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a) \(\frac{59}{42}\)
b) \(\frac{17}{36}\)
c) \(\frac{5}{51}\)
d) \(\frac{4}{7}\)
a: \(\frac56+\frac47=\frac{35}{42}+\frac{24}{42}=\frac{35+24}{42}=\frac{59}{42}\)
b: \(\frac54-\frac79=\frac{45}{36}-\frac{28}{36}=\frac{45-28}{36}=\frac{17}{36}\)
c: \(\frac{15}{17}\times\frac19=\frac{15\times1}{17\times9}=\frac{15}{153}=\frac{5}{51}\)
d: \(\frac37:\frac68=\frac37:\frac34=\frac37\times\frac43=\frac47\)
\(\frac{11}{9}-\frac67\)
\(=\frac{77}{63}-\frac{54}{63}=\frac{77-54}{63}=\frac{23}{63}\)
\(\frac{7}{10}-\frac25=\frac{7}{10}-\frac{4}{10}=\frac{7-4}{10}=\frac{3}{10}\)
\(\frac72-2=\frac72-\frac42=\frac{7-4}{2}=\frac32\)
\(\frac65\times\frac38=\frac{6\times3}{5\times8}=\frac{18}{40}=\frac{9}{20}\)
\(\frac25:\frac32=\frac25\times\frac23=\frac{2\times2}{5\times3}=\frac{4}{15}\)
\(5:\frac57=5\times\frac75=7\)
\(\frac73:4=\frac{7}{3\times4}=\frac{7}{12}\)
911−76
\(= \frac{77}{63} - \frac{54}{63} = \frac{77 - 54}{63} = \frac{23}{63}\)
\(\frac{7}{10} - \frac{2}{5} = \frac{7}{10} - \frac{4}{10} = \frac{7 - 4}{10} = \frac{3}{10}\)
\(\frac{7}{2} - 2 = \frac{7}{2} - \frac{4}{2} = \frac{7 - 4}{2} = \frac{3}{2}\)
\(\frac{6}{5} \times \frac{3}{8} = \frac{6 \times 3}{5 \times 8} = \frac{18}{40} = \frac{9}{20}\)
\(\frac{2}{5} : \frac{3}{2} = \frac{2}{5} \times \frac{2}{3} = \frac{2 \times 2}{5 \times 3} = \frac{4}{15}\)
\(5 : \frac{5}{7} = 5 \times \frac{7}{5} = 7\)
\(\frac{7}{3} : 4 = \frac{7}{3 \times 4} = \frac{7}{12}\)
tính phân số
a)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
b)\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
\(=\frac{83}{30}+\frac{-13}{9}=1\frac{29}{90}\)
\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{13}{6}-\frac{16}{9}\)
\(=\frac{7}{18}\)
Đây là chj tính nhẩm, còn em muốn giải chi tiết thì quy đồng lên để giải nha.
\(a,\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
\(=\frac{83}{30}+\frac{5}{9}-2\)
\(=\frac{299}{90}-2\)
\(=\frac{119}{90}\)
\(b,3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{13}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{31}{18}+\frac{32}{24}\)
\(=\frac{55}{18}\)
tính phân số
a)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
b)\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(\left(a\right)=\frac{119}{90}\)
\(\left(b\right)=55,18\)
Mình lười tính, k nha
bài 6 \(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+\ldots+\frac{2}{80\times82}+\frac{2}{82\times84}\)
= \(\frac12-\frac14+\frac14-\frac16+\frac16-\cdots+\frac{1}{80}-\frac{1}{82}+\frac{1}{82}-\frac{1}{84}\)
= \(\frac12-\left(\frac14-\frac14\right)-\left(\frac16-\frac16\right)-\cdots-\left(\frac{1}{82}-\frac{1}{82}\right)-\frac{1}{84}\)
=\(\frac12-0-0-\frac{1}{84}\)
=\(\frac12\) - \(\frac{1}{84}\)
=\(\frac{42}{84}-\frac{1}{84}\)
=\(\frac{41}{84}\)
Bài 7
a)\(\frac{19}{4}=4\frac34\)
b)\(\frac{27}{5}=5\frac25\)
c)\(\frac{56}{8}=7\frac08\)
a) \(\frac{5}{6}< \frac{6}{7}\)
b) \(\frac{5}{8}=\frac{50}{80}\)
c) \(\frac{3}{4}>\frac{5}{7}\)
d) \(\frac{9}{7}< \frac{8}{5}\)
\(\frac{6}{8}+\frac{4}{8}=\frac{6+4}{8}=\frac{10}{8}=\frac{5}{4}\)
\(\frac{5}{7}-\frac{1}{7}=\frac{5-1}{7}=\frac{4}{7}\)
\(\frac{9}{6}+\frac{4}{8}=\frac{9\times3}{6\times3}+\frac{4\times2}{8\times2}=\frac{27}{19}+\frac{8}{19}=\frac{35}{19}\)
\(\frac{5}{7}-\frac{4}{6}=\frac{5\times6}{7\times6}-\frac{4\times7}{6\times7}=\frac{30}{42}-\frac{28}{42}=\frac{2}{42}=\frac{1}{21}\)
\(\frac{6}{8}+\frac{4}{8}=\frac{6+4}{8}=\frac{10}{8}=\frac{5}{4}\)
\(\dfrac56+\dfrac98\)
\(=\dfrac{20}{24}+\dfrac{27}{24}\)
\(=\dfrac{20+27}{24}\)
\(=\dfrac{47}{24}=1\dfrac{23}{24}\)
\(\frac56+\frac98\)
= \(\frac{40+72}{48}\)
= \(\frac{40}{48}+\frac{72}{48}\)
= \(\frac{112}{48}\)
= \(\frac73\)
Cảm ơn nha