Tính bth đc mà???

=(-40/51. 32/100. 17/20):64/75

=(-16/75):64/75

=(-16/75).75/64

=(-16/64)=(-1/4)

Bước 1: Bỏ ngoặc

\(= \frac{38}{5} + \frac{9}{5} - \frac{8}{5} - \frac{5}{4} - \frac{6}{7}\)

Bước 2: Thu gọn trong cùng mẫu

• \(\frac{38}{5} + \frac{9}{5} - \frac{8}{5} = \frac{38 + 9 - 8}{5} = \frac{39}{5}\)

Vậy:

\(= \frac{39}{5} - \frac{5}{4} - \frac{6}{7}\)

Bước 3: Quy đồng mẫu (5, 4, 7) → mẫu chung là 140

\(\frac{39}{5} = \frac{39 \times 28}{140} = \frac{1092}{140}\) \(\frac{5}{4} = \frac{5 \times 35}{140} = \frac{175}{140}\) \(\frac{6}{7} = \frac{6 \times 20}{140} = \frac{120}{140}\)

Bước 4: Tính

\(\frac{1092}{140} - \frac{175}{140} - \frac{120}{140} = \frac{1092 - 175 - 120}{140} = \frac{797}{140}\)

=>Kết quả cuối cùng: \(\frac{797}{140}\)

\(\)

ジェット

`a)( -5/7)+7,45+12/7-2,45`

`=(-5/7 +12/7)+(7,45-2,45)`

`=1+5=6`

`b)7/12* (-2,34)- 7/12 * (-0,34)`

`=7/12 *[(-2,34)+0,34]`

`=7/12 *(-2)`

`=-7/6`

`c)0,75 *6/13+3/4 *7/13-2,75`

`=3/4*6/13+3/4 *7/13-2,75`

`=3/4*(6/13+7/13)-2,75`

`=3/4*1-11/4`

`=3/4-11/4`

`=(3-11)/4`

`=(-8)/4=-2`

kết quả bằng 0

\(-\frac{3}{10}-0,125+\frac{-7}{10}+1,125\)

\(=\left(-\frac{3}{10}-\frac{7}{10}\right)+1,125-0,125\)

\(=-\frac{10}{10}+1=-1+1=0\)

a: \(=\dfrac{5}{3}-\dfrac{2}{7}+\dfrac{6}{5}=\dfrac{175}{105}-\dfrac{30}{105}+\dfrac{126}{105}=\dfrac{271}{105}\)

b: \(=\dfrac{-16}{36}+\dfrac{-30}{36}-\dfrac{153}{36}=\dfrac{-199}{36}\)

(1/3 + 12/67 + 13/41) - (79/67 - 28/41)

= 1/3 + 12/67 + 13/41 - 79/67 + 28/41

= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)

= 1/3 + (-1) + 1

= 1/3

(1/3 + 12/67 + 13/41) - (79/67 - 28/41)

= 1/3 + 12/67 + 13/41 - 79/67 + 28/41

= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)

= 1/3 + (-1) + 1

= 1/3.

CHÚC BẠN HỌC TỐT!!! ^^

Đề sai chắc lun.

\(\frac{54.107-53}{53.107-54}=\frac{\left(53+1\right).107-53}{53.107-54}=\frac{53.107+107-53}{53.107-54}=\frac{53.107+54}{53.107-54}=1-1=0\)