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a) \(\frac{-77}{143}+\frac{65}{143}-\frac{66}{143}+\frac{7}{22}\)
= \(\frac{-78}{143}+\frac{7}{22}\)= \(\frac{-6}{11}+\frac{7}{22}\)= \(\frac{-12}{22}+\frac{7}{22}\)
= \(\frac{-5}{22}\)
b) \(\frac{-4}{5}-\frac{20}{170}+\frac{51}{170}+\frac{150}{170}\)= \(\frac{-4}{5}-\frac{221}{170}\)
\(\frac{-4}{5}-\frac{13}{10}\)= \(\frac{-8}{10}-\frac{13}{10}\)=\(\frac{-21}{10}\)
c )
\(1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{3}{2}}}}=1+\frac{1}{1+\frac{1}{1+\frac{5}{3}}}=1+\frac{1}{1+\frac{1}{\frac{8}{3}}}=1+\frac{1}{\frac{11}{8}}=\frac{19}{11}\)
1) \(\frac{a}{b}=\frac{c}{d}=\frac{a+c}{b+d}=\frac{a-c}{b-d}\)
2)\(\frac{a-c}{b-d}=\frac{a+c}{b+d}\Rightarrow\frac{a-c}{a+c}=\frac{b-d}{b+d}\)
3) \(\frac{a}{b}=\frac{c}{d}=\frac{a+c}{b+d}\Rightarrow\frac{a}{a+c}=\frac{b}{b+d}\)
4)\(\frac{a}{b}=\frac{c}{d}=\frac{a-c}{b-d}\Rightarrow\frac{a}{a-c}=\frac{b}{b-d}\)
5)\(\frac{a}{b}=\frac{c}{d}=\frac{a+c}{b+d}\Rightarrow\frac{c}{a+c}=\frac{d}{b+d}\)
6)\(\frac{a}{b}=\frac{c}{d}=\frac{a-c}{b-d}\Rightarrow\frac{c}{a-c}=\frac{d}{b-d}\)
1) \(ℕ\subsetℤ\subsetℚ\)
\(\frac{-3}{5}\)có thuộc Z
2) \(\frac{x-3}{15}\)= \(\frac{-7}{5}\)
(x-3).5 = 15.(-7)
(x-3).5 = -105
x-3 = -105:5
x-3 = -21
x = -21+3
x= -18
CHÚC BẠN HỌC TỐT
1. \(\left(\frac{1}{2}\right)^n=\frac{1}{32}\)
\(\left(\frac{1}{2}\right)^n=\frac{1^5}{2^5}\)
\(\left(\frac{1}{2}\right)^n=\left(\frac{1}{2}\right)^5\)
Vậy \(n=5\)
2. \(\frac{343}{125}=\left(\frac{7}{5}\right)^n\)
\(\frac{7^3}{5^3}=\left(\frac{7}{5}\right)^n\)
\(\left(\frac{7}{5}\right)^3=\left(\frac{7}{5}\right)^n\)
Vậy \(n=3\)
3. \(\frac{16}{2^n}=2\)
\(2^n=\frac{16}{2}\)
\(2^n=8=2^3\)
Vậy \(n=3\)
1. (1/2)2 = 1/32 <=> (21)n = (25)n <=> 1.n = 5.1 <=> n = 5
=> n = 5
2) 343/125 = (7/5)n <=> (7/5)3 = (7/5)n <=> 3 = n
=> n = 3
3) 16/2n = 2 <=> 16.2n <=> 2n = 2/16 <=> 2n = 1/8 <=> 2n = 8 <=> 2n = 23 <=> n = 3
=> n = 3
Số thập phân hữu hạn là \(\frac{17}{10};\frac{15}{8};\frac{13}{20}\)
Số thập phân vô hạn tuần hoàn là: \(\frac{9}{22};\frac{17}{15};\frac{19}{6}\)
hay ☺