ 3x = 2 + 4 = 6
⇒ x = 6 : 3 = 2
a.97−7(x−8)=3⋅24
\(97 - 7 \left(\right. x - 8 \left.\right) = 48\)
\(7 \left(\right. x - 8 \left.\right) = 97 - 48\)
\(7 \left(\right. x - 8 \left.\right) = 49\)
\(x - 8 = 49 : 7 = 7\)
\(x = 7 + 8 = 15\)
\(b . 5 x^{2} - 74 = 51\)
\(5 x^{2} = 51 + 74 = 125\)
\(x^{2} = 125 : 5 = 25\)
\(\Rightarrow x = \pm 5\)
\(c . 3 x + 2 - 3 x = 216\)
\(0 x = 214\)
⇒ \(x \in\) rỗng
\(5 \left(\left(\right. 3 x - 4 \left.\right)\right)^{3} = 40\)
\(\left(\left(\right. 3 x - 4 \left.\right)\right)^{3} = 40 : 5 = 8\)
⇒ 3x - 4 = 2
⇒ 3x = 2 + 4 = 6
⇒ x = 6 : 3 = 2
\(\frac53.x-0,15=x+0.75\)
\(\frac53.x-x=0,75+0,15\)
\(\left(\frac53-1\right)x=0,90\)
\(\frac23x=0,90\)
\(x=\frac{90}{100}.\frac32\)
\(x=\frac{270}{200}\)
\(x=\frac{27}{20}\)
Bạn ơi, cho mình hỏi dấu chấm là phẩy hay nhân vậy ạ?