a)(x.0,25+1999)x2000=(53+1999)x2000

(x.0,25+1999)=53+1999

x.0,25=53

x=53x4

x=210

a)(x.0,25+1999)x2000=(53+1999)x2000

(x.0,25+1999)=53+1999

x.0,25=53

x=53x4

x=210

k mik đi

\(A=\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+...+\frac{2}{399}\)

=>\(A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{19.21}\)

=>\(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\)

=>\(A=\frac{1}{3}-\frac{1}{21}\)

=>\(A=\frac{2}{7}\)

\(71+65\cdot4=\frac{x+140}{x}+260\)

\(71+260=\frac{x+140}{x}+260\)

\(71=\frac{x}{x}+\frac{140}{x}\)

\(71=1+\frac{140}{x}\)

\(71-1=\frac{140}{x}\)

\(70=\frac{140}{x};\Rightarrow x=2\)

\(71+65\times4=\frac{x+140}{x}+260\)

\(71+260=\frac{x+140}{x}+260\)

\(71=\frac{x+140}{x}\)

\(\Rightarrow71x=x+140\)

\(\Rightarrow71x-x=140\)

\(\Rightarrow70x=140\)

\(\Rightarrow x=2\)

bài này dễ lắm , cô mik vừa chữa bài này rùi

b1:bạn rút gọn các phân số trên cho 2 rùi có tử là 5 , sau đó thì  dễ

\(\frac{1}{2.4}+\frac{1}{4.6}+...+\frac{1}{98.100}\)

\(=\frac{1}{2}\left(\frac{2}{2.4}+\frac{2}{4.6}+...+\frac{2}{98.100}\right)\)

\(=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{98}-\frac{1}{100}\right)\)

\(=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{100}\right)=\frac{1}{2}.\frac{49}{100}=\frac{49}{200}\)

\(\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+...+\frac{10}{1400}=\frac{5}{3}\left(\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+...+\frac{3}{700}\right)\)

\(=\frac{5}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{25.28}\right)=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{28}\right)=\frac{5}{3}.\frac{3}{14}=\frac{5}{14}\)

thanks

a) 3/x-7 = 27/135

3/x-7 = 3/15

x - 7 = 15

x = 15 + 7

x = 22

a) \(\frac{3}{x-7}=\frac{27}{135}\)

\(\Rightarrow\)\(\left(x-7\right).27=3.135\)

\(\Rightarrow\)\(\left(x-7\right).27=405\)

\(\Rightarrow\)\(x-7=15\)

\(\Rightarrow\)\(x=22\)

Vậy \(x=22\)

b ) \(71+65.4=\frac{x+140}{x}+260\)

\(71+260=\frac{x+140}{x}+260\)

\(331=\frac{x+140}{x}+260\)

\(331-260=\frac{x+140}{x}\)

\(71=\frac{x+140}{x}\)

\(71=\frac{x}{x}+\frac{140}{x}\)

\(71=1+\frac{140}{x}\)

\(70=\frac{140}{x}\)

\(x=140\div70\)

\(x=20\)

Vậy \(x=20\)

#TQY

Ta có: 75%.x + \(\frac{1}{5}\).x = \(\frac{1}{6}\)

          \(\frac{3}{4}\cdot x+\frac{1}{5}\cdot x=\frac{1}{6}\)

           \(x\left(\frac{3}{4}+\frac{1}{5}\right)=\frac{1}{6}\)

           \(\frac{19}{20}x=\frac{1}{6}\) 

            \(x=\frac{1}{6}:\frac{19}{20}=\frac{10}{57}\)

tích nha

75%.x+1/5.x=1/6                                             3/4.x+1/5.x=1/6                                               x.(3/4+1/5)=1/6                  :                                        x.19/20=1/6 suy ra x=1/6:19/20=1/6.20/19=10/57