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\(\left(\frac{2}{3}+x\right)\left(\frac{1}{5}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}+x=0\\\frac{1}{5}-2x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{2}{3}\\-2x=-\frac{1}{5}\end{cases}\Leftrightarrow}}\orbr{\begin{cases}x=-\frac{2}{3}\\x=\frac{1}{10}\end{cases}}\)
Vậy:.......
#H
Xin lỗi bạn mình k làm đầy đủ đc ạ :
2) a) Vì (x-3)(2y+1) = 7
=> x-3 và 2y + 1 \(\in\)Ư(7) = { 1;7}
Ta có bảng :
| x-3 | 1 | 7 |
| x | 4 | 10 |
| 2y+1 | 7 | 1 |
| y | 3 | 0 |
Vậy...
b) (2x+1)(3y-2) = -55
=> 2x +1 và 3y - 2 \(\in\)Ư(-55) = { 1; 5 ; 11 ; 55}
Ta có bảng :
| 2x+1 | 1 | 55 | 5 | 11 | |||
| x | 0 | 27 | 2 | 5 | |||
| 3y-2 | 55 | 1 | 11 | 5 | |||
| y | 19 | 1 | ktm | ktm |
Sr kẻ bảng thừa cột :))
Vậy...
a) \(xy+2x+y+11=0\)
\(\Leftrightarrow x\left(y+2\right)+\left(y+2\right)+9=0\)
\(\Leftrightarrow\left(x+1\right)\left(y+2\right)=0-9\)
\(\Leftrightarrow\left(x+1\right)\left(y+2\right)=-9\)\(=-1.9=-3.3=-9.1\)
\(\Rightarrow\left[{}\begin{matrix}x+1=-1;y+2=9\\x+1=-3;y+2=3\\x+1=-9;y+2=1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-2;y=7\\x=-4;y=1\\x=-10;y=-1\end{matrix}\right.\)
Vậy:.............
1.a) x = 0
b) x = 1 , y = 2
c) x = 9
2.x = 6
mik ko bik có đúng ko nhưng dù sao cx chúc b học tốt nhé ^^
a) \(\frac{-5}{9}+\frac{5}{9}:\left(1\frac{2}{3}-2\frac{1}{12}\right)\)
\(=\frac{-5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)
\(=\frac{-5}{9}+\frac{5}{9}:\frac{\left(-5\right)}{12}\)
\(=\frac{-5}{9}+\frac{5}{9}.\frac{12}{\left(-5\right)}\)
\(=\frac{-5}{9}.\left(1+\frac{12}{5}\right)\)
\(=\frac{-5}{9}.\frac{17}{5}\)
\(=\frac{-17}{9}\)
b) \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)
\(=\frac{-7}{25}-\frac{18}{25}\)
\(=-1\)
Chúc bn học tốt !!!
\(\left(3x-1\right)\left(\frac{-1}{2}x+5\right)=0\)
\(\orbr{\begin{cases}3x-1=0\\\frac{-1}{2}x+5=0\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{1}{3}\\x=10\end{cases}}\)
\(\frac{1}{4}+\frac{1}{3}:(2x-1)=-5\)
\(\Rightarrow\frac{1}{3}:(2x-1)=-5-\frac{1}{4}\)
\(\Rightarrow\frac{1}{3}:(2x-1)=\frac{-21}{4}\)
\(\Rightarrow2x-1=\frac{1}{3}:-\frac{21}{4}\)
\(\Rightarrow2x-1=\frac{1}{3}\cdot-\frac{4}{21}\)
\(\Rightarrow2x-1=\frac{-4}{63}\)
\(\Rightarrow2x=-\frac{4}{63}+1\)
\(\Rightarrow2x=\frac{59}{63}\Leftrightarrow x=\frac{59}{126}\)
\(\left(x+\frac{1}{2}\right)\cdot\left(\frac{2}{3}-2x\right)=0\)
TH1 : \(\Rightarrow x+\frac{1}{2}=0\)
\(x=0-\frac{1}{2}\)
\(x=\frac{-1}{2}\)
TH2 : \(\Rightarrow\frac{2}{3}-2x=0\)
\(2x=0+\frac{2}{3}=\frac{2}{3}\)
\(x=\frac{2}{3}\div2=\frac{1}{3}\)
\(\Rightarrow x=\frac{-1}{2};\frac{1}{3}\)
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)
\(x=\frac{3}{5}^2-\frac{1}{5}^2\)
\(x=\frac{2}{5}\)
(x-10) . 11 = 22
x - 10 = 22 : 11
x - 10 = 2
=> x = 12
b, 2x + 15 = (-27)
2x = (-27)- 15
2x = - 42
=> x = -21
c , tự làm
a) ( x - 10 ) . 11 = 22
x - 10 = 22 : 11
x - 10 = 2
x = 2 + 10
x = 12
Vậy x = 12
b) 2x + 15 = - 27
2x = - 27 - 15
2x = - 42
x = - 42 : 2
x = - 21
Vậy x=-21
c) - 765 - ( 305 + x ) = 100
305 + x = - 765 - 100
305 + x = - 865
x = - 865 - 305
x = - 1170
Vậy x=-1170
d)2x:4=16
2x:22=24
2x-2=24
=> x-2=4
x=4+2
x=6
Vậy x=6
f) ( 17x - 25 ) : 8 + 65 = 92
( 17x - 25 ) : 8 + 65 = 81
( 17x - 25 ) : 8 = 81 - 65
( 17x - 25 ) : 8 = 16
17x - 25 = 16 . 8
17x - 25 = 128
17x = 128 + 25
17x = 153
x = 153 : 17
x = 9
Vậy x=9
\(\frac{1}{25}\left(2x-\frac{1}{11}\right)^2=0\)
\(\Rightarrow\left(2x-\frac{1}{11}\right)^2=0\)
\(\Rightarrow2x-\frac{1}{11}=0\)
\(2x=-\frac{1}{11}\)
\(x=-\frac{1}{11}:2\)
\(x=-\frac{1}{22}\)
1/25( 2x - 1/11 )^2 = 0
( 2x - 1/11 )^2 = 0 : 1/25
( 2x - 1/11 )^2 = 0
2x -1/11 = 0
2x = 0 + 1/11
2x = 1/11
x =1/11 : 2
x = 1/22
1/25 (2x-1/11)^2=0
(2x-1/11)^2=0: 1/25=25
(2x-1/11)^2=5^2
TH1
2x-1/11=5
2x=5+ 1/11
2x=56/11
x=56/11 :2
x=56/11. 1/2
x=28/11
TH2
2x-1/11=(-5)
2x=-5+ 1/11
2x=-54/11
x=-54/11: 2
x=-54/11. 1/2
x=-27/11
Vậy x thuộc cả 2 trường hợp trên
Ta có: \(\dfrac{1}{25}\cdot\left(2x-\dfrac{1}{11}\right)^2=0\)
=>\(\left(2x-\dfrac{1}{11}\right)^2=0\)
=>\(2x-\dfrac{1}{11}=0\)
=>\(2x=\dfrac{1}{11}\)
=>\(x=\dfrac{1}{11}:2=\dfrac{1}{22}\)
1/25(2x-1/11)^2=0
(2x-1/11)^2=0
2x-1/11=0
2x=1/11
x= 1/11:2
x=2/22
1/22