\(\frac{1}{11}+\frac{2}{11}+\frac{3}{11}+\frac{4}{11}+\frac{5}{11}+\frac{6}{11}+\frac{7}{11}+\frac{8}{11}+\frac{9}{11}+\frac{10}{11}\)

\(=\frac{1+2+3+4+5+6+7+8+9+10}{11}\)

\(=\frac{\left(1+10\right)+\left(2+9\right)+\left(3+8\right)+\left(4+7\right)+\left(5+6\right)}{11}\)

\(=\frac{11+11+11+11+11}{11}\)

\(=\frac{11\cdot5}{11}=5\)

\(= \frac{1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10}{11}\)

\(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55\)

Vậy là bằng 55/11 nhé bạn

\(a.\frac{4}{3}-\frac{3}{2}:X=\frac{1}{6}\)

           \(\frac{3}{2}:X=\frac{4}{3}-\frac{1}{6}\)

           \(\frac{3}{2}:X=\frac{8}{6}-\frac{1}{6}\)

           \(\frac{3}{2}:X=\frac{7}{6}\)

               \(X=\frac{3}{2}:\frac{7}{6}\)

              \(X=\frac{3}{2}\times\frac{6}{7}\)

              \(X=\frac{9}{7}\)

\(b.\left(X+\frac{2}{3}\right):\frac{1}{3}=\frac{41}{3}\)

    \(X-\frac{2}{3}=\frac{41}{3}.\frac{1}{3}\)

   \(X-\frac{2}{3}=\frac{41}{9}\)

  \(X=\frac{41}{9}+\frac{2}{3}\)

  \(X=\frac{41}{9}+\frac{6}{9}\)

 \(X=\frac{47}{9}\)

bài 1:

\(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}\)

\(=\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}\)

\(=\frac{11}{11}+\frac{1}{3}=1+\frac{1}{3}=\frac{3}{3}+\frac{1}{3}=\frac{4}{3}\)

bài 2:

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\)

\(=\left(\frac{1}{2}+\frac{1}{20}\right)+\left(\frac{1}{6}+\frac{1}{12}\right)\)

\(=\frac{11}{20}+\frac{1}{4}=\frac{11}{20}+\frac{5}{20}=\frac{15}{20}=\frac{3}{4}\)

bài 3: 

a) \(\frac{3}{2}\cdot\frac{4}{5}\cdot\frac{2}{3}=\left(\frac{3}{2}\cdot\frac{2}{3}\right)\cdot\frac{4}{5}=1\cdot\frac{4}{5}=\frac{4}{5}\)

b) \(\frac{6}{7}\cdot\frac{5}{3}\cdot\frac{7}{6}=\left(\frac{6}{7}\cdot\frac{7}{6}\right)\cdot\frac{5}{3}=1\cdot\frac{5}{3}=\frac{5}{3}\)

bài 4: 

a) \(\frac{2}{5}\cdot\frac{1}{4}+\frac{3}{4}\cdot\frac{2}{5}=\frac{2}{5}\cdot\left(\frac{1}{4}+\frac{3}{4}\right)=\frac{2}{5}\cdot1=\frac{2}{5}\)

b) \(\frac{6}{11}:\frac{2}{3}+\frac{5}{11}:\frac{2}{3}=\left(\frac{6}{11}+\frac{5}{11}\right):\frac{2}{3}=1:\frac{2}{3}=\frac{3}{2}\)

Bài 1: 

  6/11 + 1/3 + 5/11 

= ( 6/11 + 5/11) + 1/3

= 11/11 + 1/3

= 1 + 1/3 

= 3/3 +1/3  

= 4/3 

Bài 2: 

1/2 + 1/6 + 1/12 + 1/20 

= ( 1/2 + 1/6 + 1/12 ) + 1/20 

= ( 6/12 + 2/12 + 1/12 ) + 1/20 

=9/12 + 1/20 

= 3/4 +1/20  

= 15/20 + 1/20 

= 16/20 = 4/5

 Bài 3:

a) \(\frac{3}{2}\times\frac{4}{5}\times\frac{2}{3}\) \(=\left(\frac{3}{2}\times\frac{2}{3}\right)\times\frac{4}{5}\)\(=1\times\frac{4}{5}=\frac{4}{5}\) 

b)  \(\frac{6}{7}\times\left(\frac{5}{3}\times\frac{7}{6}\right)\) \(=\frac{6}{7}\times\frac{35}{18}\)\(=\frac{1\times5}{7\times3}=\frac{5}{21}\)   

Bài 4:

a) 2/5  x 1/4 + 3/4 x 2/5 

= 2/5 x ( 1/4  + 3/4) 

 = 2/5 x  1 

= 2/5

 b) 6/11 : 2/3 +5/11 : 2/3 

=  ( 6/11 + 5/11) x 3/2 

= 11/11 x 3/2  

= 1 x 3/2  

=  3/2  

....  

Câu a: \(\frac{54}{63}\) và \(\frac{28}{63}\)

Câu b: \(\frac{55}{88}\)và \(\frac{24}{88}\)

a) \(\frac{6}{7}=\frac{6.9}{7.9}=\frac{54}{63}\)

\(\frac{4}{9}=\frac{4.7}{9.7}=\frac{28}{63}\)

b) \(\frac{5}{8}=\frac{5.11}{8.11}=\frac{55}{88}\)

\(\frac{3}{11}=\frac{3.8}{11.8}=\frac{24}{88}\)

c) \(\frac{6}{7}=\frac{6.3}{3.7}=\frac{18}{21}\)

\(\frac{5}{21}=\frac{5}{21}\)

d) \(\frac{7}{21}=\frac{7.4}{21.4}=\frac{28}{84}\)

477 851

\(1+1+9+6+7+4+6+2+3+3+434343+43455+11=477851\)

12/32

Phân số \(\frac{12}{32}\)bé nhất. Vì rút gọn phân số đó cho 2 sẽ có tử bằng 6. Sau đó ta so sánh

\(a.\left(\frac{6}{11}+\frac{5}{11}\right).\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}b.\frac{3}{5}\cdot\frac{7}{9}+\frac{3}{5}\cdot\frac{2}{9}=\frac{3}{5}\cdot\left(\frac{7}{9}+\frac{2}{9}\right)=\frac{3}{5}\cdot1=\frac{3}{5}\)

\(\frac{11}{3}-\frac{5}{6}+\frac{4}{3}+6-\frac{7}{6}\)

\(=\left(\frac{11}{3}+\frac{4}{3}\right)-\left(\frac{5}{6}+\frac{7}{6}\right)+\frac{4}{3}+6\)

\(=5-2+6+\frac{4}{3}\)

\(=9+\frac{4}{3}=9\frac{4}{3}\)

\(\frac{11}{3}-\frac{5}{6}+\frac{4}{3}+6-\frac{7}{6}\)

\(=\left(\frac{11}{3}+\frac{4}{3}\right)-\left(\frac{5}{6}+\frac{7}{6}\right)+\frac{4}{3}+6\)

\(=5-2+6+\frac{4}{3}\)

\(=9+\frac{4}{3}=9\frac{4}{3}\)

\(=\frac{27}{3}+\frac{4}{3}=\frac{31}{3}\)